Tìm x, biết:
\(\left(8x-1\right)^{2x+1}=5^{2x+1}\)
Những câu hỏi liên quan
Tìm x biết: \(2x.\left(8x-1\right)^2.\left(4x-1\right)=9\)
Ta có: \(2x\left(8x-1\right)^2\cdot\left(4x-1\right)=9\)
\(\Leftrightarrow\left(8x-1\right)^2\cdot\left(8x^2-2x\right)=9\)
\(\Leftrightarrow\left(64x^2-16x+1\right)\left(8x^2-2x\right)-9=0\)
\(\Leftrightarrow512x^4-128x^3-128x^3+32x^2+8x^2-2x-9=0\)
\(\Leftrightarrow512x^4-256x^3+40x^2-2x-9=0\)
\(\Leftrightarrow256x^3\left(2x-1\right)+40x^2-20x+18x-9=0\)
\(\Leftrightarrow256x^3\left(2x-1\right)+20x\left(2x-1\right)+9\left(2x-1\right)=0\)
\(\Leftrightarrow\left(2x-1\right)\left(256x^3+20x+9\right)=0\)
\(\Leftrightarrow\left(2x-1\right)\left(256x^3+64x^2-64x^2-16x+36x+9\right)=0\)
\(\Leftrightarrow\left(2x-1\right)\left[64x^2\left(4x+1\right)-4x\left(4x+1\right)+9\left(4x+1\right)\right]=0\)
\(\Leftrightarrow\left(2x-1\right)\left(4x+1\right)\left(64x^2-4x+9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\4x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=1\\4x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{1}{4}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{1}{2};-\dfrac{1}{4}\right\}\)
Đúng 2
Bình luận (0)
Thực hiện phép tính:
a) \(2x.\left(2x^2+3x-1\right)\)
b) \(\left(x+5\right).\left(2x-3\right)\)
c) \(\left(x+1\right)^2-x\left(2+3x\right)\)
d) \(\left(2x^3+x^2-8x+3\right):\left(2x-3\right)\)
b: \(=2x^2-3x+10x-15=2x^2+7x-15\)
Đúng 0
Bình luận (0)
Tìm x biết:
\(a.\left(x+1\right)\left(x^2-x+1\right)-x\left(x^2-5\right)=71\)
\(b.\left(2x-3\right)^3-8x\left(x-1\right)^2+4x\left(4x+1\right)+27=0\)
Giải các phương trình sau:
f. 5 – (x – 6) = 4(3 – 2x)
g. 7 – (2x + 4) = – (x + 4)
h. \(2x\left(x+2\right)^2-8x^2=2\left(x-2\right)\left(x^2+2x+4\right)\)
i. \(\left(x-2^3\right)+\left(3x-1\right)\left(3x+1\right)=\left(x+1\right)^3\)
k. (x + 1)(2x – 3) = (2x – 1)(x + 5)
f. 5 – (x – 6) = 4(3 – 2x)
<=>5-x+6=12-8x
<=>7x=1
<=>x=\(\dfrac{1}{7}\)
g. 7 – (2x + 4) = – (x + 4)
<=>7-2x-4=-x-4
<=>x=7
h. 2x(x+2)\(^2\)−8x\(^2\)=2(x−2)(x\(^2\)+2x+4)
<=>\(2x\left(x^2+4x+4\right)-8x^2=2\left(x^3-8\right)\)
<=>\(2x^3+8x^2+8x-8x^2=2\left(x^3-8\right)\)
<=>\(2x^3+8x=2x^3-16\)
<=>\(8x=-16\)
<=>\(x=-2\)
i. (x−2\(^3\))+(3x−1)(3x+1)=(x+1)\(^3\)
<=>\(x-8+9x^2-1=x^3+3x^2+3x+1\)
<=>\(6x^2-2x-10=0\)
<=>\(3x^2-x-5=0\)
<=>\(\left[{}\begin{matrix}x=\dfrac{1+\sqrt{61}}{6}\\x=\dfrac{1-\sqrt{61}}{6}\end{matrix}\right.\)
k. (x + 1)(2x – 3) = (2x – 1)(x + 5)
<=>\(2x^2-x-3=2x^2+9x-5\)
<=>10x=2
<=>\(x=\dfrac{1}{5}\)
Đúng 1
Bình luận (0)
f. 5 – (x – 6) = 4(3 – 2x)
<=>5-x+6=12-8x
<=>7x=1
<=>x=\(\dfrac{1}{7}\)
g. 7 – (2x + 4) = – (x + 4)
<=>7-2x-4=-x-4
<=>x=7
h. \(2x\left(x+2\right)^2-8x^2=2\left(x-2\right)\left(x^2+2x+4\right)\)
<=>\(2x\left(x^2+4x+4\right)-8x^2=2\left(x^3-8\right)\)
<=>\(2x^3+8x^2+8x-8x^2=2x^3-16\)
<=>\(8x=-16\)
<=>x=-2
i.\(\left(x-2\right)^3+\left(3x-1\right)\left(3x+1\right)=\left(x+1\right)^3\)
<=>\(x^3-6x^2+12x+8+9x^2-1=x^3+3x^2+3x+1\)
<=>\(9x+6=0\)
<=>x=\(\dfrac{-2}{3}\)
k. (x + 1)(2x – 3) = (2x – 1)(x + 5)
<=>\(2x^2-x-3=2x^2+9x-5\)
<=>10x=2
<=>
Đúng 1
Bình luận (0)
Tìm x biết :
\(\sqrt{\left(2x-1\right)}^2=5\)
gợi ý:
\(\sqrt{\left(2x-1\right)}^2=\left|2x-1\right|\)
cần giải hai phương trình
2x-1=5
2x-1=-5
\(\Leftrightarrow\left|2x-1\right|=5\Leftrightarrow\left[{}\begin{matrix}2x-1=5\\1-2x=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Đúng 1
Bình luận (0)
Giải các phương trình sau:a)frac{left(9x-0.7right)}{4}-frac{left(5x-1.5right)}{7}frac{left(7x-1.1right)}{3}-frac{5left(0.4-2xright)}{6}b)frac{3x-1}{x-1}-frac{2x+5}{x+3}1-frac{4}{left(x-1right)left(x+3right)}c)frac{3}{4left(x-5right)}+frac{15}{50-2x^2}-frac{7}{6left(x+5right)}d)frac{8x^2}{3left(1-4xright)^2}frac{2x}{6x-3}-frac{1+8x}{4+8x}
Đọc tiếp
Giải các phương trình sau:
a)\(\frac{\left(9x-0.7\right)}{4}-\frac{\left(5x-1.5\right)}{7}=\frac{\left(7x-1.1\right)}{3}-\frac{5\left(0.4-2x\right)}{6}\)
b)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}=1-\frac{4}{\left(x-1\right)\left(x+3\right)}\)
c)\(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=-\frac{7}{6\left(x+5\right)}\)
d)\(\frac{8x^2}{3\left(1-4x\right)^2}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
Tìm x biết:
a) \(2x\left(5x-3\right)-\left(2x-1\right)\left(2x+1\right)-8x^2+6x\)
b) \(\left(x^2+2\right)\left(x-1\right)-\left(x-2\right)\left(x^2+2x+4\right)\)
Mastered Ultra Instinct đề là tìm x thế ko có vế phải à???
Đúng 0
Bình luận (0)
Tìm x, biết:
1)
\(5x\left(x-1\right)=\left(x-1\right)\)
2)
\(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)
3)
\(3x\left(3-2x\right)+6x\left(x-1\right)=15\)
4)
\(x\left(x-3\right)+x-3=0\)
1, \(5x\left(x-1\right)=x-1\Rightarrow5x\left(x-1\right)-\left(x-1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(5x-1\right)=0\Rightarrow\orbr{\begin{cases}x-1=0\\5x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}}\)
2, \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)
\(\Rightarrow24x^2-10x-24x^2+8x=30\) \(\Rightarrow-2x=30\Rightarrow x=-15\)
3, \(3x\left(3-2x\right)+6x\left(x-1\right)=15\) \(\Rightarrow9x-6x^2+6x^2-6x=15\Rightarrow3x=15\Rightarrow x=5\)
4, \(x\left(x-3\right)+x-3=0\Rightarrow\left(x-3\right)\left(x+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
Đúng 0
Bình luận (0)
Tìm x biết1) left(2x+3right)left(x-4right)+left(x-5right)left(x-2right)left(3x-5right)left(x-4right)2)left(8x-3right)left(3x+2right)-left(4x+7right)left(x+4right)left(2x+1right)left(5x+1right)-333)6xleft(3x+5right)-2xleft(9x-2right)+left(17-xright)left(x-1right)+xleft(x-18right)-17x^204)left(x-1right)left(x+2right)-left(x-3right)+5x-70Giúp mình nha. Camon nhiều
Đọc tiếp
Tìm x biết
1) \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
2)\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x+1\right)-33\)
3)\(6x\left(3x+5\right)-2x\left(9x-2\right)+\left(17-x\right)\left(x-1\right)+x\left(x-18\right)-17x^2=0\)
4)\(\left(x-1\right)\left(x+2\right)-\left(x-3\right)+5x-7=0\)
Giúp mình nha. Camon nhiều
