\(a,\frac{16}{2^n}=2\Rightarrow2^n=16:2\Rightarrow2^n=8\Rightarrow2^n=2^3\Rightarrow n=3\)

\(b,\frac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=81.\left(-27\right)\Rightarrow\left(-3\right)^n=-2187\Rightarrow3^n=3^7\Rightarrow n=7\)

\(c,8^n:2^n=4\Rightarrow4^n=4\Rightarrow n=1\)

\(a,\frac{16}{2^n}=2\)                                    \(b,\frac{\left(-3\right)^n}{81}=-27\)                                              \(c,8^n:2^n=4\)

\(\Rightarrow2^4=2^n.2\)                                 \(\Rightarrow\left(-3\right)^n=\left(-27\right).81\)                                \(\Rightarrow\left(8:2\right)^n=4\)

\(\Rightarrow4=n+1\)                                 \(\Rightarrow\left(-3\right)^n=\left(-3\right)^7\)                                        \(\Rightarrow4^n=4\)

\(\Rightarrow n=4-1=3\)                         \(\Rightarrow n=7\)                                                                \(\Rightarrow n=1\)

a) \(\frac{16}{2^n}=2\)

=> 16 = 2 . 2ⁿ 

=> 16 = 2ⁿ⁺¹

=> 2⁴ = 2ⁿ⁺¹

=> n + 1 = 4

=> n = 4 - 1

=> n = 3

Vậy n = 3

b) \(\frac{\left(-3\right)^n}{81}=-27\)

=> (-3)ⁿ = -27 . 81

=> (-3)ⁿ = (-3)³ . (-3)⁴

=> (-3)ⁿ = (-3)⁷

=> n = 7

Vậy n = 7

c) 8ⁿ : 2² =  bao nhiêu vậy ban?

Chuk bn hk tốt!

a)\(\frac{16}{2^n}=2\)

    \(\Rightarrow16:2=2^n\) 

         2ⁿ=8=2³

Vậy n=3

b)\(\frac{\left(-3\right)^n}{81}=-27\)

  \(\Rightarrow\)(-3)ⁿ=-27.81

      (-3)ⁿ=-2187=(-3)⁷

Vậy n=7

c)Mk ko hiểu bn ghi gì

a)\(\frac{16}{2^n}=2\)

\(\Rightarrow2^n=\frac{16}{2}=8=2^3\)

\(\Rightarrow n=3\)

b) \(\frac{\left(-3\right)^n}{81}=27\)

\(\Rightarrow\left(-3\right)^n=-27.81=-2187=\left(-3\right)^7\)

\(\Rightarrow n=7\)
c) thiếu đề

Bài 10:

a: 2x-3 là bội của x+1

=>\(2x-3⋮x+1\)

=>\(2x+2-5⋮x+1\)

=>\(-5⋮x+1\)

=>\(x+1\in\left\{1;-1;5;-5\right\}\)

=>\(x\in\left\{0;-2;4;-6\right\}\)

b: x-2 là ước của 3x-2

=>\(3x-2⋮x-2\)

=>\(3x-6+4⋮x-2\)

=>\(4⋮x-2\)

=>\(x-2\inƯ\left(4\right)\)

=>\(x-2\in\left\{1;-1;2;-2;4;-4\right\}\)

=>\(x\in\left\{3;1;4;0;6;-2\right\}\)

Bài 14:

a: \(4n-5⋮2n-1\)

=>\(4n-2-3⋮2n-1\)

=>\(-3⋮2n-1\)

=>\(2n-1\inƯ\left(-3\right)\)

=>\(2n-1\in\left\{1;-1;3;-3\right\}\)

=>\(2n\in\left\{2;0;4;-2\right\}\)

=>\(n\in\left\{1;0;2;-1\right\}\)

mà n>=0

nên \(n\in\left\{1;0;2\right\}\)

b: \(n^2+3n+1⋮n+1\)

=>\(n^2+n+2n+2-1⋮n+1\)

=>\(n\left(n+1\right)+2\left(n+1\right)-1⋮n+1\)

=>\(-1⋮n+1\)

=>\(n+1\in\left\{1;-1\right\}\)

=>\(n\in\left\{0;-2\right\}\)

mà n là số tự nhiên

nên n=0

Bài 16:

a: \(\left(x+5\right)\left(y-3\right)=15\)

=>\(\left(x+5\right)\left(y-3\right)=1\cdot15=15\cdot1=\left(-1\right)\cdot\left(-15\right)=\left(-15\right)\cdot\left(-1\right)=3\cdot5=5\cdot3=\left(-3\right)\cdot\left(-5\right)=\left(-5\right)\cdot\left(-3\right)\)

=>\(\left(x+5;y-3\right)\in\left\{\left(1;15\right);\left(15;1\right);\left(-1;-15\right);\left(-15;-1\right);\left(3;5\right);\left(5;3\right);\left(-3;-5\right);\left(-5;-3\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(-4;18\right);\left(10;4\right);\left(-6;-12\right);\left(-20;2\right);\left(-2;8\right);\left(0;6\right);\left(-8;-2\right);\left(-10;0\right)\right\}\)

mà (x,y) là cặp số tự nhiên

nên \(\left(x,y\right)\in\left\{\left(10;4\right);\left(0;6\right)\right\}\)

b: x là số tự nhiên

=>2x-1 lẻ và 2x-1>=-1

\(\left(2x-1\right)\left(y+2\right)=24\)

mà 2x-1>=-1 và 2x-1 lẻ

nên \(\left(2x-1\right)\cdot\left(y+2\right)=\left(-1\right)\cdot\left(-24\right)=1\cdot24=3\cdot8\)

=>\(\left(2x-1;y+2\right)\in\left\{\left(-1;-24\right);\left(1;24\right);\left(3;8\right)\right\}\)

=>\(\left(2x;y\right)\in\left\{\left(0;-26\right);\left(2;22\right);\left(4;6\right)\right\}\)

=>\(\left(x;y\right)\in\left\{\left(0;-26\right);\left(1;11\right);\left(2;6\right)\right\}\)

mà (x,y) là cặp số tự nhiên

nên \(\left(x,y\right)\in\left\{\left(1;11\right);\left(2;6\right)\right\}\)

c:

x,y là các số tự nhiên

=>x+3>=3 và y+2>=2

xy+2x+3y=0

=>\(xy+2x+3y+6=6\)

=>\(x\left(y+2\right)+3\left(y+2\right)=6\)

=>\(\left(x+3\right)\left(y+2\right)=6\)

mà x+3>=3 và y+2>=2

nên \(\left(x+3\right)\cdot\left(y+2\right)=3\cdot2\)

=>x=0 và y=0

d: xy+x+y=30

=>\(xy+x+y+1=31\)

=>\(x\left(y+1\right)+\left(y+1\right)=31\)

=>\(\left(x+1\right)\left(y+1\right)=31\)

\(\Leftrightarrow\left(x+1\right)\cdot\left(y+1\right)=1\cdot31=31\cdot1=\left(-1\right)\cdot\left(-31\right)=\left(-31\right)\cdot\left(-1\right)\)

=>\(\left(x+1;y+1\right)\in\left\{\left(1;31\right);\left(31;1\right);\left(-1;-31\right);\left(-31;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(0;30\right);\left(30;0\right);\left(-2;-32\right);\left(-32;-2\right)\right\}\)

mà (x,y) là cặp số tự nhiên

nên \(\left(x,y\right)\in\left\{\left(0;30\right);\left(30;0\right)\right\}\)

a, \(\frac{64}{2^n}=16\Leftrightarrow\frac{64}{2^n}=\frac{64}{4}\Leftrightarrow2^n=4\Leftrightarrow n=2\)

b, \(\left(\frac{1}{3}\right)^{2n-1}=\left(\frac{1}{3}\right)^3\Leftrightarrow2n-1=3\Leftrightarrow n=2\)

a)\(\frac{64}{2^n}=16\Leftrightarrow2^n.16=64\Leftrightarrow2^n=4\Leftrightarrow2^n=2^2\Leftrightarrow n=2\)

b)\(\left(\frac{1}{3}\right)^{2n-1}=\frac{1}{27}\)

\(\Leftrightarrow\left(\frac{1}{3}\right)^{2n-1}=\left(\frac{1}{3}\right)^3\)

\(\Leftrightarrow2n-1=3\Leftrightarrow2n=4\Leftrightarrow n=2\)

a) \(\frac{64}{2^n}=16\Leftrightarrow64=16.2^n\Leftrightarrow2^n=4\Leftrightarrow2^n=2^2\Leftrightarrow n=2\)

Vậy: \(n=2\)

b) \(\left(\frac{1}{3}\right)^{2n-1}=\frac{1}{27}\Leftrightarrow\left(\frac{1}{3}\right)^{2n-1}=\left(\frac{1}{3}\right)^3\Leftrightarrow2n-1=3\Leftrightarrow2n=4\Leftrightarrow n=2\)

Vậy: \(n=2\)

1.a.\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2=\frac{17}{12}.\left(\frac{1}{20}\right)^2=\frac{17}{12}.\frac{1}{400}=\frac{17}{4800}\)

b. \(2\div\left(\frac{1}{2}-\frac{2}{3}\right)^3=2\div\left(-\frac{1}{6}\right)^3=2\div\left(-\frac{1}{216}\right)=2.\left(-216\right)=-432\)

2.a.\(\frac{16}{2^n}=2\Rightarrow2^n=16:2=8=2^3\Rightarrow n=3\)

b.\(\frac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=-27.81=-2187=\left(-3\right)^7\Rightarrow n=7\)

c. \(8^n:2^n=4\Rightarrow\left(8:2\right)^n=4\Rightarrow4^n=4^1\Rightarrow n=1\)

a, \(\frac{16}{2^n}=2\Leftrightarrow16=2^n.2\Rightarrow2^4=2^{n+1}\Rightarrow n+1=4\Rightarrow n=3\)

b) \(\frac{\left(-3\right)^n}{81}=-27\Rightarrow\left(-3\right)^n=-27.81\Rightarrow\left(-3\right)^n=-3^3.3^4\Rightarrow\left(-3\right)^n=\left(-3\right)^7\Rightarrow n=7\)

c, \(8^n:2^n=4\Leftrightarrow2^{3n}:2^n=2^2\Leftrightarrow2^{2n}=2^2\Leftrightarrow2n=2\Rightarrow n=1\)

\(\frac{16}{2^n}=1;2^n=8;n=3\)

\(\frac{\left(-3\right)^n}{81}=-27;\left(-3\right)^n=\left(-3\right)^7;n=7\)

\(8^n:2^n=4;\left(8:2\right)^n=4;4^n=4=4^1;n=1\)

a, \(\frac{16}{2^n}=2\Leftrightarrow2\cdot2^n=16\Leftrightarrow2^{n+1}=2^4\Leftrightarrow n+1=4\Rightarrow n=3\)

b,\(\frac{\left(-3\right)^n}{81}=-27\Leftrightarrow\left(-3\right)^n=-3^3.3^4\Leftrightarrow\left(-3\right)^n=\left(-3\right)^7\Rightarrow n=7\)

c,\(8^n:2^n=4\Leftrightarrow\left(2^3\right)^n:2^n=2^2\Leftrightarrow2^{3n}:2^{2n}=2^2\Leftrightarrow2^{3n-2n}=2^2\Leftrightarrow2^n=2^2\Leftrightarrow n=2\)

câu 1.      \(\frac{16}{2^n}\)=2  =>2ⁿ=16x2=32

                    2ⁿ=2⁵    =>    n=5

câu 2.\(\frac{\left(-3\right)^n}{81}\)=-27=3³ =>(-3)ⁿ =81x3³

                                                                   =(-3)⁴x(-3)³

                                                                   =(-3)⁷

câu 3.  8ⁿ:4ⁿ=4=>(8:4)ⁿ=4

                          2ⁿ=4 =2²

                         =>n=2