đề sai rồi cậu, ghi đề lại mình làm cho

\(=\left(12x+9x^2+4\right)-\left(6y\right)^2=\left(3x+2\right)^2-\left(6y\right)^2\)

\(=\left(3x+2-6y\right)\left(3x+2+6y\right)\)

k mình cái

12x+9x²+4-36y²

= (9x²+12x+4)-36y²

= (3x+2)²-36y²

= ((3x+2)-6y²)((3x+2)+6y²)

=(3x+2-6y²)(3x+2+6y²)

Phải là

=((3x+2)-6y)((3x+2)+6y)

=(3x+2-6y)(3x+2+6y) nha

Mik bấm điện thoại bị nhảy chữ xin lỗi nhiều nha

Hk tốt ^-^

a) \(4x^2y^2-12xy+9y^2\)

\(=y\left(4x^2y-12x+9y\right)\)

b) \(25x^2-36y^2\)

\(=\left(5x\right)^2-\left(6y\right)^2\)

\(=\left(5x+6y\right)\left(5x-6y\right)\)

\(=6\left(4x^2-9y^2+6y-1\right)\)

\(=6\left[\left(2x\right)^2-\left(3y-1\right)^2\right]\)

\(=6\left(2x-3y+1\right)\left(2x+3y-1\right)\)

\(24x^2+36y-54y^2-6\)

\(=6\left(4x^2+6y-9y^2-1\right)\)

\(=6\left[4x^2-\left(9y^2-6y+1\right)\right]\)

\(=6\cdot\left[\left(2x\right)^2-\left(3y-1\right)^2\right]\)

\(=6\left(2x-3y+1\right)\left(2x+3y-1\right)\)

a)  \(4x^3-4x^2=4x^2\left(x-1\right)\)

b)  mk chỉnh đề

\(9x^2y^2+15x^2y-21xy^2=3xy\left(3xy+5x-7y\right)\)

c)   \(4x^2\left(x-2y\right)-20x\left(2y-x\right)=4x\left(x-2y\right)\left(x+5\right)\)

d)  \(4x^2-4x+1=\left(2x-1\right)^2\)

e)  bạn ktra lại đề

f)  \(16x^2+24xy+9y^2=\left(4x+3y\right)^2\)

      \(49\left(y-4\right)^2-9y^2-36y-36\)

\(=\left[7\left(y-4\right)\right]^2-\left[\left(3y\right)^2+2.3y.6+6^2\right]\)

\(=\left(7y-28\right)^2-\left(3y+6\right)^2\)

\(=\left(7y-28-3y-6\right)\left(7y-28+3y+6\right)=\left(4y-34\right)\left(10y-22\right)=4\left(2y-17\right)\left(5y-11\right)\)

\(49\left(y-4\right)^2-9y^2-36y-36=49\left(y-4\right)^2-9\left(y^2+4y+4\right)\)\(=\left[7\left(y-4\right)\right]^2-\left[3\left(y+4\right)\right]^2=\left(7y-28-3y-12\right)\left(7y-28+3y+12\right)\)\(=\left(4y-40\right)\left(10y-16\right)=4\left(y-20\right)\left(5y-8\right)\)

\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

a) \(x^6-y^6\)

\(=\left(x^3\right)^2-\left(y^3\right)^2\)

\(=\left(x^3-y^3\right)\left(x^3+y^3\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)\left(x^2-xy+y^2\right)\)

b) \(10ab+0,25a^2+100b^2\)

\(=\left(0,5a\right)^2+2\cdot0,5a\cdot10b+\left(10b\right)^2\)

\(=\left(0,5a+10b\right)^2\)

c) \(9x^2-xy+\frac{1}{36}y^2\)

\(=\left(3x\right)^2-2\cdot3x\cdot\frac{1}{6}y+\left(\frac{1}{6}y\right)^2\)

\(=\left(3x-\frac{1}{6}y\right)^2\)