`1.` He writes well

`2.` What do these flowers cost?

`3.` He goes to Ha Noi by car. 

`4.` Nam's hobby is planting trees.

`5.` He is good at cooking.

`6.` He is interested in playing games.

1 He writes well

2 What is the price of these flowers?

3 He goes to Ha Noi by car

4 Nam's hobby is planting trees

5 He is a good cook / He is good at cooking

5 He is interested in playing games

1.too 2.either 3.either 4.too 5.too

1 too

2 either

3 either

4 too 

5 too

p: \(\left(-\dfrac{2}{5}\right)^2+\dfrac{17}{-18}\cdot\dfrac{36}{34}-\left(-\dfrac{2}{3}\right)^3\)

\(=\dfrac{4}{25}-\dfrac{17}{34}\cdot\dfrac{36}{18}-\dfrac{-8}{27}\)

\(=\dfrac{4}{25}+\dfrac{8}{27}-1=\dfrac{-367}{675}\)

q: \(\left(-\dfrac{1}{2}\right)^0-\dfrac{-1}{3}\cdot\dfrac{-9}{12}+\dfrac{2^4}{-4}\)

\(=1-\dfrac{1}{3}\cdot\dfrac{3}{4}+\dfrac{16}{-4}\)

\(=1-\dfrac{1}{4}-4=-3-\dfrac{1}{4}=-\dfrac{13}{4}\)

r: \(\left(-5\right)\cdot\dfrac{17}{45}-\left(-\dfrac{2}{3}\right)^2+\left(-\dfrac{20}{2023}\right)^0\)

\(=-\dfrac{17}{9}-\dfrac{4}{9}+1\)

\(=-\dfrac{21}{9}+1=-\dfrac{12}{9}=-\dfrac{4}{3}\)

Câu 2:

\(PT\Leftrightarrow\sqrt{\left(x-3\right)^2}=4x-21\\ \Leftrightarrow\left|x-3\right|=4x-21\\ \Leftrightarrow\left[{}\begin{matrix}x-3=4x-21\left(x\ge3\right)\\3-x=4x-21\left(x< 3\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(tm\right)\\x=\dfrac{24}{5}\left(ktm\right)\end{matrix}\right.\Leftrightarrow x=6\)

Đề đâu ạ?

Bài 19:

Chu vi hình vuông là: \(\left(12+6\right)\cdot2=36\left(cm\right)\)

Độ dài cạnh hình vuông là 36/4=9(cm)

Diện tích hình vuông là \(9^2=81\left(cm^2\right)\)

Bài 20:

Độ dài đường cao là \(\dfrac{160}{4}=40\left(m\right)\)

Diện tích miếng đất là: \(60\cdot40=2400\left(m^2\right)=0,24\left(ha\right)\)

Khối lượng ngô thu hoạch được là:

\(0,24:3\cdot13,5=1,08\left(tấn\right)=1080\left(kg\right)\)

1/48

2/35

3/bí

1/21

2/17

3/0

nếu đúng thid thik cho mk nha

a) 20         b) -18        c) 0

33 A
34 B
35 B -> faster
36 A -> many
37 B -> is
38 A
39 D
40 A
41 B
42 D
43 A
44 D
45 C
46 B
47 A
48 B
49 A
50 A

33.A

34.B

35.C

36.A

37.B

38.A

39.D

40.A

41.B

42.D

43.A

44.D

45.C

46.B

47.A

48.B

49.A

50.A

33. A
34. B
35. C. more fast => faster
36. A. much => many
37. B. are => is
38. A
39. D
40. A
41. B
42. D
43. A
44. D
45. C
46. B
47. A
48. B
49. A
50. A

ta có: \(\frac{31+32+35}{34}=\frac{31}{34}+\frac{32}{34}+\frac{35}{34}.\)

mà \(\frac{31}{32}>\frac{31}{34};\frac{32}{33}>\frac{32}{34}\)

\(\Rightarrow\frac{31}{32}+\frac{32}{33}+\frac{35}{34}>\frac{31}{34}+\frac{32}{34}+\frac{35}{34}=\frac{31+32+35}{34}\)

a)  đoạn bổ sung :- X - T - G - X - A - T - G - X - T - A - G - T - X - G -

b) - theo NTBS :  A = T = 1500 (nu)

                           G = X = 2000 (nu)

- chiều dài gen : 

L = \(\dfrac{N}{2}.3,4=\dfrac{1500.2+2000.2}{2}.3,4=11900\left(A\right)\)

Chu kỳ xoắn :  C = \(\dfrac{N}{20}=\dfrac{1500.2+2000.2}{20}=350\left(chuky\right)\)