60%.x+0,4.x+x:3=4
Tìm x
60%+x+0,4+x+x:3=2
60%+x+0,4+x+x:3=2
3/5+x+2/5+x+x.1/3=2
(3/5+2/5)+x.(1+1+1/3)=2
1+x.10/3=2
suy ra x.10/3=1
x=1:10/3
x=3/10
vậy x=3/10 nha
60%.x+0,4.x+x:3=2
60%.x+0,4.x+x:3=2
\(\frac{3}{5}\).x+\(\frac{2}{5}\).x+x:3=2
x.(\(\frac{3}{5}\)+\(\frac{2}{5}\))+x:3=2
x.1+x.\(\frac{1}{3}\)=2
x.(1+\(\frac{1}{3}\))=2
x.\(\frac{4}{3}\)=2
x=2:\(\frac{4}{3}\)
x=\(\frac{3}{2}\)
Bài 2 . Tìm x, nếu biết : \(\text{60% x + 0,4 x + x : 3 = 2}\)
\(60\%x+0,4x+x:3=2\\ \Leftrightarrow\left(60\%+0,4+\dfrac{1}{3}\right)x=2\\ \Rightarrow\dfrac{4}{3}x=2\\ \Rightarrow x=\dfrac{3}{2}\)
\(60\%x+0,4x+x:3=2\)
\(x.\left(60\%+0,4+\dfrac{1}{3}\right)=2\)
\(x.\dfrac{4}{3}=2\)
\(x=2:\dfrac{4}{3}\)
\(x=\dfrac{3}{2}\)
60%× x +0,4 × x +x ÷3=2
Tìm x nhé
\(60\%\cdot x+0,4\cdot x+x:3=2\)
\(x\cdot\left(60\%+0,4+\frac{1}{3}\right)=2\)
\(x\cdot\frac{4}{3}=2\)
\(x=2:\frac{4}{3}=\frac{3}{2}\)
Bài 1 :So sánh
A= 2^19 .27^3+15.4^9.9^4/6^9.2^10+12^10 va B = 4/35+4/63+4/99+4/143+4/195
Bài 2 : tìm x biết :
60%.x+0,4.x +x:3=2
BÀI 2
60%.x + 0,4.x + x:3= 2
\(\frac{60}{100}\)x + \(\frac{4}{10}\).x + x. \(\frac{1}{3}\)=2
\(\frac{3}{5}\).x + \(\frac{2}{5}\).x + x.\(\frac{1}{3}\)=2
(\(\frac{3}{5}\)+ \(\frac{2}{5}\)+ \(\frac{1}{3}\)) .x =2
\(\frac{4}{3}\).x =2
x = 2: \(\frac{4}{3}\)
x = \(\frac{3}{2}\)
Vậy x=\(\frac{3}{2}\)
k cho mik nha các bạn
Bài 2 :
60%x + 0.4x + x : 3 = 2
\(x.\left(\frac{60}{100}+\frac{2}{5}+\frac{1}{3}\right)\)= 2
\(x.\frac{4}{3}\)= 2
\(x=2.\frac{3}{4}\)
\(x=1.5\)
Tìm x, biết:
a) (3-2x).(x-5)=0
b) 60%.x+0,4.x-2-x:3
(dấu . là dấu nhân nhé)
y x 60% + 0,4 x y = 2,5
19.Giá trị của x thỏa mãn "60% . x + 0,4 . x + x : 3 = 2 "
A.5,1 B.5 C.1,5 D.1,05
25. Giá trị x thỏa mãn " 1,2 . x + 2/3 . x = -0,448 "
A.-0,24 B.-2,4 C.-4,2 D.-2,04
dang 2
1/_6,4x+(-2,4)x=1,2
2/_2.3/4:x3.1/7:0,01
3/_3/4+1/4:x=1
4/_(x-2/3)(x+1/4)=0
5/_|x+4/5|=0
6/_|x+3/4|-3/4=0
7/_1,6-|x-0,4|=0.5
8/_(x-1/2)^2+=0
9/_(x-3)^3=8
10/_(x+1/2)^2=1/25
11/_-3^x/81=-27
12/_a/x/15=-60/x
b/x/27=2/36
9: =>x-3=2
=>x=5
10: =>x+1/2=1/5 hoặc x+1/2=-1/5
=>x=-7/10 hoặc x=-3/10
12:
a: =>x^2=900
=>x=30 hoặc x=-30
b: =>x=1/18*27=3/2
7: =>|x-0,4|=1,1
=>x-0,4=1,1 hoặc x-0,4=-1,1
=>x=1,5 hoặc x=-0,7