Đáp án C

Những phân số có cùng tử số nếu phân số nào có mẫu số lớn hơn thì bé hơn nên  7 11 >  7 9 >  7 5 .

\(\frac{96}{135}\)+\(\frac{153}{199}\)+\(\frac{79}{711}\)và 3

=> 2 < 3

=> \(\frac{96}{135}\)+\(\frac{153}{199}\)+\(\frac{79}{711}\)<3

CHÚC BẠN HỌC GIỎI

K MÌNH NHÉ

thì bạn tính ra rồi so sánh

\(\frac{96}{135}\)\(+\)\(\frac{153}{199}\)\(+\) \(\frac{79}{711}\)

\(=\)\(1.591066443\)

Mà \(1.591066443\)bé hơn \(3\), nên \(\frac{96}{135}\)\(+\)\(\frac{153}{199}\)\(+\) \(\frac{79}{711}\) \(< \) \(3\)

a: \(4\cdot3^3-75:5^2\)

\(=4\cdot27-\dfrac{75}{25}\)

=108-3

=105

b: \(7\cdot2^4-16\cdot3\)

\(=16\cdot7-16\cdot3\)

=16(7-3)

=16*4=64

c: \(2^3\cdot17-2^3\cdot14\)

\(=8\cdot17-8\cdot14\)

=8(17-14)

=8*3

=24

d: \(45+\dfrac{54}{3^2}\)

\(=45+\dfrac{54}{9}\)

=45+6

=51

e: \(17\cdot85+15\cdot17-120\)

\(=17\left(85+15\right)-120\)

=1700-120

=1580

f: \(\dfrac{3^{24}}{3^{21}}+2^2\cdot2^3\)
 

\(=3^3+2^5\)

=27+32

=59

g: \(92+4^3:8\)

=92+64/8

=92+8

=100

h: \(5\cdot2^3+7^{11}:7^9-1^{2023}\)

\(=5\cdot8+49-1\)

=40+48

=88

1: \(23+\left(-13\right)+\left(-50\right)\)

\(=23-13-50\)

=10-50

=-40

2: \(-5+15+\left(-123\right)\)

\(=\left(-5+15\right)-123\)

=10-123

=-113

3: \(5871:\left\{928-\left[\left(-82+247\right)\right]\right\}\cdot5\)

\(=5871-\left\{928+82-247\right\}\cdot5\)

\(=5871-763\cdot5=5871-3815=2056\)

4: \(40-\left(4\cdot5^2-3\cdot2^3\right)\)

\(=40-4\cdot5^2+3\cdot2^3\)

\(=40-4\cdot25+3\cdot8\)

=40-100+24

=64-100

=-36

5: \(6^2\cdot5-7^2+149\)

\(=36\cdot5-49+149\)

\(=180+149-49\)

=180+100

=280

6: \(-210:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]+\left(-2022\right)\)

\(=-210:\left[16+3\cdot\left(6+3\cdot4\right)\right]+\left(-2022\right)\)

\(=-210:\left[16+3\cdot18\right]+\left(-2022\right)\)

\(=-210:70-2022\)

=-3-2022

=-2025

7: \(5\cdot2^3+7^{11}:7^9-2023^0\cdot1^8\)

\(=5\cdot8+7^2-1\)

=40+49-1

=39+49

=88

8: \(400:\left\{5\cdot\left[360-\left(290+2\cdot5^2\right)\right]\right\}\)

\(=400:\left\{5\cdot\left[360-290-2\cdot25\right]\right\}\)

\(=400:\left\{5\cdot20\right\}\)

\(=\dfrac{400}{100}=4\)

9: \(75-\left(3\cdot5^2\right)-4\cdot5^3\)

\(=75-3\cdot25-4\cdot5^3\)

=-4*125

=-500

4.5580952381

=45-2=43

5.9-32:16

=45-2

=43

\(\Rightarrow2x-49=160\\ \Rightarrow2x=160+49=209\\ \Rightarrow x=\dfrac{209}{2}=104,5\)

x=104,5

2x - 49 = 160

2x= 160 + 49

2x = 209

2 : x = 209

x = 209 : 2

x = 104,5

\(750:\left\{32-\left[22+\left(5.32-420\right)\right]\right\}+100\)

\(=750:\left\{32-\left[22+\left(160-420\right)\right]\right\}+100\)

\(=750:\left\{32-\left[22+\left(-260\right)\right]\right\}+100\)

\(=750:\left[32-\left(-238\right)\right]+100\)

\(=750:270+100\)

\(=\dfrac{25}{9}+100\)

\(=\dfrac{925}{9}\)

Mình ko chắc có đúng hông, có gì thông kẻm nha fen

  750 :{32-[22+(5.32-420)]}+100

=750:{32-[22+(160-420)]}+100

=750:{32-[22-260]}+100

=750:{32+238}+100

=750:270+100

=25/9+100

=925/9

tick giùm

\(375:\left\{32-\left[4+\left(5.32-42\right)\right]\right\}-14\)

\(=375:\left\{32-\left[4+\left(160-42\right)\right]\right\}-14\)

\(=375:\left\{32-\left[4+118\right]\right\}-14\)

\(=375:\left\{32-122\right\}-14\)

\(=375:\left(-90\right)-14\)

\(=\dfrac{-25}{6}-14\)

\(=\dfrac{-109}{6}\)