a, (24 x 15 - 2x) - 1/4 = 400
b, 3200 : (8 + 3x) = 4
a) x/12=-1/24-1/8
b) 2/3x=1/2x+15/12
c) |3/4-2x|+1/6=9/2
Giúp em với ạ
a, \(\frac{x}{12}=-\frac{1}{24}-\frac{1}{8}\Leftrightarrow\frac{x}{12}=-\frac{1}{6}\Leftrightarrow6x=-12\Leftrightarrow x=-2\)
b, \(\frac{2}{3}x=\frac{1}{2}x+\frac{15}{12}\Leftrightarrow\frac{2x}{3}=\frac{x}{2}+\frac{15}{12}\Leftrightarrow\frac{4x}{6}-\frac{3x}{6}=\frac{15}{12}\Leftrightarrow\frac{x}{6}=\frac{15}{12}\Leftrightarrow x=\frac{15}{2}\)
c, \(\left|\frac{3}{4}-2x\right|+\frac{1}{6}=\frac{9}{2}\Leftrightarrow\left|\frac{3}{4}-2x\right|=\frac{13}{3}\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{3}{4}-2x=\frac{13}{3}\\\frac{3}{4}-2x=-\frac{13}{3}\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-\frac{43}{12}\\2x=\frac{61}{12}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-\frac{43}{24}\\x=\frac{61}{24}\end{cases}}}\)
a) x-12=-9+15
b)4x -12=400
c)2x -35=15
d)3x+17=2
e)-5/8=x/16
f)y/10=-4/8
a) x-12=-9+15
x-12=24
x=24+12
x=36
Vậy x=36
b)4x -12=400
4x=412
x=412:4
x=103
Vậy x=103
c)2x -35=15
2x=50
x=50:2
x=15
Vậy x=15
d)3x+17=2
3x=-15
x=(-15):3
x=-5
Vậy x=-5
e)\(\frac{-5}{8}=\frac{x}{16}\)
\(\Rightarrow\left(-5\right).16=8.x\)
\(\Rightarrow8x=-80\)
\(\Rightarrow x=-10\)
f)\(\frac{y}{10}=-\frac{4}{8}\)
\(\Rightarrow8y=\left(-4\right).10\)
\(\Rightarrow8y=-40\)
\(\Rightarrow y=-5\)
a) x - 12 = -9 + 15
=> x - 12 = 6
=> x = 6 + 12 = 18
b) 4x - 12 = 400
=> 4x = 400 + 12 = 412
=> x = 412 : 4 = 103
c) 2x - 35 = 15
=> 2x = 15 + 35 = 50
=> x = 50 : 2 = 25
d) 3x + 17 = 2
=> 3x = 2 - 17
=> 3x = -15
=> x = -15 : 3 = -5
e) \(\frac{-5}{8}=\frac{x}{16}\)
\(=>\frac{-10}{16}=\frac{x}{16}\)
=> x = -10
f) \(\frac{y}{10}=\frac{-4}{8}\)
\(=>\frac{y}{10}=\frac{-1}{2}\)
\(=>\frac{y}{10}=\frac{-5}{10}\)
=> y = -5
a) x - 12 = -9 + 15
x - 12 = 6
x = 12 + 6
x = 18
b) 4x - 12 = 400
4x = 412
x = 412 : 4
x = 103
c) 2x - 35 = 15
2x = 50
=> x = 25
d) 3x + 17 = 2
=> 3x = -15
=> x = -5
e) -5/8 = x/16
=> -10/16 = x/16
=> x = -10
y/10 = -4/8
=> y/10 = -40/80
=> y/10 = -5/10
=> y = -5
16 Tìm x, biết
a) 4(x+2)-7(2x-1)+9(3x-4)=30 ; b) 2(5x-8)-3(4x-5)=4(3x-4)+11
c) 5x(1-2x)-10(x+8)=0 ; d) (5x-3).4x-2x.(10x-3)=15
A. \(4\left(x+2\right)-7\left(2x-1\right)+9\left(3x-4\right)=30\)
\(\Leftrightarrow4x+8-14x+7+27x-36=30\)
\(\Leftrightarrow4x-14x+27x=30-8-7+36\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=3\) . Vậy \(S=\left\{3\right\}\)
B. \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow10x-12x-12x=16-15-16+11\)
\(\Leftrightarrow10x=-4\)
\(\Leftrightarrow x=-\dfrac{2}{5}\) . Vậy \(S=\left\{-\dfrac{2}{5}\right\}\)
Câu C) bạn xem lại đề nha mik tính ko đc
D. \(\left(5x-3\right)4x-2x\left(10x-3\right)=15\)
\(\Leftrightarrow20x^2-12x-20x^2+6x=15\)
\(\Leftrightarrow-6x=15\)
\(\Leftrightarrow x=-\dfrac{5}{2}\) . Vậy \(S=\left\{-\dfrac{5}{2}\right\}\)
Giai PT a, 6/x^2-1 + 5 = 8x-1/4x+4 - 12x-1/4-4x
b, 2x+1/2x-1 - 2x-1/2x+1 = 8/4x^2 -1
c, 3/2x-16 + 3x-20/x-8 + 1/8 = 13x-102/3x-24
d, x+4/x^2-3x+2 - x+1/x^2 -4x+3 = 2x+5/x^2-4x+3
Bài 2: Tính giá trị biểu thức
1/ (-25). ( -3). x với x = -4
2/ (-1). (-4) . 5 . 8 . y với y = 25
3/ (2ab 2 ) : (abc) với a = 4; b = -6; c = 12
4/ [(-25).(-27).(-x)] : y với x = -4; y = -9
5/ (a 2 - b 2 ) : (a + b) (a – b) với a = 5;b = -3
Bài 3: Tính tổng
1/ 1 + (-2) + 3 + (-4) + . . . + 19 + (-20)
2/ 1 – 2 + 3 – 4 + . . . + 99 – 100
3/ 2 – 4 + 6 – 8 + . . . + 48 – 50
4/ – 1 + 3 – 5 + 7 - . . . . - 97 + 99 5/ 1 + 2 – 3 – 4 + . . . . + 97 + 98 – 99 - 100
-2x + 3n . { 12- 2 [ 3x - ( 20+ 2x ) - 4x ] + 1= 45
3x - 32 >-5x + 1
15 + 4x < 2x - 145
-3 . ( 2x + 5 ) -16 < -4 . (3 - 2x )
-2x + 15 < 3x - 7 < 19 - x
+ ( x + 1 ) + ( x + 2) + ( x + 3) + .... + 13 + 14 = 14
25 + 24 + 23 +...+ x + ( x - 2 ) + ( x – 3 ) = 25
Giải các PT sau:
a,(5x-4)(4x+6)=0 b,(3,5x-7)(2,1x-6,3)=0
c,(4x-10)(24+5x)=0 d,(x-3)(2x+1)=0
e,(5x-10)(8-2x)=0 f,(9-3x)(15+3x)=0
a) ( 5x - 4)(4x + 6)=0
<=> \([^{5x-4=0}_{4x+6=0}< =>[^{x=\frac{4}{5}}_{x=\frac{-6}{4}}\)
Vậy S = \(\left\{\frac{4}{5};\frac{-6}{4}\right\}\)
b) ( 3,5x - 7 )( 2,1x - 6,3 ) = 0
<=> \([^{3,5x-7=0}_{2,1x-6,3=0}< =>[^{x=2}_{x=3}\)
Vậy S = \(\left\{2;3\right\}\)
c) ( 4x - 10 )( 24 + 5x ) = 0
<=> \([^{4x-10=0}_{24+5x=0}< =>[^{x=\frac{5}{2}}_{x=\frac{-24}{5}}\)
Vậy S = \(\left\{\frac{5}{2};\frac{-24}{5}\right\}\)
d) ( x - 3 )( 2x + 1 ) = 0
<=> \(\left[{}\begin{matrix}x-3=0\\2x+1=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=\frac{-1}{2}\end{matrix}\right.\)
Vậy S = \(\left\{3;\frac{-1}{2}\right\}\)
e) ( 5x - 10 )( 8 - 2x ) = 0
<=> \(\left[{}\begin{matrix}5x-10=0\\8-2x=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
Vậy S = \(\left\{2;4\right\}\)
f) ( 9 - 3x )( 15 + 3x ) = 0
<=> \(\left[{}\begin{matrix}9-3x=0\\15+3x=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy S = \(\left\{3;-5\right\}\)
Học tốt nhaaa !
Tìm x
a) 15 - 3 . (-6 ) - 2x = 4. ( -2 ) + 3x - 3^2
b ) -8 + 30 . ( x + 2 ) - 6 . ( x - 5 ) - 24 =10
Giúp mk !!!
15 - 3 . (-6) - 2x = 4 . (-2) + 3x - 32
<=> 15 + 18 - 2x = -8 + 3x - 9
<=> -2x - 3x = -15 - 18 - 8 - 9
<=> - 5x = -50
<=> x = 10
Vậy ...
b ) - 8 + 30(x+2)-6(x-5)-24 = 10
<=> - 8 + 30x + 60 - 6x + 30 - 24 = 10
<=> 30x - 6x = 8 - 60 - 30 + 24 + 10
<=> 24x = -48
<=> x = - 2
Vậy ...
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1
=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1
=> (15x - 8x) + (25 + 12) = 11x + 37
=> 7x + 37 = 11x + 37
=> 11x - 7x = 0
=> x = 0
Câu 2 : tìm x A, 7/8 + x = 3/5 B, 1/3 : ( 2x - 1 ) = -4/24 C, 17/2 - ( x - 3/4 ) = -7/4 D, ( 3x + 2 ) . ( -2/5x -7 ) = 0
a:x=3/5-7/8=24/40-35/40=-11/40
b: =>1/3:(2x-1)=-1/6
=>2x-1=-2
=>2x=-1
=>x=-1/2
c: =>x-3/4=17/2+7/4=34/4+7/4=41/4
=>x=11
d: =>3x+2=0 hoặc 2/5x+7=0
=>x=-2/3 hoặc x=-7:2/5=-35/2