\(H=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35.\left(294-1\right)}=\frac{14.293}{35.293}=\frac{2}{5}\)
\(K=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(I=\frac{1313-1717}{303}=\frac{13.101-17.101}{3.101}=\frac{101.\left(13-17\right)}{3.101}=\frac{-4}{3}\)

\(M=\frac{12-24.3}{1-35}=\frac{12-12.2.3}{-34}=\frac{12.\left(1-6\right)}{-34}=\frac{-60}{-34}=\frac{30}{17}\)

\(H\)\(=\) \(\frac{4116-14}{10290-35}\)

       \(=\) \(\frac{4102}{10255}\) 

       \(=\) \(\frac{4102:2051}{10255:2051}\) 

       \(=\) \(\frac{2}{5}\) 

\(K=\frac{2929-101}{2.1919+404}\)

   \(=\) \(\frac{2828}{4242}\) 

   \(=\) \(\frac{2828:1414}{4242:1414}\) 

   \(=\) \(\frac{2}{3}\)  

\(M=\frac{12-24.3}{1-35}\)

    \(=\) \(\frac{-60}{-34}\)

     \(=\) \(\frac{60}{34}\) 

      \(=\) \(\frac{30}{17}\)

:D

\(H=\frac{14\cdot294-14}{35\cdot294-35}=\frac{14\cdot\left(294-1\right)}{35\cdot\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)

\(K=\frac{29\cdot101-101}{2\cdot19\cdot101+4\cdot101}=\frac{101\cdot\left(29-1\right)}{101\cdot\left(2\cdot19+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(I=\frac{13\cdot101-17\cdot101}{3\cdot101}=\frac{101\cdot\left(13-17\right)}{3\cdot101}=\frac{-4}{3}\)

\(M=\frac{12-72}{-34}=\frac{-60}{-34}=\frac{15}{17}\)

a. 2/3 * 3/4 *4/5 ...   =  ... (1-1/3)*(1-1/4)*(1-1/5)    (đều = 2/5 = 0.4)

b. 1313/1717*10101/105105 ...  <   ... 13/17*101/105

\(=\dfrac{13}{17}\cdot\dfrac{17}{19}\cdot\dfrac{19}{13}=1\)

=1

1

1313/1717=13/17

=>1313/17 = 13/17

161616/202020 =16/20=4/5=24/30 ;5/6=25/30

=>161616/202020 <5/6

= 65/17

\(\dfrac{1313}{1717}\) : \(\dfrac{1}{5}\) = \(\dfrac{13}{17}\) : \(\dfrac{1}{5}\) = \(\dfrac{65}{17}\) 

\(\dfrac{1313}{1717}\):\(\dfrac{1}{5}\)=\(\dfrac{13}{17}\)x5=\(\dfrac{65}{17}\)

1313/1717 = 13/17             161616/202020 < 5/6

1414 > 7/8                         1212/1616 > 1515/2424

chúc bạn học tốt! ^_^

phần dưới cùng là cái underline đấy, ko phải dấu = đâu