Part 1

1 on

2 as

3 who

4 so

5 well

6 didn't

Part 2

1 - G

2 - A

3 - F

4 - B

5 - C

6 - D

Part 3 

1 have walked

2 learnt

3 watches

4 playing

5 be done

6 impressed

7 surprisingly

8 cosumption

Part4

1 reduce => reduces

2 whom => who

part 1

1 ON

2WHOM

3 WHO

4 SO

5 WELL

6 DIDM'T

part 3

1 walk

2 learnt

3 playing

4 impressive

5 suprising

\(2.a.Magie+Axitclohidric\rightarrow MagieClorua+Hidro\\ b.Mg+2HCl\rightarrow MgCl_2+H_2\\ c.m_{Mg}+m_{HCl}=m_{MgCl_2}+m_{H_2}\\ d.m_{HCl}=m_{MgCl_2}+m_{H_2}-m_{Mg}=47,5+1-12=36,5\left(g\right)\)

\(1.a.2Mg+O_2-^{t^o}\rightarrow2MgO\\ b.Fe+2AgNO_3\rightarrow Fe\left(NO_3\right)_2+2Ag\\ c.C_2H_4+3O_2-^{t^o}\rightarrow2CO_2+2H_2O\\ d.CuO+2HCl\rightarrow CuCl_2+H_2O\\ e.2Na+2H_2O\rightarrow2NaOH+H_2\\ f.4Al+3O_2-^{t^o}\rightarrow2Al_2O_3\)

\(F_A=P-F=18-10=8N\)

\(V=\dfrac{F_A}{d}=\dfrac{8}{10000}=8\cdot10^{-4}m^3\)

\(d=\dfrac{18}{8\cdot10^{-4}}=22500\)N/m³

\(F_A=P-P'=18-10=8N\)

\(V=\dfrac{F_A}{d}=\dfrac{8}{10000}=8\cdot10^{-4}m^3\)

\(d=\dfrac{P}{V}=\dfrac{18}{8\cdot10^{-4}}=22500\left(\dfrac{N}{m^2}\right)\)

1. a

2. b

3. b

4. b

5. b

6. d

7. c

8. b

9. b

10. a

11. c

12. d

13. b

14. b

15. c

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\(BC=AC-AB=60\left(km\right)\\ \Rightarrow\%_{\dfrac{s_{BC}}{s_{AB}}}=\dfrac{60}{80}\times100\%=75\%\)

B

A

A

A

B 

7. B

9. A

11. A