\(a,2448:\left[119-\left(x-6\right)\right]=24\)

\(119-\left(x-6\right)=2448:24\)

\(119-\left(x-6\right)=102\)

\(x-6=119-102\)

\(x-6=17\)

\(x=17+6\)

\(\Rightarrow x=23\)

\(b,2016-100\times\left(x+11\right)=128:8\)

\(2016-100\times\left(x+11\right)=16\)

\(100\times\left(x+11\right)=2016-16\)

\(100\times\left(x+11\right)=2000\)

\(x+11=2000:100\)

\(x+11=20\)

\(x=20-11\)

\(\Rightarrow x=9\)

\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)

Câu b,

= 50x + (1 + 3 + 5 + ..... + 99) = 2550

= 50x + 2500 = 2550

= 50x = 2550 - 2500

= 50x = 50

= x = 50 : 50

= x = 1

refer

A) 2448:[119-[x-6]]=24

<=> 199 - ( x-6 ) = 2448 : 24 = 102

<=> x - 6 = 199 - 102 = 97

<=> x = 97 +6 = 103

B) (x+1)+(x+3)+(x+5)+......+(x+99) = 2550

(x+x+x+....+x)+(1+3+5+....+99) = 2550

50x + 2500 = 2550

50x = 2550 - 2500

50x = 50

x = 50 : 50

x = 1

a. x-32.45 = 0

=> x - 32 = 0 : 45

=> x - 32 = 0

=> x        = 0 + 32

=> x        = 33

   Vậy x = 32 

b. 2448 : [119 - (x - 6)] câu này hình như sai đề hay sao đấy bạn

c. 25.( 52 - x) = 25

=> 52 - x        = 25 : 25

=> 52 - x        = 1

=>        x        = 52 - 1

=>        x        = 51

   Vậy x = 51

d. x - 84 : 42 = 21

=> x - 84       = 21.42

=> x - 84       = 882

=> x              = 882 + 84 

=> x             = 966

    Vậy x = 966

k mình nha, thks ^^

12 tập hợp

\(2448:\left[119-\left(x-6\right)\right]=24\)

\(119-\left(x-6\right)=2448:24\)

\(119-\left(x-6\right)=102\)

\(x-6=119-102\)

\(x-6=17\)

\(x=17+6\)

\(x=23\)( thỏa mãn \(x\in N\) )

vậy x = 23

\(2016-100\cdot\left(x+11\right)=2^7:2^3\)

\(2016-100\cdot\left(x+11\right)=128:8\)

\(2016-100\cdot\left(x+11\right)=16\)

\(100\cdot\left(x+11\right)=2016-16\)

\(100\cdot\left(x+11\right)=2000\)

\(x+11=2000:100\)

\(x+11=20\)

\(x=20-11\)

\(x=9\)( thỏa mãn \(x\in N\))

vậy x = 9

1) 2448 : [ 119 - (x - 6)] = 24

=> 119 - (x - 6) = 2448 : 24

=> 119 - x + 6 = 102

=> 125 - x = 102

=> x = 125 - 102 = 23 (thỏa mãn x thuộc N)

Vậy x = 23

2) 2016 - 100.(x + 11) = 2^7 : 2^3 

=> 2016 - 100.(x + 11) = 2^4 = 16

=> 100.(x+11) = 2016 - 16 = 2000

=> x + 11 = 2000 : 100 = 20

=> x = 20 -11 = 9 ( thỏa mãn)

Vậy x =9

a,

7x – 8 = 713

7x = 713 + 8

7x = 721

x = 721 : 7

x = 103.

b,

2448:[119-(x-6)]=24

119-(x-6)= 2448 : 24

119-(x-6)= 102

x-6= 119-102

x-6= 17

x=17+6

x=23

c,

2016 - 100.( x +11 ) = 2^7 : 2^3
2016 - 100.(x+11) = 2^4
2016 - 100.(x+11)=16
100.(x+11) = 2016-16
100.(x+11)=2000
x+11=2000:100
x+11=20
x = 20-11
x = 9

a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)

\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)

\(\Leftrightarrow\left(x:3+17\right):10+48=50\)

\(\Leftrightarrow\left(x:3+17\right):10=2\)

\(\Leftrightarrow x:3+17=20\)

\(\Leftrightarrow x:3=3\)

hay x=9

b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow119-\left(x-6\right)=102\)

\(\Leftrightarrow x-6=17\)

hay x=23

c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)

\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)

\(\Leftrightarrow\left(35:x+3\right)=8\)

\(\Leftrightarrow35:x=5\)

hay x=7

2448:[119-[x-6]]=24

<=> 199 - ( x-6 ) = 2448 : 24 = 102

<=> x - 6 = 199 - 102 = 97

<=> x = 97 +6 = 103

2448:[119-(x-6)]=24

119-(x-6)= 2448 : 24

119-(x-6)= 102

x-6= 119-102

x-6= 17

x=17+6

x=23

2448:[119-[x-6]]=24

        [119-(x-6)]=2448:24

        [119-(x-6)=102

                 x-6=119-102

                 x-6=17

                    x=17+6

                    x=23

119 - (x - 6) = 2448 : 24=102

x-6= 119 - 102=17

x = 17 + 6=23

119 - ( x - 6 ) = 2448 : 24 = 102

x - 6 = 119 - 102 = 17

x = 17 + 6 = 23

k cho minh nha NGUYEN LINH DAN ! cam on ban