đưa thừa số vào trong dấu căn
a) \(\frac{x-y}{x}\times\sqrt{\frac{x}{x-y}}\) (x>0: x>y)
b) \(\frac{x+y}{x-y}\times\sqrt{\frac{x-y}{x+y}}\) (x>0: x.y)
c) \(\frac{^{x^2}}{x-5}\times\sqrt{\frac{x-5}{3x}}\) (x>5)
d) \(-2\sqrt{-a}\)
rút gọn:
a)\(\left(\frac{1}{2+2\sqrt{x}}+\frac{1}{2-2\sqrt{x}}-\frac{x^2+1}{1-x^2}\right)\times\left(1+\frac{1}{x}\right)\)
b)\(\left(\frac{2\sqrt{xy}}{x-y}+\frac{\sqrt{x}-\sqrt{y}}{2\sqrt{x}+\sqrt{y}}\right)\times\frac{2\sqrt{x}}{\sqrt{x}+\sqrt{y}}+\frac{\sqrt{y}}{\sqrt{y}-\sqrt{x}}\)
c)\(\left(\frac{x-1}{\sqrt{x}-1}+\frac{x\sqrt{x}-1}{1-x}\right)\div\frac{\left(\sqrt{x}-1\right)^2+\sqrt{x}}{\sqrt{x}+1}\)
a, dk \(x\ge0.x\ne1\)
\(\left(\frac{1+\sqrt{x}+1-\sqrt{x}}{2\left(1-x\right)}-\frac{x^2+1}{1-x^2}\right)\left(\frac{x+1}{x}\right)\)=\(\left(\frac{1}{1-x}-\frac{x^2+1}{1-x^2}\right)\left(\frac{x+1}{x}\right)\)
=\(\left(\frac{1+x-x^2-1}{1-x^2}\right)\left(\frac{x+1}{x}\right)=\frac{x\left(1-x\right)\left(x+1\right)}{x\left(1-x\right)\left(1+x\right)}=1\)
phan b,c ban tu lam not nhe dai lam mk ko lam dau mk co vc ban rui
Đưa thừa số vào trong dấu căn
a)\(-\frac{a}{b}\sqrt{\frac{b}{a}}\) (a>0, b>0)
b)\(\frac{1}{2x-1}\sqrt{5-20x-20x^2}\) (x>1/2)
c) (x - 5) \(\sqrt{\frac{3}{25-x^2}}\)
d) \(\frac{x}{x-y}\sqrt{\frac{x-y}{x}}\)
Cho biểu thức:
\(A=\left[\left(\frac{1}{\sqrt{x}}+\frac{1}{\sqrt{y}}\right)\times\frac{2}{\sqrt{x}+\sqrt{y}}+\frac{1}{\sqrt{x}}+\frac{1}{\sqrt{y}}\right]:\frac{\sqrt{x^3}+y\sqrt{x}+x\sqrt{y}+\sqrt{y^3}}{\sqrt{x^3y}+\sqrt{xy^3}}\) \(\left(x>0,y>0\right)\)
a, Rút gọn A
b, Biết xy=16. Tìm giá trị của x, y để A có GTNN
Đưa thừa số vào trong dấu căn:
a) \(-\frac{a}{b}\sqrt{\frac{b}{a}}\left(a>0,b>0\right)\)
b)\(\frac{1}{2x-1}\sqrt{5-20x+20x^2}\) (x> \(\frac{1}{2}\)
c) \(\left(x-5\right)\sqrt{\frac{3}{25-x^2}}\)
d) \(\frac{x}{x-y}\sqrt{\frac{x-y}{x}}\)
a)\(=-\sqrt{\left(\frac{a}{b}\right)^2\cdot\frac{b}{a}}\)
\(=-\sqrt{\frac{a^2}{b^2}\cdot\frac{b}{a}}\)
\(=-\sqrt{\frac{a}{b}}\)
b) \(=\sqrt{\left(\frac{1}{2x-1}\right)^2\cdot5\left(4x^2-4x+1\right)}\)
\(=\sqrt{\frac{5}{\left(2x-1\right)^2}\cdot\left(2x-1\right)^2}\)
\(=\sqrt{5}\)
c)\(=\sqrt{\left(x-5\right)^2\cdot\frac{-3}{\left(x-5\right)\left(x+5\right)}}\)
\(=\sqrt{\frac{-3\left(x-5\right)}{x+5}}\)
\(=\sqrt{\frac{15-3x}{x+5}}\)
Bài 3:
B= \(\left[\left(\frac{1}{\sqrt{x}}+\frac{1}{\sqrt{y}}\right)\times\frac{2}{\sqrt{x}+\sqrt{y}}+\frac{1}{x}+\frac{1}{y}\right]\div\frac{\sqrt{x}^3+y\sqrt{x}+x\sqrt{y}+\sqrt{y}^3}{\sqrt{x^3y}+\sqrt{xy^3}}\)
a)Tìm ĐKXĐ
b)Rút gọn
c)Tìm x,y để B min
Đưa thừa số vào trong dấu căn: \(\frac{x}{x-y}\sqrt{\frac{x-y}{x}}\)
\(=\sqrt{\left(\frac{x}{x-y}\right)^2\cdot\frac{x-y}{x}}\)
\(=\sqrt{\frac{x^2}{\left(x-y\right)^2}\cdot\frac{x-y}{x}}\)
\(=\sqrt{\frac{x}{x-y}}\)
Cho A=\(\frac{\left(\sqrt{x}+\sqrt{y}\right)^2}{x\sqrt{x}+y\sqrt{y}}\times\left(\frac{x-y}{\sqrt{x}-\sqrt{y}}-\frac{x\sqrt{x}-y\sqrt{y}}{x-y}\right)\)
a)Rút gọn A
b)So sánh A và \(\sqrt{A}\)
Bài 1 :Tinh giá trị của các biểu thức sau :( lấy 05 chữ số thập phân sau dấu phẩy)
a) Tìm x số thực thỏa mãn:
\(\frac{x}{2+\frac{x}{2+\frac{x}{2+\frac{x}{\sqrt{1+x}+1}}}}=2012\)
b)\(P=\frac{1}{1+\sqrt{5}}+\frac{1}{\sqrt{5}+\sqrt{9}}+\frac{1}{\sqrt{9}+\sqrt{13}}+...+\frac{1}{\sqrt{2001}+\sqrt{2005}}\)
c)\(C=\frac{\sqrt{x^3}}{\sqrt{xy}-2y}-\frac{2x}{x+\sqrt{x}-2\sqrt{xy}-2\sqrt{y}}\times\frac{1-x}{\left(1-\sqrt{x}\right)\sqrt{y}}\)khi\(x=2,47839;y=\sqrt{7-4\sqrt{3}}\)
chứng minh đẳng thức sau
\(\frac{\left(x\sqrt{y}+y\sqrt{x}\right)\times\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}=x-y\)với x>0 và y>0
ta có:\(\frac{\left(x\sqrt{y}+y\sqrt{x}\right)\cdot\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}=\frac{\sqrt{xy}\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}=x-y\)
vậy.....
\(\frac{\left(x\sqrt{y}+y\sqrt{x}\right).\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}\)
\(=\frac{\sqrt{xy}.\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}\)
\(=\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)\)
\(=x-y\)( đpcm )