576 + 23 = 599
Học tốt!!!

599

AHIHI

bn bít hong ??????

= 599 bn nha 

\(4\left(2x+1\right)^2=576\)

\(\left(2x+1\right)^2=\dfrac{576}{4}=144=12^2\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+1=12\\2x+1=-12\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=11\\2x=-13\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=-\dfrac{13}{2}\end{matrix}\right.\)

\(4\cdot(2x+1)^2=576\\\Rightarrow (2x+1)^2=576:4\\\Rightarrow(2x+1)^2=144\\\Rightarrow(2x+1)^2=(\pm12)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x+1=12\\2x+1=-12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=11\\2x=-13\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=-\dfrac{13}{2}\end{matrix}\right.\)

Vậy: \(x\in\left\{-\dfrac{13}{2};\dfrac{11}{2}\right\}\)

4.(2x+1)²=576

(2x+1)²   =576:4

(2x+1)²   =144

 144        =12² 

    (2x+1) =12

      2x      =12-1

      2x      =11

        x      =11:2

        x      =\(\dfrac{11}{2}\)

Vậy x = \(\dfrac{11}{2}\)

464

sửa đề :

2^x + 2^x+3 = 576

2^x . 1 + 2^x . 2³ = 576

2^x . ( 1 + 2³ ) = 576

2^x . 9 = 576

2^x = 576 : 9

2^x = 64

2^x = 2⁶

=> x = 6

2^x+2^x+3=576

2^x(1+2³)=576

2^x=579/9

2^x=64

2^x=2⁶

x=6