Tim x biet:
X-2√x=x
Giuc mk voi
Giup minh cau nay voi
Tim x biet:x^3-x^2=0
x3-x2=0
x2(x-1)=0
Suy ra
x2=0 su ra x=0
x-1=0 suy ra x=1
3-x2 =0
3-x=0:2
3-x = 0
x= 3-0
x = 3
Tim x biet:x(2+x^2)(7-x)=0
x(2 + x2)(7 - x) = 0
<=> x = 0 hoặc 2 + x2 = 0 hoặc 7 - x = 0
Mà 2 + x2 > 0 => x = 0 và 7 - x = 0
=> x = 0 và x = 7
Vậy x = 0 và x = 7
tim X biet:x+2/3=X-2/2
\(\frac{x+2}{3}=\frac{x-2}{2}\Rightarrow2\left(x+2\right)=3\left(x-2\right)\)
=>2x+4=3x-6
=>2x-3x=-4-6
=>-x=-10
=>x=10
tim x biet:x-3/x+1=2/3
=>3.(x-3)=2.(x+1)
<=>3x-9=2x+2
<=>3x-2x=2+9
<=>x=11
tim x, y,biet:x-y= 2(x+y)=x:y
x-y=2(x+y) x-y=x;y x=3y
x-y=2x+2y 3y-y=3y;y x=3.3/2
x=3y 2y=3 x=9/2
y=3/2
tim so huu ti x biet:x^2=x^5
x2=x5 =>x2-x5=0
=>x2(1-x3)=0
=>x2(1-x)(x2+x+1)=0
=>x2=0 hoặc 1-x=0 hoặc x2+x+1=0
Với x2=0 =>x=0Với 1-x=0 =>x=1Với x2+x+1=0 =>\(\left(x+\frac{1}{2}\right)^2+\frac{3}{4}>0\) =>vô nghiệmtim x biet:x/6=2/9
\(\frac{x}{6}=\frac{2}{9}\Rightarrow x=\frac{6.2}{9}\Rightarrow x=\frac{4}{3}\)
tim so nguyen x biet:x^2-2x+1=0
x^2-2x+1=0
x2-x-x+1=0
x(x-1)-(x-1)=0
(x-1)(x-1)=0
(x-1)2=0
=>x-1=0
x=1
vậy x=1
tim x,biet:x-{x-[x-(-x+1)]}=1
Ta có : \(x-\left\{x-\left[x+x-1\right]\right\}=1\)
\(x-\left\{x-x-x+1\right\}=1\)
\(x-x+x+x-1=1\)
\(2x-1=1\)
\(2x=1+1\)
\(2x=2\)
\(\Rightarrow x=2:2\)
\(x=1\)
\(x-\left\{x-\left[x-\left(-x+1\right)\right]\right\}=1\)
\(x-\left\{x-\left[x+x-1\right]\right\}=1\)
\(x-\left\{x-x-x+1\right\}=1\)
\(x-x+x+x-1=1\)
\(2x-1=1\)
\(2x=2\)
\(x=1\)
Vậy x=1
tim x thuoc Q biet:x-2can bac 2 cua x=0
đề là nt này pk???
\(x-2\sqrt{x}=0\)
\(\Leftrightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\sqrt{x}=0\\\sqrt{x}=2\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=4\end{cases}}}\)