Đề mik chẳng hiểu tý gì luôn

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)

\(=\dfrac{4}{5}\)

utroi vt j z

Cảm ơn bạn nha

s bạn lại cảm ơn mik?

Nhiwf bạn nên mình làm được bài này ! Hihi 

tính vế trên trước: 2^12 x 3^5 - 4^6 x 9^2 = 4096 x 243 - 4096 x 81 = 4096 x ( 243 - 81 ) = 663552.

tính vế dưới sau : ( 2^2 x 3 )^6 + 8^4 x 3^5 = ( 4 x 3 )^6 + 4096 x 243 = 12^6 + 995328 = 2985984 + 995328 = 3981312.

Vậy được: 663552/3981312 = 1/6.

a,

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}-6^{11}}=\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{-2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{-2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{-2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=\dfrac{2^{13}\cdot3^{11}}{-2^{11}\cdot3^{11}\left(2\cdot3+1\right)}=\dfrac{2^2}{7}=\dfrac{4}{7}\)

b,

\(\dfrac{1}{1-\dfrac{1}{1-2-1}}+\dfrac{1}{1+\dfrac{1}{1+2-1}}=\dfrac{1}{1-\dfrac{1}{-2}}+\dfrac{1}{1+\dfrac{1}{2}}=\dfrac{1}{1+\dfrac{1}{2}}+\dfrac{1}{1+\dfrac{1}{2}}=\dfrac{2}{\dfrac{3}{2}}=\dfrac{4}{3}\)

\(\dfrac{4}{9}+x=\dfrac{11}{6}\)

\(x=\dfrac{11}{6}-\dfrac{4}{9}\)

\(x=\dfrac{99-24}{54}=\dfrac{75}{54}\)

a. x= 11/6 - 4/9

x= 25/18

a) x = 11/6 - 4/9

     x = 25/18

b) = 21/5 x 4/5

    = 84/25
 

M=4⁸:9⁸+6⁹x120/8⁴x3¹²-6¹¹

M=(2²)⁸:(3²)⁸+6⁹x2³x3x5/(2³)⁴x3¹²-6¹¹

M=2¹⁶:3¹⁶+6⁹x2³x3x5/2¹²x3¹²-6¹¹

M=(2¹⁹:3¹⁷+6⁹⁾x5 / 2¹²x3¹²-6¹¹

M=2⁷:3⁵x5/6²

M=128/243x5:36

M=640/243:36

M=160/2187