=(64+52)x52-2x26

=116x52-2x26

=6032-52

=5980

=64.52+37.52-52=(64+(37-1)).52=5200

e có chép nhầm để ko cj hấy ra số thập phân

\(=\dfrac{x^2\left(x-2\right)+3\left(x-2\right)}{x-2}=x^2+3\)

\(\dfrac{x^3-2x^2+3x-6}{x-2}=\dfrac{x^2\left(x-2\right)+3\left(x-2\right)}{x-2}\\ =\dfrac{\left(x^2+3\right)\left(x-2\right)}{x-2}=x^2+3\)

\(\left(x^3-2x^x+3x-6\right):\left(x-2\right)\)

\(=x^3:\left(x-2\right)-2x^x:\left(x-2\right)+3x:\left(x-2\right)-6:\left(x-2\right)\)

\(=x^3:x-x^3:2-2x^x:x+2x^x:2+3x:x-3x:2-6:x+6:2\)

\(=x^2-\dfrac{x^3}{2}-2x^{x-1}+x^x+3-\dfrac{3x}{2}-\dfrac{6}{x}+3\)

\(=x^2-\dfrac{x^3+3x}{2}-2x^{x-1}+x^x+6-\dfrac{6}{x}\)

\(=\left[66+34+77+23+12+88+45+55\right]\times\left[1808\times\left(25-25\right)\right]\\ =0\)

(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)

=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200-45200)

=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0

=0

(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)

= (12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 45200 )

= (12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0

= 0 

= [ (12+88) + (77+23) + (34+66) + (45+55) ] x ( 45200 - 45200 )

= [ 100 + 100 + 100 + 100 ] x 0

= 400

ĐÁP ÁN  : 400

Giải:

( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 1808 .25 )

=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 45200 )

=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . 0

=0

Học tốt!!!

(12+77+34+23+88+45+55+66)* (45200-1808*25)

=(12+77+34+23+88+45+55+66)* (45200-45200)

=(12+17+34+23+88+45+55+66)* 0

=0

\(\left(12+77+34+23+88+45+55+66\right)\times\left(45200-1808\times25\right)\)

\(=\left(12+77+34+23+88+45+55+66\right)\times\left(45200-45200\right)\)

\(=\left(12+77+34+23+88+45+55+66\right)\times0\)

\(=0.\)