(32−x÷5)÷13=2
Tìm x, biết
a) 21x = 63;
b) 32. |x| = 96;
c) 11x + 5 = 60;
d) 2 . |x| + 5 = 32 - 13.
a) x = 3.
b) x Î {-3; 3}.
c) x = 5.
d) x Î {-7; 7).
Tìm x, biết a) 21x = 63; b) 32. x = 96 c) 11x + 5 = 60 d) 2 . x + 5 = 32 - 13
tính nhanh
4/5-2/3/+1/5-1/3
2/5 x 7/4 - 2/5x3/7
13/4 x 2/3 x 4/13 x 3/12
75/100 + 18/21 + 19/32 +1/4 + 3/21 + 13/32
2/5 + 6/9+3/4+3/5+1/3+1/4
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a , =(4/5+1/5)-(2/3+1/3)=1-1=0
b , =2/5 x (7/4-3/7) =2/5 x 37/28 =74/140=37/70
c, =13/4 x 2/3 x 13/4 x 2/3=26/12 x 26/12= 13/6 x 13/6 =13 x 13/6 x 6(gạch 13 trên tử thì tử còn 1 x 13,mẫu hết.) =1 x 13/1=13
d, =3/4+6/7+19/32 +1/4+1/7 +13/32=(3/4+1/4 )+(6/7+1/7)+(19/32+13/32)=1+1+1=3
e, =(2/5+3/5)+(2/3+1/3)+(3/4+1/4) [6/9 rút gọn thành 2/3] =1+1+1=3
A=1+2+3+....+20
B=1+3+5+.....21
(2x-1) • 2 = 13
32•(x-10)=32
Tìm x
a)
Dãy trên có số số hạng là:
( 20 - 1 ) : 1 + 1 = 20 ( số hạng )
Tổng của dãy trên là:
( 20 + 1 ) x 20 : 2 = 210
Đáp số: 210
b)
Dãy trên có số số hạng là:
( 21 - 1 ) : 2 + 1 = 11 ( số hạng )
Tổng của dãy trên là:
( 21 + 1 ) x 11 : 2 = 121
Đáp số: 121
c) ( 2x - 1 ) x 2 = 13
2x - 1 = \(\dfrac{13}{2}\)
2x = \(\dfrac{15}{2}\)
\(x=\dfrac{15}{4}\)
32 x ( x - 10 ) = 32
( x - 10 ) = 1
x = 11
\(A=1+2+3+...+20\)
Số hạng:
\(\left(20-1\right):1+1=20\) (số hạng)
Tổng: \(\left(20+1\right)\cdot20:2=210\)
\(B=1+3+5+...+21\)
Số hạng:
\(\left(21-1\right):2+1=11\) (số hạng)
Tổng: \(\left(21+1\right)\cdot11:2=121\)
\(\left(2x-1\right)\cdot2=13\)
\(\Rightarrow2x-1=\dfrac{13}{2}\)
\(\Rightarrow2x=\dfrac{15}{2}\)
\(\Rightarrow x=\dfrac{15}{4}\)
\(32\cdot\left(x-10\right)=32\)
\(\Rightarrow x-10=1\)
\(\Rightarrow x=11\)
`a,` Khoảng cách là : `1`
Số số hạng là : \(\dfrac{20-1}{1}+1=20\)
Tổng là : \(\dfrac{20+1\times20}{2}=\)`210`
`b,` Khoảng cách là : `2`
Số số hạng là : \(\dfrac{21-1}{2}+1=11\)
Tổng là : \(\dfrac{21+1\times11}{2}=121\)
\(c,\left(2x-1\right).2=13\\ \Rightarrow2x-1=\dfrac{13}{2}\\ \Rightarrow2x=\dfrac{13}{2}+1\\ \Rightarrow2x=\dfrac{15}{2}\\ \Rightarrow x=\dfrac{15}{2}:2\\ \Rightarrow x=\dfrac{15}{4}\)
\(32.\left(x-10\right)=32\\ \Rightarrow x-10=32:32\\ \Rightarrow x-10=1\\ \Rightarrow x=1+10\\ \Rightarrow x=11\)
Tìm x biết 2.|x| + 5= 32 - 13
a)5-(13-3x)=109-(32+109)
b)/3x-6/+(x-2^2)=0
c)/7-2x/=-13-5.(-8)
a)5-(13-3x)=109-(32+109)
5-(13-3x)=-32
13-3x =37
3x =-24
3x =-6
a)5-(13-3x)=109-(32+109)
5-13+3x =109-32-109
-8+3x=-32
3x=-32-(-8)
3x=-24
x=-24:3
x=-8
b)|3x-6|+(x-22)=0
(3x-6)+(x-22)=0
3x-6+x-22=0
3x+x=0+6+22
4x=10
x=\(\dfrac{5}{2}\)
c)/7-2x/=-13-5.(-8)
|7-2x|=27
⇒7-2x=27 hoặc 7-2x=-27
x=-10 hoặc x=-17
5 x 3\(^n\) + 2 - 32 x 3\(^n\) = 13
Giups vơis
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Tìm x biết:
a, x – 27 = 5 × 9
b, x + 13 = 80 : 2
c, x × 4 = 32
d, x : 8 = 5
Tìm x
(5+4/7):x=13
(2,8.x+32):2/3=90
\(\left(5+\frac{4}{7}\right):x=13\)
\(\frac{39}{7}:x=13\)
\(x=\frac{39}{7}:13\)
\(x=\frac{3}{7}\)
\(\left[5+\frac{4}{7}\right]:x=13\)
\(\Rightarrow\left[\frac{5\cdot7+4}{7}\right]:x=13\)
\(\Rightarrow\frac{39}{7}:x=13\)
\(\Rightarrow x=\frac{39}{7}:13=\frac{39}{7}\cdot\frac{1}{13}=\frac{3}{7}\cdot\frac{1}{1}=\frac{3}{7}\)
\(\left[2,8\cdot x+32\right]:\frac{2}{3}=90\)
\(\Rightarrow\left[2,8\cdot x+32\right]=90\cdot\frac{2}{3}\)
\(\Rightarrow\left[2,8\cdot x+32\right]=60\)
\(\Rightarrow2,8\cdot x+32=60\)
\(\Rightarrow2,8\cdot x=60-32\)
\(\Rightarrow2,8\cdot x=28\)
Đến đây dễ rồi :v
\(\left(2,8.x+32\right):\frac{2}{3}=90\)
\(2,8.x+32=90.\frac{2}{3}\)
\(2,8.x+32=60\)
\(2,8.x=60-32\)
\(2,8.x=28\)
\(x=28:2,8\)
\(x=10\)