\(=>x\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{10}{3}+1=\dfrac{13}{3}\)

\(=>x=\dfrac{13}{3}:\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{13}{3}:\dfrac{7}{6}=\dfrac{26}{7}\)

5/6x - 1 = 10/3

5/6x = 10/3 + 1 = 13/3

X = 13/3 : 5/6 = 26/5

\(\dfrac{1}{2}\times x+\dfrac{2}{3}\times x-1=3\dfrac{1}{3}\)

\(\Rightarrow x\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{10}{3}+1\)

\(\Rightarrow\dfrac{7}{6}x=\dfrac{13}{3}\)

\(\Rightarrow x=\dfrac{13}{3}:\dfrac{7}{6}\)

\(\Rightarrow x=\dfrac{26}{7}\)

`1/2x^2(-2x^2y^2z).(-1/3)x^2y^3`

`=1/2 .(-2).(-1/3)x^{2+2+2}.y^{2+3}.z`

`=1/3x^6y^5z`

Ta có: \(\dfrac{1}{2}x^2\cdot\left(-2x^2y^2z\right)\cdot\left(-\dfrac{1}{3}\right)x^2y^3\)

\(=\left(\dfrac{1}{2}\cdot2\cdot\dfrac{1}{3}\right)\cdot\left(x^2\cdot x^2\cdot x^2\right)\cdot\left(y^2\cdot y^3\right)\cdot z\)

\(=\dfrac{1}{3}x^6y^5z\)

Vô nghiệm

\(\dfrac{-3}{2}\times\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{5}\right):3\dfrac{2}{3}\\ =\dfrac{45}{128}+\left(-2\right)\times\dfrac{3}{11}\\ =\dfrac{45}{128}-\dfrac{6}{11}\\ =-\dfrac{273}{1408}\)

\(x^3-9x^2=x^3-9x^2+2x-3\)

⇔\(x^3-x^3-9x^2+9x^2-2x=-3\)

⇔\(-2x=-3\)

⇔\(x=\dfrac{3}{2}\)

`x^3 -9x^2 =x^3 -9x^2 +2x-3`

`=> x^3 -9x^2-x^3 +9x^2 -2x+3=0`

`=> (x^3-x^3) +(-9x^2+9x^2)-2x+3=0`

`=> -2x-3=0`

`=>-2x=-3`

`=>x=3/2`

5: \(\Leftrightarrow9\left(x^2-5x-4\right)=36\left(x+1\right)+8\left(x^2-10x\right)\)

\(\Leftrightarrow9x^2-45x-36-36x-36-8x^2+80x=0\)

\(\Leftrightarrow x^2-x-72=0\)

=>(x-9)(x+8)=0

=>x=9 hoặc x=-8

6: \(\Leftrightarrow x^2-9=9x-x^2-9+x\)

\(\Leftrightarrow2x^2-10x=0\)

=>2x(x-5)=0

=>x=0 hoặc x=5

5, <=> 9x^2 - 45x - 36 = 36x + 36 + 8x^2 - 80x 

<=> x^2 - x - 72 = 0 <=> x = 9 ; x = -8 

6, <=> x^2 - 9 = 9x - x^2 - 9 + x = 10x - x^2 - 9 

<=> 2x^2 - 10x = 0 <=> x = 0 ; x = 5 

7, <=> (x-1)^2 = (3x+3)^2 

<=> (x-1-3x-3)(x-1+3x+3) = 0

<=> (-2x-4)(4x+2) = 0 <=> x = -2;x=-1/2

8, = (x^2-10x-15)(x^2-10x+25)

\(\frac{2^5\cdot6^7}{8^5\cdot3^5}=\frac{2^5\cdot\left(2\cdot3\right)^7}{\left(2\cdot4\right)^5\cdot3^5}=\frac{2^5\cdot2^7\cdot3^7}{2^5\cdot4^5\cdot3^5}=\frac{2^7\cdot3}{4^5}\)

x; y tỉ lệ thuận với 2 và 5 nên :

\(\frac{x}{2}=\frac{y}{5}\)

\(\Rightarrow\frac{x-y}{2-5}=\frac{x}{2}=\frac{y}{5}\) mà x - y = 21

\(\Rightarrow\frac{21}{-3}=\frac{x}{2}=\frac{y}{5}\)

\(\Rightarrow-7=\frac{x}{2}=\frac{y}{5}\)

\(\Rightarrow\hept{\begin{cases}x=-7\cdot2=-14\\y=-7\cdot5=-35\end{cases}}\)

vậy_

x; y tỉ lệ nghịch với 2 và 5 nên :

2x = 5y

=> 2x/10 = 5y/10

=> x/5 = y/2 

=> x/5 = 2y/4

=> x + 2y/5 + 4 = x/5 = y/2        mà x + 2y = 54

=> 54/9 = x/5 = y/2

=> 6 = x/6 = y/2

=> x = 6*6 = 36; y = 6*2 = 12

vậy_