960-4608:x=888

<=>4608:x=72

<=>x=64

960 - (4608 : x) = 888

          4608 : x = 960 - 888

          4608 : x = 72

             x = 4608 : 72 

              x = 64

960-4608:x=888

960-888=4608:x

72=4608:x

x=4608:72

x=64

960 - 4608 : x = 888

        4608 : x = 960 - 888

        4608 : x = 72

                  x = 4608 : 72

                  x = 64

****

960 - 4608/X = 888

960 - 888 = 4608/X

72 = 4608/X

X = 4608 : 72

X = 64

\(960-\frac{4608}{x}=888\)

\(\frac{4608}{x}=960-888\)

\(\frac{4608}{x}=72\)

\(x=\frac{4608}{72}\)

\(x=64\)

960 - 4608/x = 888

=> 4608/x = 960 - 888

=> 4608/x = 72

=>4608.1 = 72 . x

=> 4608 = 72 . x

=> x = 4608 : 72

=> x = 64

Vậy x = 64

Bài 1: 

a: x/-2=-18/x

=>x²=36

=>x=6 hoặc x=-6

b: x/2+x/5=17/10

=>7/10x=17/10

hay x=17/7

<=> 2ⁿx(6+3)=4608

<=>2ⁿx9=4608

<=>2ⁿ=512

<=>2ⁿ=2⁹

=>n=9

=> (6 + 3).2ⁿ = 4608

=> 9.2ⁿ = 4608

=> 2ⁿ = 4608 : 9 

=> 2ⁿ = 512 = 2⁹ => n = 9 

Vậy...

   6×2ⁿ+3 x 2ⁿ=4608

=> (6 + 3).2ⁿ = 4608

<=> 9.2ⁿ = 4608

<=> 2ⁿ = 4608 : 9 

<=> 2ⁿ = 512 = 2⁹ 

=> n = 9 

Vậy.......................

hok tốt

Bài 1: 

Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)

Vậy: \(x=\dfrac{4}{65}\)

Bài 2: 

a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)

\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)

\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)

\(=\dfrac{5366}{527}\)

b) -26 - ( x - 7 ) = 0

               x - 7   = -26 - 0

                x - 7  = -26

                x        = -26 + 7

                 x       = -19

Bài 2 :

a) 3 - ( 17 - x ) = -12

          ( 17 - x ) = 3 - ( -12 )

          ( 17 - x ) = 15

                    x  = 17 - 15

                    x  = 2

b) -26 - ( x - 7)=0

             x - 7 = -26 -0

            x - 7 = -26

              x = -26 + 7

             x = -19