Ta có:

\(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=5\)

\(\Rightarrow\frac{2}{3}-\frac{1}{3}x+\frac{1}{3}.\frac{3}{2}-x-\frac{1}{2}=5\)

\(\Rightarrow\frac{2}{3}-\left(\frac{1}{3}x+x\right)+\frac{1}{2}-\frac{1}{2}=5\)

\(\Rightarrow\frac{4}{3}x=\frac{2}{3}-5=-\frac{13}{3}\)

\(\Rightarrow x=-\frac{13}{3}:\frac{4}{3}=-\frac{13}{3}.\frac{3}{4}=-\frac{13}{4}\)

Vậy x=-13/4

131 . x - 942 = 2^7 . 2^3 

131 . x - 942 = 2^10

131 . x - 942 = 1024

131 . x = 1024 + 942 

131 . x = 1966

x = 1966 : 131 

x \(\approx15\)

b ) [ ( x + 32 ) - 17 ] . 2 = 42 

     [ ( x + 32 ) - 17 ] = 42 : 2

     ( x + 32 ) - 17  = 21

     x + 32 = 21 + 17

     x + 32 = 38

     x = 38 - 32

    x = 6

A. 131.x-942=2^7.2^3

    131.x-942=1024

    131.x       =1966

       x           =1966/131

B. [(x+32)-17].2=42

     (x+32-17) .2 =42

     (x+15).2       =42

      x+15           = 21

     x                 =6

\(5\cdot x+10\cdot9=990\)

\(\Rightarrow5\cdot x+90=990\)

\(\Rightarrow5\cdot x=900\)

\(\Rightarrow x=\dfrac{900}{5}\)

\(\Rightarrow x=180\)

_____________

\(1045:\left[215-\left(3\cdot x-24\right)\right]=5\)

\(\Rightarrow215-\left(3\cdot x-24\right)=1045:5\)

\(\Rightarrow215-\left(3\cdot x-24\right)=209\)

\(\Rightarrow3\cdot x-24=215-209\)

\(\Rightarrow3\cdot x-24=6\)

\(\Rightarrow3\cdot x=30\)

\(\Rightarrow x=10\)

`@` `\text {Ans}`

`\downarrow`

`5.x + 10.9 = 990`

`\Rightarrow 5x + 90 = 990`

`\Rightarrow 5x = 990 - 90`

`\Rightarrow 5x = 900`

`\Rightarrow x = 900 \div 5`

`\Rightarrow x = 180`

Vậy, `x = 180`

\(1045 \div [ 215 - (3 . x - 24 ) ] = 5\)

`\Rightarrow 1045 \div (215 - 3x + 24) = 5`

`\Rightarrow 191 + 3x = 1045 \div 5`

`\Rightarrow 191 + 3x = 209`

`\Rightarrow 3x = 209 - 191`

`\Rightarrow 3x =18`

`\Rightarrow x = 18 \div 3`

`\Rightarrow x = 6`

Vậy, `x = 6.`

5x+10.9=990

=>5x+90=990

=>5x=990-90

=>5x=900

=>x=900:5

=>x=180

______________

1045:[215-(3x-24)]=5

=>215-(3x-24)=1045:5

=>215-(3x-24)=209

=>3x-24=215-209

=>3x-24=6

=>3x=6+24

=>3x=30

=>x=30:3

=>x=10

\(4\left(x+2\right)-8\left(x+3\right)=36\)

\(\Rightarrow4x+8-8x-24=36\)

\(\Rightarrow4x-8x=36+24-8\)

\(\Rightarrow-4x=52\)

\(\Rightarrow x=-13\)

\(\text{a/96-3(x+1)=42}\)

\(3\left(x+1\right)=54\)

\(x+1=54:3\)

\(x+1=18\)

\(\Rightarrow x=17\)

\(\text{b/2.x-18=20}\)

\(2x=38\)

\(x=38:2\)

\(x=19\)

\(\text{c/134-5.(x+4)=34}\)

\(5\left(x+4\right)=100\)

\(x+4=100:5\)

\(x+4=20\)

\(\Rightarrow x=16\)

học tốt

a) 96-3(x+1)=42

3(x+1)=96-42

3(x+1)=54

x+1=54:3

x+1=18

x=18-1

Vậy x=17

b) 2x-18=20

2x=20+18

2x=38

x=38:2

x=19

Vậy x=19.

c) 134-5(x+4)=34

5(x+4)=134-34

5(x+4)=100

x+4=100:5

x+4=20

x=20-4

x=16

Vậy x=16.

a) 96-3(x+1)=42

          3(x+1)=96-42

          3(x+1)=54

               x+1=54:3

               x+1=18

                   x=18-1

                   x=17

Vậy x=17

b)2.x-18=20

   2.x     =20+18

   2.x     =38

      x     =38:2

      x     =19

Vậy x=19

c)134-5.(x+4)=34

          5.(x+4)=134-34

          5.(x+4)=100

              x+4 =100:5

              x+4 =20

                  x =20-4

                  x =16

Vậy x=16
 

a,(72000+18000)-(3x+3000)=12000

 90000-(3x+3000)=12000

            3x+3000=90000-12000

             3x+3000=78000

               3x=78000-3000

                3x=75000

                x=75000:3

                 x=25000

b,[3.(x+2):7]:4=120

 3.(x+2):7=120:4

3.(x+2):7=30

3.(x+2)=30.7

3.(x+2)=210

    x+2=210:3

     x+2=70

      x=70-2

       x=68

trúc nam ơi làm hộ tớ nốt với

c,4.(x-1)+[(4750-2160)-(1750-1160)=3000

   4.  x-1+(2590-590)=3000

   4. x-1+2000=3000

   4.x-1=3000-2000

   4.x-1=1000

   4.x=1000+1

    4.x=1001

      x=1001:4

       x=250,25

phương ơi cậu có chép sai đề ko

6+[x.(2+5)]=13

6+(x+7)=13

    x+7=13-6

    x+7=7

     x=7-7

       x=0

có khi nào bạn lầm đề ko? x=1 chứ nhỉ

mà 6+ thì phải là 7+