3x + 3x + 1 = 324

  (3 + 3 ). x = 324 - 1

            6x  = 323

              x  = 323 : 6

              x = \(\frac{323}{6}\)= \(53\frac{5}{6}\)

có 3x+3x+1=324

=>3x+3x=324-1

=>3x+3x=323

=>2.3x=323

=>6x=323

=>x=\(\frac{323}{6}\)

3x + 3x + 1 = 324

3x + 3x = 323

6x = 323

x = 323 : 6

x = 323

-(24-36) + 112= - 24 + 36 + 112 = 12 + 112 = 124

324 + [112 - (112 + 324) - 320] = 324 + 112 -112 - 324 - 320

= 112 - 112 - 324 - 324 + 320

=0 - 0 + 320

= 320

289 : 17 - 324 : 18 + 18 :3 = 5

ai đi qua xin để lại cho mình 1 k nhé!

Xin kết bạn cùng mình nhé!

Chúc các bạn học tốt!

Thankyouvery much!

289:17-324:18+18:3

=17-18+6

=-1+6

=5

nha

17 - 18 + 6 = 5 

3^x+3^x+1=324

->3^x+3^x.3=324

->3^x.(1+3)=324

->3^x.4=324

->3^x=324:4=81=3⁴

->x=4

Vậy x=4

Chúc bạn học tốt! ^^

mk ko biết

mk nhanh nhất đó, có đc k ko???

bruh

no

324+[112−(112+324)]=324+(112−112−324)=324+112−112−324=0

\(\left(3x-4\right)\left(3x+4\right)+\left(x-5\right)\left(x-3\right)=10x^2+3\)

\(\Leftrightarrow9x^2-16+x^2-8x+15-10x^2-3=0\)

\(\Leftrightarrow-8x=4\)

hay \(x=-\dfrac{1}{2}\)

=>(3x-16)=2*7=14

=>3x=30

=>x=10

\(\left(3x-2^4\right).7^3=2.7^4\)

\(\left(3x-2^4\right)=2.7^4\div7^3\)

\(3x-2^4=2.7\)

\(3x-2^4=14\)

\(3x=14+2^4\)

\(3x=30\)

`=>` \(x=30\div3\)

`=> x=10`

(3x-2) (9x+6x+4)-(3x-1) (9x+3x+1)=x-4

(3x - 2)(15x + 4) - (3x - 1)(12x + 1) = x - 4

<=> 45x² + 12x - 30x - 8 - (36x² + 3x - 12x - 1) - x + 4 = 0

<=> 9x² - 10x - 3 = 0

<=> (3x - \(\frac{5}{3}\))² = \(\frac{52}{9}\) => \(\orbr{\begin{cases}3x-\frac{5}{3}=\frac{2\sqrt{13}}{3}\\3x-\frac{5}{3}=-\frac{2\sqrt{13}}{3}\end{cases}}\) <=> \(\orbr{\begin{cases}x=\frac{5+2\sqrt{13}}{9}\\x=\frac{5-2\sqrt{13}}{9}\end{cases}}\)

Vậy ...