92 + 71 + 108 = (92 + 108) + 71 = 200 + 71 = 271

32 x 47 + 53 x 47 + 47 x 15 = 47(32 + 53 + 15)

                                         = 47.100

                                         = 4700

90 x 143 - 43 x 90 = 90.(143 - 43) = 90.100 = 9000

(1200 + 60) : 12 = 1800 : 12 = 150

2 x 18 x 24 + 3 x 50 x 16 + 12 x 32 x 4 = 18.(2.24) + 50.(3.16) + 32.(12.4) = 18.48 + 50.48 + 32.48 = 48(18 + 50 + 32) = 48.100 = 4800

92+71+108=71+92+108=71+200=271

92+71+108=71+(92+108)=71+200=271

90x143-43x90=90x(143-43)=90x100=9000

32x47+53x47+47x15=47x(32+53+15)=47x100=4700

(1200+60):12=1260:12=105

2x18x24+3x50x16+12x32x4=(2x24)x18+(3x16)x50+(12x4)x32

=48x18+48x50+48x32

=48x(18+50+32)

=48x100=4800

g: x:(-7)-6=-15

=>x:(-7)=-15+6=-9

=>\(x=\left(-9\right)\left(-7\right)=9\cdot7=63\)

h: \(x:12+\left(-12\right)=-37\)

=>\(x:12=\left(-37\right)-\left(-12\right)=-37+12=-25\)

=>\(x=-25\cdot12=-300\)

i: \(x:\left(-25\right)+81=85\)

=>\(x:\left(-25\right)=85-81=4\)

=>\(x=4\cdot\left(-25\right)=-100\)

k: \(\left(-31\right)\cdot x=-93\)

=>\(x=\dfrac{-93}{-31}=\dfrac{93}{31}\)

=>x=3

l: 5x+1=-4

=>5x=-4-1=-5

=>\(x=-\dfrac{5}{5}=-1\)

m: \(\left(-12\right)\cdot x+34=10\)

=>\(\left(-12\right)\cdot x=10-34=-24\)

=>12x=24

=>x=24/12=2

=0

0 nhé

0

a) x=3

b) x=1

c) x=1 hoặc -5

d) x=2

e) x=2

g) x=2

h) x=1 hoặc x=0 hoặc x=-1

i) x=-1 hoặc x=0

\(a.4^x=64\)

\(4^x=4^3\)

\(\Rightarrow x=3\)

\(b,3^{x\times4}=81\)

\(3^{x\times4}=3^4\)

\(x\times4=4\)

\(\Rightarrow x=1\)

\(c,\left(2+x\right)^4=81\)

     \(\left(2+x\right)^4=3^4\) 

       \(2+x=3\)

                \(x=3-2\)

                \(x=1\)

\(d,5^{x\times5}=125\)

     \(5^{x\times5}=5^3\)

        \(x\times5=3\)

        \(x=3:5\)

        \(x=\frac{3}{5}\)

Bài 2:

a: \(17-x=3\)

=>\(x=17-3\)

=>x=14(nhận)

b: \(2\cdot\left(x-1\right):3=6\)

=>\(2\left(x-1\right)=6\cdot3=18\)

=>x-1=18/2=9

=>x=9+1=10(nhận)

c: \(x+\left(-2\right)=\left(-11\right)+7\)

=>\(x-2=-4\)

=>\(x=-4+2=-2\left(loại\right)\)

d: \(\left(x-1\right)^2-5=20\)

=>\(\left(x-1\right)^2=25\)

=>\(\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(nhận\right)\\x=-4\left(loại\right)\end{matrix}\right.\)

Câu 3:

a: Đặt *=a

\(\overline{57a3}⋮9\)

=>\(5+7+a+3⋮9\)

=>\(a+15⋮3\)

mà 0<=a<=9

nên a=3

=>*=a

b: \(A=123\cdot7+8+9\)

123*7 là số lẻ

9 là số lẻ

=>123*7+9 chia hết cho 2

mà 8 chia hết cho 2

nên \(A=123\cdot7+9+8⋮2\)

\(123\cdot7⋮3;9⋮3;8⋮̸3\)

=>\(A=123\cdot7+9+8⋮̸3\)

c: \(B=3\cdot5\cdot7+10^{50}\)

\(=5\cdot3\cdot7+5\cdot5^{49}\cdot2^{49}\)

\(=5\left(3\cdot7+5^{49}\cdot2^{49}\right)⋮5\)

=>B là hợp số

\(3^x-15=12\\ \Rightarrow3^x=27\\ \Rightarrow x=3\)

\(5^{x-1}-12=13\\ \Rightarrow5^{x-1}=25\\ \Rightarrow x=3\)

\(3^{x-2}.9=81\\ \Rightarrow3^{x-2}=9\\ \Rightarrow x=4\)

\(3^{x+1}:9=3\\ \Rightarrow3^{x+1}=27\\ \Rightarrow x=2\)

\(2.x^3=16\\ \Rightarrow x^3=8\\ \Rightarrow x=2\)

\(75:x^2=3\\ \Rightarrow x^2=25\\ \Rightarrow x=\pm2\)

Câu cuối cộng trừ 5

1.8100

2. 34 x 18 + 18 x 66

= 18 x ( 34 + 66)

= 18 x 100 = 1800

3. X × ( 8 +  12) =  160 + 20 × 12

= X x 20 = 160 + 240

= X x 20 = 400

X = 400 : 20 = 20

4. X x 12 - X x 2 = 2020

(12 - 2) x X = 2020

10 x X = 2020

X = 2020 : 10 = 202

1.8100

2. 34 x 18 + 18 x 66

= 18 x ( 34 + 66)

= 18 x 100 = 1800

3. X × ( 8 +  12) =  160 + 20 × 12

= X x 20 = 160 + 240

= X x 20 = 400

X = 400 : 20 = 20

4. X x 12 - X x 2 = 2020

(12 - 2) x X = 2020

10 x X = 2020

X = 2020 : 10 = 202