12-2.(x-4)=13.22
Những câu hỏi liên quan
Tìm x
(34\7.13+51\13.22+85\22.37+68\37.49+170\49.79+799\79.126).x=289\9
bạn nào help me
tính hợp lí
a)2016.(-4)-(-1008).8
b)(3^2016,11+3^2018.5):(3^2017.4^2)
c)(34/7.13+51/13.22+85/22.37+68/39.49):(39/7.16+65/16.31+52/31.43+26/43.49)
a, 2016.(-4) - (-1008).8= (-1008).8 - (-1008).8=0
b, Sai đề à bạn
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tính tổng
A = 34/7.13 + 51/13.22 + 85/22.37 + 68/37.49
B = 39/7.16 + 65/16.31 + 52/31.43 + 26/43.49
C = 4/8.13 + 4/13.18 + 4/18.23 + ..... + 4/252.258
mik cảm ơn mấy bn nhiều
\(A=\frac{34}{7.13}+\frac{51}{13.22}+\frac{85}{22.37}+\frac{68}{37.49}\)
\(=17.\left(\frac{2}{7.13}+\frac{3}{13.22}+\frac{5}{22.37}+\frac{4}{37.49}\right)\)
\(=17.\frac{1}{3}.\left(\frac{6}{7.13}+\frac{9}{13.22}+\frac{15}{22.37}+\frac{12}{37.49}\right)\)
\(=\frac{17}{3}.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+\frac{1}{22}-\frac{1}{37}+\frac{1}{37}-\frac{1}{49}\right)\)
\(=\frac{17}{3}.\left(\frac{1}{7}-\frac{1}{49}\right)\)
\(=\frac{17}{3}.\frac{6}{49}\)
\(=\frac{34}{49}\)
\(B=\frac{39}{7.16}+\frac{65}{16.31}+\frac{52}{31.43}+\frac{26}{43.49}\)
\(=13.\left(\frac{3}{7.16}+\frac{5}{16.31}+\frac{4}{31.43}+\frac{2}{43.49}\right)\)
\(=13.\frac{1}{3}.\left(\frac{9}{7.16}+\frac{15}{16.31}+\frac{12}{31.43}+\frac{6}{43.49}\right)\)
\(=\frac{13}{3}.\left(\frac{1}{7}-\frac{1}{16}+\frac{1}{16}-\frac{1}{31}+\frac{1}{31}-\frac{1}{43}+\frac{1}{43}-\frac{1}{49}\right)\)
\(=\frac{13}{3}.\left(\frac{1}{7}-\frac{1}{49}\right)\)
\(=\frac{13}{3}.\frac{6}{49}\)
\(=\frac{26}{49}\)
Câu C sai đề rồi , phải là như thế này :
\(C=\frac{4}{8.13}+\frac{4}{13.18}+\frac{4}{18.23}+...+\frac{4}{253.258}\)
\(=\frac{4}{5}.\left(\frac{5}{8.13}+\frac{5}{13.18}+\frac{5}{18.23}+...+\frac{5}{253.258}\right)\)
\(=\frac{4}{5}.\left(\frac{1}{8}-\frac{1}{13}+\frac{1}{13}-\frac{1}{18}+\frac{1}{18}-\frac{1}{23}+...+\frac{1}{253}-\frac{1}{258}\right)\)
\(=\frac{4}{5}.\left(\frac{1}{8}-\frac{1}{258}\right)\)
\(=\frac{4}{5}.\frac{125}{1032}\)
\(=\frac{25}{258}\)
A= 34/7.13+51/13.22+85/22.37+68/37.49 = ?
A= 34/7.13+51/13.22+85/22.37+68/37.49 = ?
Tìm x biết
( \(\dfrac{34}{7.13}+\dfrac{51}{13.22}+\dfrac{85}{22.37}+\dfrac{68}{37.49}+\dfrac{170}{49.79}+\dfrac{779}{79.126}\)) . x = \(\dfrac{289}{9}\)
\(\dfrac{\Leftrightarrow3A}{17}=\left(\dfrac{6}{7.13}+\dfrac{9}{13.22}+\dfrac{15}{22.37}+\dfrac{12}{37.49}+\dfrac{30}{49.79}+\dfrac{47}{79.126}\right)x=\dfrac{289}{9}\)
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Tìm x biết
\(\left(\dfrac{34}{7.13}+\dfrac{51}{13.22}+\dfrac{85}{22.37}+\dfrac{68}{37.49}+\dfrac{170}{49.126}\right)\).x=\(\dfrac{289}{9}\)
Cho
A=34/7.13+51/13.22+85/22.37+68/37.49
17 tháng 10 2023 lúc 15:42
Tính: \(A=\dfrac{34}{7.13}+\dfrac{51}{13.22}+\dfrac{85}{22.37}+\dfrac{68}{37.49}\)
\(\dfrac{3}{17}A=\dfrac{6}{7.13}+\dfrac{9}{13.22}+\dfrac{15}{22.37}+\dfrac{12}{37.49}\)
\(\dfrac{3}{17}A=\dfrac{1}{7}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{22}+\dfrac{1}{22}-\dfrac{1}{37}+\dfrac{1}{37}-\dfrac{1}{49}\)
\(\dfrac{3}{17}A=\dfrac{1}{7}-\dfrac{1}{49}=\dfrac{6}{49}\)
\(A=\dfrac{6}{49}:\dfrac{3}{17}=\dfrac{6.17}{49.3}=\dfrac{34}{49}\)
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