Cách viết khác : \(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

Chúc bạn học tốt ^^

\(\left(\frac{16}{81}\right)=\left(\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{-4}{-9}\right)^2=\left(\frac{2^2}{3^2}\right)^2=\left(\frac{\left(-2\right)^4}{\left(-3\right)^4}\right)=...\)

\(\left(\frac{4}{9}\right)^2nha\)

4/9 mét vuông

(2/3)⁴ nha bạn

Lời giải:

Ta có:

Lời giải :

      Ta có :

 \(\frac{16}{81}\)\(=\)\(\left(\frac{4}{9}\right)^2\)\(=\)\(\left(\frac{-4}{9}\right)^2\)\(=\)\(\left(\frac{2}{3}\right)^4\)\(=\)\(\left(\frac{-2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(-\dfrac{4}{9}\right)^2\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

\(\frac{25}{9}=\left(\frac{5}{3}\right)^2\)

\(\frac{16}{81}=\frac{4^2}{9^2}=\left(\frac{4}{9}\right)^2\)

\(\frac{16}{81}=\frac{4^2}{9^2}=\left(\frac{4}{9}\right)^2\)

P/s : Học tốt !

\(\frac{16}{81}=\frac{4^2}{9^2}=\left(\frac{4}{9}\right)^2\)

(2/3)⁴ = 16/81

\(\frac{16}{81}=\left(\frac{-4}{9}\right)^2=\left(\frac{4^2}{3^2}\right)=\left(\frac{\left(-4\right)^2}{\left(-3\right)^2}\right)=....\)

\(\frac{16}{81}=\left(\frac{4}{9}\right)^2\)

\(\frac{16}{81}=\frac{4^2}{9^2}=\left(\frac{4}{9}\right)^2\)

`@` `\text {Ans}`

`\downarrow`

`a)`

`16^3 = (4^2)^3 = 4^6` 

`b)`

`25^6 = (5^2)^6 = 5^12`

`c)`

`81^5 = (9^2)^5 = 9^10`

`d)`

`27^5 = (3^3)^5 = 3^15`

`e)`

`64^3*16^3`

`= (4^3)^3*(4^2)^3`

`= 4^9*4^6`

`= 4^15`

_____

`@` Nâng lên lũy thừa

CT: `(a^m)^n=a^m*a^n = a^(m*n)`