a x 23 + a x 13 x 4 + a x 25 = 2400
Những câu hỏi liên quan
tìm x biết:
a. 12+x \ 42 = 5/6
b. 25-x \ 40 = 3/8
c. 13+x \ 20 = 3/4
d. 23-x/25 = 4/5
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
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tìm x
a. 13+x\20 = 3\4
b.23-x\25 = 4\5
b) \(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=23-\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}=\frac{555}{25}\)
=> x = 555
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Bài 1: Tìm x, biết:
a) -15 + (53 – x) = 13 – (4 – 10)
b) 11 – (25 – x + 11) = - (45 – 7)
c) 23 + (63 – 7) = 5 – (23 - x)
d) 114 – (72 – x) = 24 – (25 – 43)
Tìm số nguyên x, biết:a) (25 + x) - 25 0; b) ( -19) - ( x- 19) 0;c) 15 + ( x - 10) 23; d) 19- ( - 13 + x) 40
Đọc tiếp
Tìm số nguyên x, biết:
a) (25 + x) - 25 = 0; b) ( -19) - ( x- 19) = 0;
c) 15 + ( x - 10) = 23; d) 19- ( - 13 + x) = 40
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
e , 13 - | x + 5 | = 13
g , | x - 10 | - ( -12 ) = 4
h , | x + 2 | < 5
a, 43 + ( 9 - 21 ) = 317 - ( x + 317 )
43 + ( -12 ) = 317 - x - 317
43 - 12 = 317 - 317 - x
-x = 31
x = -31
b, (15-x) + (x-12) = 7- (-5 + x)
15-x+x-12 = 7+5-x
15-12 = 12-x
3 = 12-x
x = 12-3
x = 9
c, x - { 57- [42+ (-23 - x)]} = 13- {47+ [25- (32-x)]}
x - [57- (42-23-x)] = 13- [47+ (25-32+x)]
x - [57- (19-x)] = 13- [47+ (x-7)]
x - (57-19+x) = 13- (47+x-7)
x - (38+x) = 13- (40+x)
x-38-x = 13-40-x
x = 13-40+38
x = 11
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )
b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )
c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}
d , -7 + | x - 4 | = -3
e , 13 - | x + 5 | = 13
g , | x - 10 | - ( -12 ) = 4
h , | x + 2 | < 5
a) \(43+\left(9-21\right)=317-\left(x+317\right)\\ 43+9-21=317-x-317\\ 52-21=\left(317-317\right)-x\\ 31=-x\\ x=-31\)Vậy x = -31
b) \(\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\\ 15-x+x-12=7+5-x\\ \left(x-x\right)+\left(15-12\right)=12-x\\ 3=12-x\\ x=9\)Vậy x = 9
c) \(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\\ x-\left\{57-\left[42+\left(-23\right)-x\right]\right\}=13-\left\{47+\left[25-32+x\right]\right\}\\ x-\left\{57-42+23+x\right\}=13-\left\{47+25-32+x\right\}\\ x-57+42-23-x=13-47-25+32-x\\ -57+42-23=-34-25+32-x\\ -15-23=-59+32-x\\ -38=-27-x\\ x=11\)Vậy x = 11
d) \(-7+\left|x-4\right|=-3\\ \left|x-4\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\)Vậy \(x\in\left\{8;0\right\}\)
e) \(13-\left|x+5\right|=13\\ \left|x+5\right|=0\\ \Rightarrow x+5=0\\ \Rightarrow x=-5\)Vậy x = -5
g) \(\left|x-10\right|-\left(-12\right)=4\\ \left|x-10\right|=-8\\ \Rightarrow x\in\varnothing\left(\text{vì }\left|x-10\right|\ge0\text{với mọi }x\right)\)Vậy \(x\in\varnothing\)
h) \(\left|x+2\right|< 5\\ 0\le\left|x+2\right|< 5\\ \Rightarrow\left|x+2\right|\in\left\{1;2;3;4\right\}\\ \Rightarrow x+2\in\left\{1;-1;2;-2;3;-3;4;-4\right\}\\ \Rightarrow x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)Vậy \(x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)
a) 43+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−3143+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−31Vậy x = -31
b) (15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9(15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9Vậy x = 9
c) x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11Vậy x = 11
d) −7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0−7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0Vậy x∈{8;0}x∈{8;0}
e) 13−|x+5|=13|x+5|=0⇒x+5=0⇒x=−513−|x+5|=13|x+5|=0⇒x+5=0⇒x=−5Vậy x = -5
g) |x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)|x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)Vậy x∈∅x∈∅
h) |x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}|x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}Vậy x∈{−1;−3;0;−4;1;−5;2;−6}
Bài 2.Tìm x:
a) 2017-(x-17)=169:13
b) [(25-x).3+21]:2-4=23
c)1+3+5+...+x=1600
Ta có : 1 + 3 + 5 + ..... + x = 1600
=> \(\frac{\text{[(x - 1) : 2 + 1](x + 1)}}{2}=1600\)
\(\Rightarrow\left(\frac{1}{2}x-\frac{1}{2}+1\right)\left(x+1\right)=3200\)
\(\Rightarrow\left(\frac{1}{2}x+\frac{1}{2}\right)\left(x+1\right)=3200\)
\(\Rightarrow\left(x+1\right)^2.\frac{1}{2}=3200\)
\(\Rightarrow\left(x+1\right)^2=6400\)
\(\Rightarrow x+1=80\)
=> x = 79
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Tim x :
a) -25 + x = -14
d) 13 + x - 47 = 23
a) - 25 + x = - 14
x = - 14 + 25
x = 11
Vậy x = 11
d) 13 + x - 47 = 23
x = 23 + 47 - 13
x = 70 - 13
x = 57
Vậy x = 57
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Tìm x:
a) x + (x+1) + (x+2) + (x+3) +.......+ 13 + 14 = 14
b) 25 + 24 + 23 +.......+ x + (x-1) + (x-2) + (x-3) = 25
a: =>14x+2*(14*13/2)=14
=>14x+14*13=14
=>14x=-12*14
=>x=-12
b: =>3x+(0-1-2-3+1+2+...+25)=25
=>3x+4+...+25=25
=>3x+4+...+24=0
=>3x+(24-4+1)*28/2=0
=>3x+21*28/2=0
=>3x=-21*14
=>x=-7*14=-98
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