a: \(575-\left(2x+70\right)=445\)

=>\(2x+70=575-445=130\)

=>\(2x=130-70=60\)

=>x=60/2=30

b: \(575-2\left(x+70\right)=445\)

=>\(2\left(x+70\right)=575-445=130\)

=>x+70=130/2=65

=>x=65-70=-5

c: \(x^5=32\)

=>\(x^5=2^5\)

=>x=2

d: \(\left(3x-1\right)^3=8\)

=>\(\left(3x-1\right)^3=2^3\)

=>3x-1=2

=>3x=3

=>\(x=\dfrac{3}{3}=1\)

e: \(\left(x-2\right)^3=27\)

=>\(\left(x-2\right)^3=3^3\)

=>x-2=3

=>x=5

f: \(\left(2x-3\right)^2=9\)

=>\(\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)

g: \(2x+5=3^4:3^2\)

=>\(2x+5=3^2\)

=>2x+5=9

=>2x=9-5=4

=>x=4/2=2

h: \(\left(4x-5^2\right)\cdot7^3=7^4\)

=>\(4x-25=\dfrac{7^4}{7^3}=7\)

=>4x=25+7=32

=>\(x=\dfrac{32}{4}=8\)

\(7^5:7^3-x=23\)

\(7^2-x=23\)

\(49-x=23\)

\(x=49-23\)

\(x=26\)

\(\left(2x-7\right).5^8=5^{10}\)

\(\left(2x-7\right)=5^{10}:5^8\)

\(2x-7=5^{10-8}\)

\(2x-7=5^2\)

\(2x-7=25\)

\(2x=32\)

\(x=32:2\)

\(x=16\)

* Mình nghĩ câu a sửa đề như vậy sẽ đúng hơn!

\(\left(2x+5\right).\left|-7\right|=73\)

\(\left(2x+5\right).7=73\)

\(\left(2x+5\right)=\frac{73}{7}\)

\(2x=\frac{73}{7}-5=\frac{38}{7}\)

\(x=\frac{38}{7}:2=\frac{19}{7}\)

  (2x+5).7=73

<=>2x.7+5.7=73

<=>14x+35=73

<=>14x=73-35

<=>14x=38

<=>x=38:14

=>x= 17/7

(2x+5) . l-7l = 73

=(2x+5) . 7 =73

=(2x+5)     =\(\frac{73}{7}\) 

=2x          =\(\frac{73}{7}\) - 5

=2x          =\(\frac{38}{7}\) 

=x           =\(\frac{38}{7}\) :2

=x           =\(\frac{19}{7}\)

(2x+5).|-7|=73

=> (2x+5).7=73

=> 2x+5=73:7

=> 2x+5=\(\frac{73}{7}\)

=>2x=\(\frac{73}{7}\)-5

=>2x=\(\frac{38}{7}\)

=>x=\(\frac{38}{7}\):2

=>x=\(\frac{19}{7}\)

vậy.....

Cảm ơn các bạn nhé !

15: \(\Leftrightarrow3x-2=1\)

hay x=1