\(a,101^2=101.\left(100+1\right)=10100+101=10201.\\ b,75^2-50.75+25^2\\ =75.\left(75-50\right)+25^2\\ =75.25+25^2\\ =25.\left(75+25\right)\\ =25.100\\ =2500.\)

\(c,103.97\\ =\left(100+3\right).97\\ =9700+291\\ =9991\)

a) \(101^2=101.101=10201\)

b) \(75^2-50.75+25^2\)

\(=75^2-2.25.75+25^2\)

\(=\left(75-25\right)^2=50^2=2500\)

c) \(103.97=\left(100+3\right).\left(100-3\right)\)

\(=100^2-3^2=9991\)

 752x89-752x9+752x20

=752x(89-9+20)

=752x100

=75200

752 x 89 - 752 x 9 + 752 x 20

= 752 x ( 89 - 9 + 20 )

= 752 x ( 80 + 20 )

= 752 x 100

= 75200

752x89-752x9+752x20

=752x(89-9+20)

=752x100

=75200

a) \(103^2=\left(100+3\right)^2=10000+600+9=10609\)

b) \(52\cdot48=\left(50-2\right)\left(50+2\right)=2500-4=2496\)

c) \(75^2-50\cdot75+25^2=\left(75-25\right)^2=50^2=2500\)

\(103^2=\left(100+3\right)^2=100^2+2.3.100+3^2=10000+600+9=10609\)

\(52.48=\left(50+2\right)\left(50-2\right)=50^2-2^2=2500-4=2496\)

\(75^2-50.75+25^2=75^2-25.75-25.75+25^2=75\left(75-25\right)-25\left(75-25\right)=\left(75-25\right)=50^2=2500\)

thiếu r

4,25 . 5 .20

=425

\(425\)

a) = (50-1)^2 = 50^2 - 2.50 + 1 = 2500 - 100 + 1 = 2401

b) = (50+1)^2 = 50^2 + 2.50 + 1 = 2601

c) = 9900

a) \(\left(-48\right)+10+\left(-22\right)+\left(-10\right)\)

\(=\left[\left(-48\right)+\left(-22\right)\right]+\left(-10+10\right)\)

\(=-70+0=-70\)

Tham khảo <3

= -70 

( hihi )

(-48)+(-22)+(10-10)

=-70 +0

=-70

làm giúp😢😢

a) 425.7.4-170.60

=85.5.7.4-85.2.60=85.(5.7.4-2.60)=85.20=1700

b) 8.9.14+6.17.12+19.4.18

=72.14+72.17+72.19=72.(14+17+19)=72.50=3600 

4996+2314+1003=8313

4996 + 2314 + 1003

= ( 4996 + 2314 ) + 1003

= 7310 + 1003

= 8313

4996+2314+1003=8313

Chúc bạn chăm ngoan học giỏi ,vâng lời ông bà , cha mẹ!!!.Kết bạn với mình nha!!!!!!!!!!!

a. Ta có: \(17^2-14.17+49=17^2-2.7.17+7^2=\left(17-7\right)^2=10^2=100\)

b. \(2021^2-2020^2=\left(2021-2020\right)\left(2021+2020\right)=4041\)