Tìm x
X+5=x(x+5)^2
X(x-2)=(x-2)
tìm x
x^3 -2x^2+x-2=0
2x(3x-5)=10-6x
4-x=2(x-4)^2
4-6x+x(3x-2)=0
\(x^3-2x^2+x-2=0\\ \Leftrightarrow x^2\left(x-2\right)+\left(x-2\right)=0\\ \Leftrightarrow\left(x^2+1\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2+1=0\\x-2=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(vô.lí\right)\\x=2\end{matrix}\right.\\ Vậy:x=2\\ ---\\ 2x\left(3x-5\right)=10-6x\\ \Leftrightarrow6x^2-10x-10+6x=0\\ \Leftrightarrow6x^2-4x-10=0\\ \Leftrightarrow6x^2+6x-10x-10=0\\ \Leftrightarrow6x\left(x+1\right)-10\left(x+1\right)=0\\ \Leftrightarrow\left(6x-10\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}6x-10=0\\x+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-1\end{matrix}\right.\)
\(4-x=2\left(x-4\right)^2\\ \Leftrightarrow4-x=2\left(x^2-8x+16\right)\\ \Leftrightarrow2x^2-16x+32+x-4=0\\ \Leftrightarrow2x^2-15x+28=0\\ \Leftrightarrow2x^2-8x-7x+28=0\\ \Leftrightarrow2x\left(x-4\right)-7\left(x-4\right)=0\\ \Leftrightarrow\left(2x-7\right)\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-7=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=4\end{matrix}\right.\\ ---\\ 4-6x+x\left(3x-2\right)=0\\ \Leftrightarrow4-6x+3x^2-2x=0\\ \Leftrightarrow3x^2-8x+4=0\\ \Leftrightarrow3x^2-6x-2x+4=0\\ \Leftrightarrow3x\left(x-2\right)-2\left(x-2\right)=0\\ \Leftrightarrow\left(3x-2\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}3x-2=0\\x-2=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=2\end{matrix}\right.\)
tìm x
x^2 (x - 5) + x - 5 = 0
\(x^2\left(x-5\right)+x-5=0\)
\(\Rightarrow x^2\left(x-5\right)+\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x^2-1\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-1=0\\x+1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=1\\x=-1\end{matrix}\right.\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Leftrightarrow x-5=0\)
hay x=5
BÀI 1cho biểu thức
P= (2√x+xx√x−1−1√x−1):(1−√x+2x+√x+1)(2x+xxx−1−1x−1):(1−x+2x+x+1)
a) Rút gọn P
b) tính √PP khi x=5+2√3
Bài 1 : Tìm X
X/-2 = -18/X
X/2 + X/5 = 17/10
Bài 2 : Tính ( tính nhanh nếu có thể )
2 mũ 5 . 9 - 2 mũ 6 / 32.5 + 25. 3 mũ 2
Bài 3 : Tìm số nguyên X biết :
5/21 + -3/7 < X/21 < -2/7 + 8/21
Giúp nhanh đang gấp ạ!!!
Bài 1:
a: x/-2=-18/x
=>x2=36
=>x=6 hoặc x=-6
b: x/2+x/5=17/10
=>7/10x=17/10
hay x=17/7
2 TÌM X
X- 9 = 21:5
X = ............................
X = ............................
X : 3 = 1,248 : 4
X = ..........................
X = ............................
X- 9 = 21:5
X- 9 = 4,2
x = 4,2 + 9
x = 13,2
X : 3 = 1,248 : 4
X : 3 = 0,312
x = 0,312 x 3
x = 0,936
x - 9 = 4,2
x = 4,2 + 9 =13,2
x : 3 = 0,312
x = 0,312 x 3 = 0,936
Tập nghiệm của bất phương trình 2 - x x - 5 > x - 2 x - 5
A. S = ∅
B. S = 2 ; + ∞
C. S = - ∞ ; 2
D. S = 5 ; + ∞
Giải hệ phương trình
Căn x+2(x-y+3)= căn yX^2+(xx+3)(2x-y+5)=x+16
1.tìm x
X x 6/7=5/14 X : 2/3=4/9
X-1/4=3/2 X+4/5=8/9
`x xx 6/7=5/14`
`=>x=5/14:6/7`
`=>x=5/14xx7/6`
`=>x=35/84`
`=>x=5/12`
Vậy `x=5/12`
__
`x:2/3=4/9`
`=>x=4/9xx2/3`
`=>x=8/27`
Vậy `x=8/27`
__
`x-1/4=3/2`
`=>x=3/2+1/4`
`=>x=6/4+1/4`
`=>x=7/4`
Vậy `x=7/4`
__
`x+4/5=8/9`
`=>x=8/9-4/5`
`=>x=40/45-36/45`
`=>x=4/45`
Vậy `x=4/45`
\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)
\(x\) \(=\dfrac{5}{14}:\dfrac{6}{7}\)
\(x\) \(=\dfrac{5}{12}\)
\(x:\dfrac{2}{3}=\dfrac{4}{9}\)
\(x\) \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)
\(x\) \(=\dfrac{8}{27}\)
\(x-\dfrac{1}{4}=\dfrac{3}{2}\)
\(x\) \(=\dfrac{3}{2}+\dfrac{1}{4}\)
\(x\) \(=\dfrac{7}{4}\)
\(x+\dfrac{4}{5}=\dfrac{8}{9}\)
\(x\) \(=\dfrac{8}{9}-\dfrac{4}{5}\)
\(x\) \(=\dfrac{4}{45}\)