`@` `\text {Ans}`

`\downarrow`

\(7\cdot35\cdot7\cdot25\)

`=`\(7^2\cdot7\cdot5\cdot5^2\)

`=`\(7^3\cdot5^3=\left(7\cdot5\right)^3=35^3\)

Ta có:

12 . 12 . 12 . 2. 6 = 12 . 12 . 12 . 12 = 12⁴

25 . 5 . 4 . 2 . 10 =  25 . 4 . 2 . 10 . 5 = 100 . 100 = 100²

2. 10 . 10 . 3 . 5. 10 = 10 . 10 . 10 . 2 . 5 . 3 = 10 . 10 . 10 . 10 . 3 = 10⁴ . 3 

a,12.12.2.12.6=12.12.12.(2.6)=12.12.12.12=12⁴

b,25.5.4.2.10=(25.4)(5.2.10)=100.100=100²

c,2.10.10.3.5.10=10.10.10.2.5.3=10.10.10.10.3=10⁴.3

a, 2.2.4.4 =  2 . 2 . 2 2 . 2 2 = 2 1 + 1 + 2 + 2 =  2 6

b, 10.1000.100000 =  10 . 10 3 . 10 5 =  10 1 + 3 + 5 = 10 9

c,  4 5 . 2 7 =  2 2 . 2 7 = 2 2 . 5 . 2 7 = 2 10 . 2 7 = 2 10 + 7 = 2 7

d,  3 3 . 18 - 3 3 . 15 =  3 3 ( 18 - 15 ) = 3 3 . 3 = 3 3 + 1 = 3 4

e,  6 3 . 36 =  6 3 . 6 2 = 6 3 + 2 = 6 5

f,  49 3 . 7 4 =  7 2 3 . 7 4 = 7 2 . 3 . 7 4 = 7 6 . 7 4 =  7 6 + 4 = 7 10

g,  a 9 . a 7 = a 9 + 7 = a 16

h,  a . b 6 . b 6 =  a 6 . b 6 . b 6 = a 6 . b 6 . b 6 = a 6 . b 6 + 6 = a 6 . b 12

a) 5.5.5.5.5.5 = 5 6

1)  \(12\cdot12\cdot2\cdot12\cdot6=12\cdot12\cdot12\cdot12=12^4\)

2)   \(25\cdot5\cdot4\cdot2\cdot10=\left(25\cdot4\right)\cdot\left(5\cdot2\cdot10\right)=100\cdot100=100^2=10^4\)

3)   \(2\cdot10\cdot10\cdot3\cdot5\cdot10=3\cdot10\cdot10\cdot10\cdot10=3\cdot10^4\)

4)  \(a\cdot a\cdot a+b\cdot b\cdot b\cdot b=a^3+b^4\)

Viết gọn các biểu thức sau bằng cách dùng lũy thừa

1) 12.12.2.12.6

=> 12 . 12 . 12 . (2 . 6)

 = 12 . 12 . 12 . 12 . 12 = 12⁵

2) 25.5.4.2.10

=> ( 25 . 4 ) . ( 2 . 5 . 10 )

  = 100 . 100 = 100²

3) 2.10.10.3.5.10

=> ( 2 . 5 ) . 10 . 10 . 10 . 3 

  = 10 . 10 . 10 . 10 . 3 = 10⁴ . 3

4) a.a.a cộng b.b.b.b

=> a³ + b⁴

Chịu

`10.1000.100000`

`=10^{1}.10^{3}.10^{5}`

`=10^{1+3+5}`

`=10^{9}`

\(10.1000.100000=10.10^3.10^5=10^9\)

2.2.2.3.3 = 23 .32.

Viết gọn các tích sau bằng cách dùng luỹ thừa:

a) 2.2.2.3.3

b) x4.x

5.5.5.5.5 = 56

=5^5 nha bn

=5⁶