a) \(\left(\frac{1}{2}\right)^x=\frac{1}{32}\)

\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)

=> x = 5 

cau b x o dau z bn

a)(1/2)^m=1/32

(1/2)^m=(1/2)⁵

=>m=5

a) \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)

\(\Rightarrow\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{2}\right)^3\)

\(\Rightarrow2n-1=3\)

\(\Rightarrow2n=4\)

\(\Rightarrow n=2\)

a) \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)

\(\Rightarrow2^{-\left(2n-1\right)}=2^{-3}\)

\(\Rightarrow2^{-2n+1}=2^{-3}\)

\(\Rightarrow-2n+1=-3\)

\(\Rightarrow-2n=-4\)

\(\Rightarrow n=-2\)

Vậy ...

b) \(\left(\dfrac{7}{5}\right)^n=\dfrac{343}{125}\)

\(\Rightarrow\left(\dfrac{7}{5}\right)^n=\left(\dfrac{7}{5}\right)^3\)

\(\Rightarrow n=3\)

Vậy ....

a. )\(\left(\dfrac{1}{2}\right)^{2n-1}\)=\(\dfrac{1}{8}\)

=> 2n-1=3

=>2n=3+1

=>2n=4

=>n=4:2=2

úp mik với sáng mai mik phải nộp rùi

Bài 10:
a)  (1/3)ⁿ = 1/81
=> (1/3)ⁿ = (1/3)⁴
=>     n   =    4

b)  -512/343 = (-8/7)ⁿ
=> (-8/7)³    = (-8/7)ⁿ
=>     3       =     n     (hay n = 3)

c)  (-3/4)ⁿ = 81/256
=> (-3/4)ⁿ = (-3/4)⁴
=>     n    =     4

d)  64/(-2)ⁿ = (-2)³
=> 64/(-2)ⁿ = -8
=>     (-2)ⁿ = -8
=>     (-2)ⁿ = (-2)³
=>        n  =   3

Bài 11: (không có y để tìm nhé)
a)  (0,4x - 1,3)² = 5,29
=> (0,4x - 1,3)² = (2,3)²
=>  0,4x - 1,3    =  2,3
=>  0,4x           = 3,6
=>       x           = 9

b)  (3/5 - 2/3x)³ = -64/125
=> (3/5 - 2/3x)³ = (-4/5)³
=>  3/5 - 2/3x   =  -4/5
=>          2/3x   = 7/5
=>              x    = 21/10

a) Ta có: \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

Mà \(\frac{1}{32}=\left(\frac{1}{2}\right)^5\)

\(\Rightarrow\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\Rightarrow m=5\)

b)Ta có:  \(\frac{343}{125}=\left(\frac{7}{5}\right)^3\)

Mà \(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\Rightarrow n=3\)

\(a)\) \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\frac{1^5}{2^5}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\)

\(\Leftrightarrow\)\(m=5\)

Vậy \(m=5\)

\(b)\) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\frac{7^3}{5^3}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(n=3\)

Vậy \(n=3\)

Chúc bạn học tốt ~ 

a, \(\frac{1}{2^m}=\frac{1}{32}\)

\(\Rightarrow\frac{1}{2^m}=\frac{1}{2^5}\)

\(\Rightarrow m=5\)

\(b,\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Rightarrow\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Rightarrow n=3\)

a) \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

\(=>\left(\frac{1}{2}\right)^m=\frac{1^5}{2^5}\)

\(=>\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\)

\(=>m=5\)

b) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(=>\frac{7^3}{5^3}=\left(\frac{7}{5}\right)^n\)

\(=>\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(=>n=3\)

a) \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

\(\Rightarrow\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\)

=> m =5

b) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Rightarrow\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

=> n = 3

\(\left(\frac{1}{2}\right)^M\)=\(\frac{1}{32}\)

\(\left(\frac{1}{2}\right)^M=\left(\frac{1}{2}\right)^5\)

-->M=5

b) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

--> n=3

a) \(\left(\dfrac{1}{2}\right)^n=\dfrac{1}{32}\)

\(\Rightarrow\left(\dfrac{1}{2}\right)^n=\dfrac{1^5}{2^5}\)

\(\Rightarrow n=5\)

Vậy n = 5

c) \(\dfrac{1}{9}\cdot27=3^n\)

\(\Rightarrow3=3^n\)

\(\Rightarrow n=1\)

Vậy n = 1

d) \(3^{-2}\cdot3^4\cdot3^n=3^7\)

\(\Rightarrow3^2\cdot3^n=3^7\)

\(\Rightarrow3^n=3^5\)

\(\Rightarrow n=5\)

Vậy n = 5