\(x+x\times\frac{1}{4}:\frac{2}{7}+x:\frac{2}{9}=255\)

\(\Rightarrow x+x\times\frac{1}{4}\times\frac{7}{2}+x\times\frac{9}{2}=255\)

\(\Rightarrow x+x\times\frac{7}{8}+x\times\frac{9}{2}=255\)

\(\Rightarrow x\times\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)

\(\Rightarrow x\times\left(\frac{8}{8}+\frac{7}{8}+\frac{36}{8}\right)=255\)

\(\Rightarrow x\times\frac{51}{8}=255\)

\(\Rightarrow x=255:\frac{51}{8}\)

\(\Rightarrow x=40\)

Vậy \(x=40\)

~ Ủng hộ nhé 

Tìm  X  nha!

\(x+x\times\frac{1}{4}:\frac{2}{7}+x:\frac{2}{9}=255\)

\(x+x\times\frac{1}{4}\times\frac{7}{2}+x\times\frac{9}{2}=255\)

\(x\times\left(1+\frac{1}{4}\times\frac{7}{2}+\frac{9}{2}\right)=255\)

\(x\times\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)

\(x\times\frac{51}{8}=255\)

\(x=255:\frac{51}{8}=40\)

Vậy x = 40

`9/2xx7/3-4/3xx9/2`

`=9/2xx(7/3-4/3)`

`=9/2xx3/3`

`=9/2xx1`

`=9/2`

\(x+x\times\dfrac{1}{4}:\dfrac{2}{7}+x:\dfrac{2}{9}=255\)

\(x+x\times\dfrac{7}{8}+x\times\dfrac{9}{2}=255\)

\(x\times\left(1+\dfrac{7}{8}+\dfrac{9}{2}\right)=255\)

\(x\times\dfrac{51}{8}=255\)

\(x=255:\dfrac{51}{8}\)

\(x=255\times\dfrac{8}{51}\)

\(x=40\)

\(x+x\times\dfrac{1}{4}:\dfrac{2}{7}+x:\dfrac{2}{9}=255\)

\(x+x\times\dfrac{7}{8}+x\times\dfrac{9}{2}=255\)

\(x+\left(1+\dfrac{7}{8}+\dfrac{9}{2}\right)=255\)

\(x\times\dfrac{51}{8}=255\)

\(x=255:\dfrac{51}{8}\left(255\times\dfrac{8}{51}\right)\)

\(x=40\)

tk cho mk nhé

`!`

\(a,\dfrac{8}{9}\times\dfrac{7}{5}-\dfrac{7}{9}\times\dfrac{2}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\left(\dfrac{7}{5}-\dfrac{2}{5}\right)+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\dfrac{5}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}+\dfrac{2}{9}\\ =\dfrac{10}{9}\)

\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\\ =\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\\ =\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\\ =\dfrac{1}{4}\times\dfrac{9}{9}\\ =\dfrac{1}{4}\)

a: \(=\dfrac{4}{5}\cdot\dfrac{7}{3}\cdot\dfrac{3}{7}\cdot\dfrac{5}{4}+2011=2011+1=2012\)

b: \(=\dfrac{1}{3}\cdot\dfrac{9}{7}\cdot\dfrac{7}{9}=\dfrac{1}{3}\)

`a)4/5:3/7xx3/7:4/5+2011`

`=4/5xx7/3xx3/7xx5/4+2011`

`=(4/5xx5/4)xx(7/3xx3/7)+2011`

`=1xx1+2011`

`=1+2011`

`=2012`

__

`b)1/2xx2/3:7/9xx7/9`

`=1/2xx2/3xx9/7xx7/9`

`=(1/2xx2/3)xx(9/7xx7/9)`

`=1/3xx1`

`=1/3`

x + x * 1/4 : 2/7 + x : 2/9 = 255

x + x * 1/4 * 7/2 + x * 9/2 = 255

x + x * 7/8 + x * 9/2 = 255

x * ( 1 + 7/8 + 9/2 ) = 255

x * (8/8 + 7/8 + 36/8 ) = 255

x * 51/8 = 255

x = 255 : 51/8

x = 255* 8/51

x = 40

Chúc bạn học tốt!

x + x × 1/4 : 2/7 + x : 2/9 = 255

x + x × 1/4 × 7/2 + x × 9/2 = 255

x + x × 7/8 + x × 9/2 = 255

x × (1 + 7/8 + 9/2) = 255

x × (8/8 + 7/8 + 36/8) = 255

x × 51/8 = 255

x = 255 : 51/8

x = 255 × 8/51

x = 40

x + x * 1/4 : 2/7 + x : 2/9 = 255

x + x * 1/4 * 7/2 + x * 9/2 = 255

x + x * 7/8 + x * 9/2 = 255

x * ( 1 + 7/8 + 9/2 ) = 255

x * (8/8 + 7/8 + 36/8 ) = 255

x * 51/8 = 255

x = 255 : 51/8

x = 255* 8/51

x = 40

x + x × 1/4 : 2/7 + x : 2/9 = 255

x + x × 1/4 × 7/2 + x × 9/2 = 255

x + x × 7/8 + x × 9/2 = 255

x × (1 + 7/8 + 9/2) = 255

x × (8/8 + 7/8 + 36/8) = 255

x × 51/8 = 255

x = 255 : 51/8

x = 255 × 8/51

x = 40

x + x × 1/4 : 2/7 + x : 2/9 = 255

x + x × 1/4 × 7/2 + x × 9/2 = 255

x + x × 7/8 + x × 9/2 = 255

x × (1 + 7/8 + 9/2) = 255

x × (8/8 + 7/8 + 36/8) = 255

x × 51/8 = 255

x = 255 : 51/8

x = 255 × 8/51

x = 40

Vậy x = 40

40

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