a) x + 4 = – 14 – 9

x + 4 = – 23

x = – 23 – 4

x = – 27

b) 3x = – 14 + 2

3x = – 12

x = – 12 : 3

x = – 4

c) 2| x | = 4 – (– 8)

2| x | = 12

| x | = 6

x = 6 hoặc x = – 6

d) |x – 2| = 7

x – 2 = 7 hoặc x – 2 = – 7

x = 9 hoặc x = – 5

b) 3x = – 14 + 2

3x = – 12

x = – 12 : 3

x = – 4

5 ( x - 1 ) - 7 ( x - 2 ) = 2x - 39

<=> 5x - 5 - 7x + 14 = 2x - 39

<=> 5x - 7x - 2x = -39 + 5 - 14

<=> -4x = -48

<=> x = 12

x - 3 - 14.( x-2 )= -3x -3\(\Rightarrow\chi-3-28-14\chi-28=-3\chi-3\)

\(\Rightarrow\chi-3-28+3=-3\chi-3\)

\(\Rightarrow\chi-28=11\chi\)

\(\Rightarrow\chi-11\chi=28\)

\(\Rightarrow10\chi=28\Rightarrow\chi=2,8\left(kot.m\chi\inℤ\right)\) 

HTDT-sai-rùi

x-3-14(x-2)=-3x-3

x-3+28-14x=-3x-3

-13x+35=-3x-3

-13x+3x=-3-35

-10x=-38

x=38/10=19/5

(x + 3)(x² - 3x + 9) - x(x - 1)(x + 1) = 14

<=> x³ + 27 - x(x² - 1) = 14

<=> x³ + 27 - x³ + x = 14

<=> x³ - x³ + x = 14 - 27

<=> x = -13

\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)=14\)

\(\Leftrightarrow x^3+27-x^3+x=14\)

hay x=-13

(x + 3)(x² - 3x + 9) - x(x - 1)(x + 1) = 14

=> x³ + 27 - x(x² - 1) = 14

=> x³ + 27 - x³ + x = 14

=>  x = 14 - 27

=> x = -13

a)  3x – 15 = 25 – 5x 

=> 3x + 5x = 25 + 15

=> 8x = 40

=> x = 5

 b) 3x - 17 = 2x – 7     

=> 3x - 2x = -7 + 17

=> x = 10

 c) 2x – 17 =  – (3x – 18)

=> 2x - 17 = -3x + 18

=> 2x + 3x = 18 + 17

=> 5x = 35

=> x = 7

d) 3x – 14 = 2(x – 9) + 1

=> 3x - 14 = 2x - 18 + 1

=> 3x - 2x = -18 + 1 + 14

=> x = -3

f) (x – 5)² = 9          

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

a) Ta có: \(3x-15=25-5x\)

\(\Leftrightarrow3x-15-25+5x=0\)

\(\Leftrightarrow8x-40=0\)

\(\Leftrightarrow8x=40\)

hay x=5

Vậy: x=5

b) Ta có: \(3x-17=2x-7\)

\(\Leftrightarrow3x-17-2x+7=0\)

\(\Leftrightarrow x-10=0\)

hay x=10

Vậy: x=10

c) Ta có: \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=-3x+18\)

\(\Leftrightarrow2x-17+3x-18=0\)

\(\Leftrightarrow5x-35=0\)

\(\Leftrightarrow5x=35\)

hay x=7

Vậy: x=7

d) Ta có: \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14-2x+18-1=0\)

\(\Leftrightarrow x+3=0\)

\(\Leftrightarrow x=-3\)

Vậy: x=-3

f) Ta có: \(\left(x-5\right)^2=9\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy: \(x\in\left\{2;8\right\}\)

Bài 2. Tìm x, biết :                                

a) \(3x-15=25-5x\)

\(\Leftrightarrow8x=40\)

\(\Leftrightarrow x=5\)

Vậy x = 5

b) \(3x-17=2x-7\)

\(\Leftrightarrow x=10\)

Vậy x = 10

c) \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=18-3x\)

\(\Leftrightarrow5x=35\)

\(\Leftrightarrow x=7\)

Vậy x = 7

d) \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14=2x-17\)

\(\Leftrightarrow x=-3\)

Vậy x = -3

e) \(\left(x-5\right)^2=9\)

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy x = {8; 2}

5x+3x -2=14

x.(5+3)-2=14

x.8 -2 =14

x.8=14+2

x.8=16

x=16:8

x=2

Đúng nhé! Chúc bạn học giỏi

Tìm x thuộc N , biết : 5x + 3x - 2  = 14

Giải

5x + 3x - 2 = 14

=> 8x - 2 = 14

=> 8x = 16 

=> x = 2

a: =>10|x-2|=50

=>|x-2|=5

=>x-2=5 hoặc x-2=-5

=>x=7 hoặc x=-3

b: =>|3x-12|+|5x-20|=56

=>8|x-4|=56

=>|x-4|=7

=>x-4=7 hoặc x-4=-7

=>x=11 hoặc x=-3

14 chia hết cho 3x+2

=> 3x+2 \(\in\)Ư(14)={1;2;7;14}

mà x là số tự nhiên nên

=> 3x+2 \(\in\){2;7;14}

=> 3x \(\in\){0;5;12} (lại loại 5 vì 5 không chia hết cho 3)

=> 3x \(\in\){0; 12}

+) TH1: 3x=0

=> x=0:3

=> x=0

+) TH2: 3x=12

=> x=12:3

=> x=4

Vậy x \(\in\){0; 4} thì 14 chia hết cho 3x+2.

ta có 14 = 3.4 +2 chia het cho 3x+2=>x=4

\(\frac{3x}{2.5}+\frac{3x}{5.8}+\frac{3x}{8.11}+\frac{3x}{11.14}=\frac{1}{21}\)

=> \(x\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}\right)=\frac{1}{21}\)

=> \(x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\right)=\frac{1}{21}\)

=> \(x\left(\frac{1}{2}-\frac{1}{14}\right)=\frac{1}{21}\)

=> \(x.\frac{3}{7}=21\)

=> x = 49 

Vậy x = 49

Xin lỗi bạn nhé x = 1/9 bước cuối mình ghi sót 

sai rồi bạn ơi