c,99^20=(99^2)^10=9801^10<9999^10

--------Hok tốt-------

a,2^91=2^85.2^6

         =(2^5)^17.64

         =32^17.64

  5^35=5^34.5

         =25^17.5

Có 32^17>25^17;64>5

Nên 2^91>5^35

Cố lên nha ai nhanh và đúng ( làm đc cả ba phần sẽ đc k ) :))

a, Ta có:

\(2^{225}=2^{3.75}=\left(2^3\right)^{75}=8^{75}\)

\(3^{150}=3^{2.75}=\left(3^2\right)^{75}=9^{75}\)

Vì \(8^{75}< 9^{75}\)nên \(2^{225}< 3^{150}\)

b, Ta có:

\(2^{91}=2^{13.7}=\left(2^{13}\right)^7=8192^7\)

\(5^{35}=5^{5.7}=\left(5^5\right)^7=3125^7\)

Vì \(8192^7>3125^7\)nên \(2^{91}>5^{35}\)

2^225>3^150

2^91<5^35

99^20<9999^10

a, 2²²⁵ và 3¹⁵⁰
2²²⁵ = ( 2³ )⁷⁵ = 8⁷⁵
3¹⁵⁰ = ( 3² )⁷⁵ = 9⁷⁵
Do 8⁷⁵ < 9⁷⁵ nên 2²²⁵ < 3¹⁵⁰ 
b,c tương tự
 

a, 2^24 > 3^16

b, 5^300>3 ^500

c,99^20 > 9999^10

d, 2^30 +3^44 +4^30 < 3x24^10

1) Ta có: 9²⁰⁰⁰ = (3²)²⁰⁰⁰ = 3⁴⁰⁰⁰

nên 3⁴⁰⁰⁰ = 9²⁰⁰⁰

f: 11^1979<11^1980=1331^660

37^1320=(37^2)^660=1369^660

1331<1369

=>1331^660<1369^660

=>11^1980<37^1320

=>11^1979<37^1320

g: 10^10=2^10*5^10

48*50^5=2^4*3*2^5*5^10=2^9*3*5^10

2^10<2^9*3

=>2^10*5^10<2^9*3*5^10

=>10^10<48*50^5