a) 3xy² + x²y² - 5x²y = xy( 3y + xy - 5x )

b) 8m³ + 12m² + 6m + 1 = ( 2m + 1 )³

\(a)-64+y^2=\left(y-8\right)\left(y+8\right)\)

\(b)-27-x^3=-\left(27+x^3\right)=-\left(3+x\right)\left(9-3x+x^2\right)\)

- 64 + y ²

= - 8 . 8 + y . y

= ( y + 8 ) . ( y - 8 ) 

-27 - x³

= - ( 27 + x³ )

= - ( 3 + x ) . ( 9 - 3 + x² )

a) \(8x^3-\dfrac{1}{27}=\left(2x-\dfrac{1}{3}\right)\left(4x^2+\dfrac{2}{3}x+\dfrac{1}{9}\right)\)

b) \(\dfrac{1}{8}a^3-125b^6=\left(\dfrac{1}{2}a-5b^2\right)\left(\dfrac{1}{4}a+\dfrac{5}{2}ab^2+25b^4\right)\)

c) \(125+\left(a-b\right)^3=\left(5+a-b\right)\left(25-5a+5b+a^2-2ab+b^2\right)\)

= ( x ⁴) ² + 8² - 16x⁴ + 16x⁴ = ( x⁴ + 4) - ( 4x ) ² = ( x⁴ +4 - 4x)( x⁴ +4 + 4x ) 

 =

( x⁴ ) ² + 16x⁴ + 16x⁴ = ( x⁴  + ) ² = ( x⁴ + 4 - 4x ) +  ( x^{4  +} 4 + 4x )

Đáp số : ....

câu hỏi hay......nhưng tui xin nhường cho các bn khác

Hãy tích đúng cho tui nha

THANKS

1.

$k^5-k^3+k^2-1=(k^5-k^3)+(k^2-1)=k^3(k^2-1)+(k^2-1)=(k^2-1)(k^3+1)$

$=(k-1)(k+1)(k+1)(k^2-k+1)=(k-1)(k+1)^2(k^2-k+1)$

2. 

$2m^2-72+96n-32n^2$

$=2(m^2-36+48n-16n^2)$

$=2[m^2-(16n^2-48n+36)]$

$=2[m^2-(4n-6)^2]=2(m-4n+6)(m+4n-6)$

3.
$(b-3a)^2-4b^2+12ab=(b-3a)^2-(4b^2-12ab)=(b-3a)^2-4b(b-3a)$

$=(b-3a)(b-3a-4b)=(b-3a)(-3a-3b)=3(3a-b)(a+b)$

4.

$(a^2-3a-10)^2-4(a^2-10)^2+12a(a^2-10)$

$=(a^2-3a-10)^2-4(a^2-10)(a^2-10-3a)$

$=(a^2-3a-10)(a^2-3a-10-4a^2+40)$

$=(a^2-3a-10)(-3a^2-3a+30)$

$=-3(a^2-3a-10)(a^2+a-10)$

$=-3(a-5)(a+2)(a^2+a-10)$