x³+13x²+7x-5

= x³+x²+12x²+12x-5x-5

=(x³+12x²-5x)+(x²+12x-5)

=x(x²+12x-5)+1(x²+12x-5)

=(x+1)(x²+12x-5)

phân tích đa thức thành nhân tử:

x³+13x²+7x-5

= x³+x²+12x²+12x-5x-5

=(x³+12x²-5x)+(x²+12x-5)

=x(x²+12x-5)+1(x²+12x-5)

=(x+1)(x²+12x-5)

Ai trên 10 điểm hỏi đáp thì mình nha mình đang cần gấp chỉ còn 99 điểm là tròn rồi mong các bạn hỗ trợ mình sẽ đền bù xứng đáng

tích nha 

tk cho nk

trần hoàng viêt nha , mk sẽ tk lại

a) Ta có : 6x² - 13x + 6 = 6x² - 9x - 4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3)

b) Ta có: 6x² + 7x - 3 = 6x² + 9x - 2x - 3 = 3x(2x + 3) - (2x + 3) = (3x - 1)(2x + 3)

\(a,6x^2-13x+6\)

\(=6x^2-9x-4x+6\)

\(=3x\cdot\left(2x-3\right)-x\cdot\left(2x-3\right)\)

\(=\left(2x-3\right)\cdot\left(3x-x\right)\)

\(=\left(2x-3\right)\cdot2x\)

\(b,6x^2+7x-3\)

\(=6x^2-2x+9x-3\)

\(=2x\cdot\left(3x-1\right)+3\cdot\left(3x-1\right)\)

\(=\left(3x-1\right)\cdot\left(2x+3\right)\)

\(a,6x^2-13x+6=6x^2-9x-4x+6\)

\(=3x\left(2x-3\right)-2\left(2x-3\right)=\left(2x-3\right)\left(3x-2\right)\)

\(b,6x^2+7x-3=6x^2-2x+9x-3\)

\(=2x\left(3x-1\right)+3\left(3x-1\right)=\left(3x-1\right)\left(2x+3\right)\)

\(=2x^4-6x^3-x^3+3x^2-5x^2+15x-2x+6\)

\(=2x^3\left(x-3\right)-x^2\left(x-3\right)-5x\left(x-3\right)-2\left(x-3\right)\)

\(=\left(x-3\right)\left(2x^3-x^2-5x-2\right)\)

\(=\left(x-3\right)\left(2x^3-4x^2+3x^2-6x+x-2\right)\)

\(=\left(x-3\right)\left[2x^2\left(x-2\right)+3x\left(x-2\right)+\left(x-2\right)\right]\)

\(=\left(x-3\right)\left(x-2\right)\left(2x^2+3x+1\right)\)

\(=\left(x-3\right)\left(x-2\right)\left(x+1\right)\left(2x+1\right)\)

=6x^2 - 4x - 9x +6

=(6x^2 -4x) - (9x-6)

=2x(3x -2) - 3(3x-2)

=(3x-2) (2x - 3)

\(4x^3-13x^2+9x-18=4x^3-12x^2-x^2+3x+6x-18\)

\(=4x^2.\left(x-3\right)-x\left(x-3\right)+3.\left(x-3\right)=\left(x-3\right)\left(4x^2-x+3\right)\)

\(4x^3-13x^2+9x-18\)

\(=4x^3-12x^2-x^2+3x+6x-18\)

\(=4x^2\left(x-3\right)-x\left(x-3\right)+6\left(x-3\right)\)

\(=\left(x-3\right)\left(4x^2-x+6\right)\)

a: Ta có: \(-3x^4+20x^3-35x^2-10x+48\)

\(=-\left(3x^4-20x^3+35x^2+10x-48\right)\)

\(=-\left(3x^4-9x^3-11x^3+33x^2+2x^2-6x+16x-48\right)\)

\(=-\left(x-3\right)\left(3x^3-11x^2+2x+16\right)\)

\(=-\left(x-3\right)\left(3x^3-6x^2-5x^2+10x-8x+16\right)\)

\(=-\left(x-3\right)\left(x-2\right)\left(3x^2-5x-8\right)\)

\(=-\left(x-3\right)\left(x-2\right)\left(3x-8\right)\left(x+1\right)\)

b: Ta có: \(-\left(2x^4+7x^3+x^2-7x-3\right)\)

\(=-\left(2x^4-2x^3+9x^3-9x^2+10x^2-10x+3x-3\right)\)

\(=-\left(x-1\right)\left(2x^3+9x^2+10x+3\right)\)

\(=-\left(x-1\right)\left(2x^3+2x^2+7x^2+7x+3x+3\right)\)

\(=-\left(x-1\right)\left(x+1\right)\left(2x^2+7x+3\right)\)

\(=-\left(x-1\right)\left(x+1\right)\cdot\left(x+3\right)\left(2x+1\right)\)

1) 6x^2 + 7x - 5 

=6x²-3x+10x-5

=3x.(2x-1)+5.(2x-1)

=(2x-1)(3x+5)

2) 10x^2 - 13x - 3

=10x²+2x-15x-3

=2x(5x+1)-3(5x+1)

=(5x+1)(2x-3)

\(6x^2+7x-5\)

\(=6x^2-3x+10x-5\)

\(=3x\left(2x-1\right)+5\left(2x-1\right)\)

\(=\left(2x-1\right)\left(3x+5\right)\)

1) x² -7x + 10 = x² - 2x - 5x + 10 = x(x - 2) - 5(x - 2) = (x - 5)(x - 2)

2) x² + 3x + 2 = x² + 2x + x  + 2 = x(x + 2) + (x + 2) = (x + 1)(x + 2)

3) x² - 7x + 12 = x² - 3x - 4x + 12 = x(x - 3) - 4(x - 3) = (x - 3)(x - 4)

4) x² + 7x + 12 = x² + 3x + 4x + 12 = x(x + 3) + 4(x + 3) = (x + 3)(x + 4)

5) 16x - 5x² - 3 = 15x - 5x² + x - 3 = -5x(x - 3) + (x - 3) = (x - 3)(1 - 5x) 

6) 6x² + 7x - 3 = 6x² - 2x + 9x - 3 = 2x(3x - 1) + 3(3x - 1) = (2x + 3)(3x - 1)  

7) 3x² - 3x - 6 = 3x² - 6x + 3x - 6 = 3x(x - 2) + 3(x - 2) = (x - 2)(3x + 3) = 3(x - 2)(x + 1)

8) 3x² + 3x - 6 = 3x² - 3x + 6x - 6 = 3x(x - 1) + 6(x - 1) = (x - 1)(3x + 6) = 3(x - 1)(x + 2)

9) 6x² - 13x + 6 = 6x² - 9x -  4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3) 

10) 6x² + 15x  + 6 = 6x² + 12x + 3x + 6 = 6x(x + 2) + 3(x + 2) = (x + 2)(6x + 3) = 3(x + 2)(3x + 1)

11) 6x² - 20x + 6 = 6x² - 18x - 2x + 6 = 6x(x -3) - 2(x - 3) = (6x - 2)(x - 3) = 2(3x - 1)(x - 3)

12) 8x² + 5x - 3 = 8x² + 8x - 3x - 3 = 8x(x + 1) - 3(x + 1) = (x + 1)(8x - 3)