a) x = 74    

b) x = 5 

c) x = 3      

d) x = 14

d , ( x : 7 + 15 ) . 23 + 391 => Đề thiếu

e , ( 19 . x + 2 . 5² ) : 14 = ( 13 - 8 ) ² - 4²

=> ( 19 . x + 2 . 5² ) : 14 = 5² -  16

=> ( 19 . x + 2 . 5² ) : 14 = 25 - 16 = 9

=> 19 . x + 2 . 52 = 9 x 14 = 126

=> 19 . x + 2 . 25 = 126

=> 19 . x + 50 = 126

=> 19 . x = 126 - 50 = 76

=> x = 76 : 19 = 4

a, 230 + [ 2⁴ + ( x - 5 ) ] = 315 . 2020⁰

=> 230 + [16 + ( x - 5 ) ] = 315 . 1

=> 230 + [ ( 16 - 5 ) + x ) = 315

=> 11 + x = 315 - 230 = 85

=> x = 85 - 11 = 74

b, 707 : [ ( 2^x - 5 ) + 74 ] = 4² - 3²

=> 707 : [ ( 2^x - 5 ) + 74 ] = 16 - 9 = 7

=> ( 2^x - 5 ) + 74 = 707 : 7 = 101

=> 2^x - 5 = 101 - 74 = 27

=> 2^x = 27 + 5 = 32

=> 2^x = 2⁵

=> x = 5

a) (x – 45).27 = 0

=>   x -  45  =  0

=>  x  =  45

 b) 23.(42- x) = 23 

=>  42- x  =  1

=>   x  =  41

c. 3x – 5=7

=>  3x  =  12

=>  x  =  4

e. 15 – 5x=10

=>  5x  =  5

=>  x  =  1

con bà mày

quá ghê gớm

\(-\dfrac{15}{23}:\dfrac{22x}{7}=-\dfrac{14x}{11}:\left(13+\dfrac{4}{5}\right)\)

=>\(-\dfrac{15}{23}\cdot\dfrac{7}{22x}=\dfrac{-14x}{11}:\dfrac{69}{5}\)

=>\(-\dfrac{105}{23\cdot22x}=\dfrac{-70x}{11\cdot69}\)

=>\(\dfrac{-3}{2x}=\dfrac{-2x}{3}\)

=>\(4x^2=9\)

=>\(x^2=\dfrac{9}{4}\)

=>\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)