\(2^x+5\cdot2^{x+2}=168\)

=>\(2^x+20\cdot2^x=168\)

=>\(21\cdot2^x=168\)

=>\(2^x=8=2^3\)

=>x=3

\(2^x+5.2^{x+2}=168\\ \Leftrightarrow2^x.\left(1+5.2^2\right)=168\\ \Leftrightarrow2^x.21=168\\ \Leftrightarrow2^x=\dfrac{168}{21}=8=2^3\\ Vây:x=3\)

a) \(2^x+2^{x+3}=144\)

\(2^x\left(1+2^3\right)=144\)

\(2^x.9=144\)

\(2^x=144:9=16\)

=> \(2^x=2^4\Rightarrow x=4\)

b) \(2^{x-1}+5.2^{x-2}=224\)

\(2^{x-2}\left(2+5\right)=224\)

\(2^{x-2}.7=224\Rightarrow2^{x-2}=32\Rightarrow2^{x-2}=2^5\)

=> x - 2 = 5 => x = 7

a ) 2^x + 2^{x + 3} = 144
=> 2^x . ( 1 + 2³ ) = 144

=> 2^x . 9  = 144

=> 2^x = 16

=> 2^x = 2⁴

=> x = 4
Vậy x = 4

b ) 2^{x - 1}  + 5. 2^{x - 2} = 224

=> 2^{x - 2} . ( 2 + 5 ) = 224

=> 2^{x - 2} . 7 = 224

=> 2^{x - 2} =  32

=> 2^{x - 2} = 2⁵

=> x - 2 = 5

=> x = 7

Vậy x = 7

\(5\cdot2^x+1\cdot2^{x-2}-2^x=384\)

=>\(4\cdot2^x+2^x\cdot\dfrac{1}{4}=384\)

=>2^x=1536/17

hay \(x\in\varnothing\)

Sai đề thì phải bạn ơi!

Chắc vậy

8^x=2¹¹¹

=>(2³)^x=2¹¹¹

=>2^3x=2¹¹¹

=>3x=111

=>x=37

2^x+5.2^x=48

=>2^x.6=48

=>2^x=8=2³

=>x=3

Câu cuối ko làm đc nha

a. 8^x = 2¹¹¹

    2^3x = 2¹¹¹

    3x  = 111

      x  = 111:3

     x  = 37

b. 2^x + 5.2^x = 48

    2^x(5 + 1 )= 48

    2^x.6        = 48

    2^x           = 48 : 6

    2^x           = 8

    2^x            = 2³

      x            = 3

c. 2^x + 3.2^x-1 = 40

   2^x(3:2 +1 )     = 40

   2^x . \(\frac{5}{2}\)      = 40

    2^x                  = 40 : \(\frac{5}{2}\)

    2^x                  = 16

    2^x                   = 2⁴

      x                   = 4

+) \(8^x=2^{111}\)

\(\Rightarrow\left(2^3\right)^x=2^{111}\)

\(\Rightarrow2^{3x}=2^{111}\)

\(\Rightarrow3x=111\)

\(\Rightarrow x=111:3\)

\(\Rightarrow x=37\)

Vậy x = 37

+) \(2^x+5\times2^x=48\)

\(\Rightarrow2^x\times\left(1+5\right)=48\)

\(\Rightarrow2^x\times6=48\)

\(\Rightarrow2^x=48:6\)

\(\Rightarrow2^x=8\)

\(\Rightarrow2^x=2^3\)

\(\Rightarrow x=3\)

Vậy x = 3

+) \(2^x+3\times2^{x-1}=40\)

\(\Rightarrow2^x+3\times2^x:2=40\)

\(\Rightarrow2^x+3\times2^x\times\frac{1}{2}=40\)

\(\Rightarrow2^x+2^x\times\left(3\times\frac{1}{2}\right)=40\)

\(\Rightarrow2^x+2^x\times\frac{3}{2}=40\)

\(\Rightarrow2^x\times\left(1+\frac{3}{2}\right)=40\)

\(\Rightarrow2^x\times\frac{5}{2}=40\)

\(\Rightarrow2^x=40:\frac{5}{2}\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

Vậy x = 4

_Chúc bạn học tốt_

a: =>x-8=27

hay x=35

3.(x-8) = 106-25

3.(x-8) = 81

x-8 = 81:3

x-8 = 27

x=35

\(a,25+3\left(x-8\right)=106\\ 3\left(x-8\right)=81\\ x-8=27\\ x=35\)

3² . (x + 4 ) - 5² = 5 . 2²

9  . ( x + 4 ) - 25 = 20

9 . ( x + 4 )        = 20 + 25

9 . ( x + 4 )        = 45

     ( x + 4 )       = 45 : 9

      x  + 4          = 5

      x                 = 5 - 4

      x                 = 1

Mn jup mk vs

3_² ((x + 4)-5)² = 5x2²

9 (( x + 4 ) - 5)² = 20

????

Không cho điều kiện của x sao làm đc bạn

\(3^{2\left(x+4\right)}-5^2=5.2^2\)

\(3^{2\left(x+4\right)}-25=5.4\)

\(3^2.3^{x+4}=45\)

\(3^{x+4}=9\)

\(3^{x+4}=3^2\)

\(\Rightarrow x+4=2\)

\(x=-2\)

Vay ....

Đề như này có vẻ hợp lí hơn:

\(2^x+4.2^x=5.2^5\)

\(\Leftrightarrow2^x\left(1+4\right)=5.2^5\)

\(\Leftrightarrow5.2^x=5.2^5\)

\(\Leftrightarrow x=5\)