tim x
1/4. (x/4+-2/x+2/8)=-1/14
1/Tính :
a. A= 1/17+ 7/17.27 + 7/27.37 + .................... +7/1997.2007
b. B=-1/2007.2006 - 1/2005.2006 - 1/2005.2004 - .................... - 1/3.2 - 1/2.1
2/Tim x biết :
2/(x+2)(x+4) + 4/(x+4)(x+8) + 6/(x+8)(x+14) = x/(x+2)(x+14)
Với x không thuộc tập hợp {-2;-4;-6;-8;-14}
A = 7/7.17 + 7/17.27 + 7/27.37 + ............ +7/1997.2007
A=7/10 ( 10/7.17 + 10/17.27 + 10/27.37 + ................+10/1997.2007)
A= 7/10 ( 1/7 -1/17 + 1/17 - 1/27 + 1/27 - 1/37 +...............+ 1/1997 - 1/2007)
A= 7/10 (1/7 - 1/2007)
A= 7/10 . 2000/14049
A=200/2007
bây h mk có vc rùi tích đúng nha tối mk lm típ cho
tim x biet 5/4*(x-8)=-5/3(14-1/2)
1.Cho A=1/1.2+1/3.4+...+1/99.100
C/m :7/12<A<5/6
2.Tim x:
a.2/(x+2)(x+4)+4/(x+4)(x+8)+6/(x+8)(x+14)
b.x-10/30+x-14/43+x-5/95+x-148/8=0
Lam giup minh nhe
Minh dang can gap
Tim x : \(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
Tim x
a) 10^x=1^x
B)X^10=x
c) x^10=1^x
d)2.3^x=10.3^12+8.27^4
e) (19x+2.5^2):14=(13-8)^2-4^2
10^X=1^X
Do 1^mấy cũng =1
=>10^x=1
=>x=0
1) tim m de pt co 2 nghiem x1;x2 thoa man
Ptr có nghiệm `<=>\Delta' >= 0`
`<=>[-(m+1)^2]-6m+4 >= 0`
`<=>m^2+2m+1-6m+4 >= 0`
`<=>m^2-4m+5 >= 0<=>(m-2)^2+1 >= 0` (LĐ `AA m`)
`=>` Áp dụng Viét có: `{(x_1+x_2=[-b]/a=2m+2),(x_1.x_2=c/a=6m-4):}`
Có:`(2m-2)x_1+x_2 ^2-4x_2=4`
`<=>(x_1+x_2-4)x_1+x_2 ^2-4x_2=4`
`<=>x_1 ^2+x_1 x_2 -4x_1+x_2 ^2-4x_2=4`
`<=>(x_1+x_2)^2-x_1x_2-4(x_1+x_2)=4`
`<=>(2m+2)^2-(6m-4)-4(2m+2)=4`
`<=>4m^2+8m+4-6m+4-8m-8=4`
`<=>4m^2-6m-4=0`
`<=>(2m-3/2)^2-25/4=0`
`<=>|2m-3/2|=5/2`
`<=>[(m=2),(m=-1/2):}`
tim x biet 2/(x+2)+(x+4)+4/(x+4)+(x+6)+6/(x+6)+(x+14)=x/(x+2)+(x+14)
bài 1: thực hiện phép tính
1) (13.17\(^4\)+4.17\(^4\)):17\(^3\)-(14.\(3^3\)-14.3\(^2\)):9
2) \(2^3\).\(5^2\)-[131-(23-2\(^3\))\(^2\)]
bài 2: tìm x
1) 6\(^2\).x+14.x-3\(^4\)=69
2) 3\(^x\)=81
3) 3. (2x+1)\(^2\)=75
2:
1: =>36x+14x=69+81=150
=>50x=150
=>x=3
2: 3^x=81
=>3^x=3^4
=>x=4
3: 3(2x+1)^2=75
=>(2x+1)^2=25
=>2x+1=5 hoặc 2x+1=-5
=>x=-3 hoặc x=2
1:
1: \(\dfrac{13\cdot17^4+4\cdot17^4}{17^3}-\dfrac{14\cdot3^3-14\cdot3^2}{9}\)
\(=\dfrac{17^4\cdot\left(13+4\right)}{17^3}-\dfrac{14\cdot3^2\left(3-1\right)}{9}\)
\(=17\cdot17-14\cdot2\)
=289-28
=261
2:
\(2^3\cdot5^2-\left[131-\left(23-2^3\right)^2\right]\)
\(=8\cdot25-131+\left(-1\right)^2\)
=69+1
=70
tim x biết: x=14^5*21^3*2^6 / 8^3*81*49^4