10 + 2 . x = 1024 : 64
10(x-20)=10
597-3x=9.2
10+2x=1024:64
10(x-20)=10
x - 20 = 10-10
x - 20 = 0
x = 0 + 20
x = 20
597 - 3x = 9.2
597 -3x = 18
3x = 597 - 18
3x = 579
x = 579 : 3
x = 193
10 + 2x = 1024 : 64
10 + 2x = 16
2x = 16 - 10
2x = 6
x = 6 : 2
x = 3
A)2^x-1=64 b)3^2x-10=81 c)2^2x+3=1024 d) 618-3^x+1=24.5^2
a, 2x-1 = 64
=> 2x-1 = 26
=> x - 1 = 6
=> x = 6 + 1
=> x = 7
b, 32x-10 = 81
=> 32x-10 = 34
=> 2x - 10 = 4
=> 2x = 14
=> x = 7
c, 22x+3 = 1024
=> 22x+3 = 210
=> 2x + 3 = 10
=> 2x = 7
=> x = \(\frac{7}{2}\)
Biết 2^10 = 1024
Vậy 2^64 = ?
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1.<,>,= ?
256 x 6.....512 x 3
512 x 3.....256 x 6
999 x 2.....1000
512 x 5.....1024
1024.....512 x 5
1024.....512 x 2
512.....256 x 2
256.....128 x 2
128.....64 x 2
64.....32 x 2
32.....16 x 2
256 x 6=512 x 3
512 x 3=256 x 6
999 x 2>1000
512 x 5>1024
1024<512 x 5
1024=512 x 2
512=256 x 2
256=128 x 2
128=64 x 2
64=32 x 2
32=16 x 2
Phân tích số sau ra thừa số nguyên tố:
2^100 x 1024 x 125 x 64 x 5^2021
\(=2^{110}\cdot5^3\cdot2^6\cdot5^{2021}=2^{116}\cdot5^{2024}\)
64 . 4 mũ x = 16 mũ 8
2 mũ x.16 mũ 2=1024
64 . 4x = 168
<=> 43. 4x = 416
=> 3 + x = 16
<=> x = 13
Vậy x = 13
2x.162 = 1024
<=> 2x. 28 = 210
=> x + 8 = 10
<=> x = 2
Vậy x = 2
64^x.16^x=256^12:1024
64x.16x=25612:1024
1024x=443
45x=443
5x=43
x=8,6
\(64^x.16^x=256^{12}:1024\)
\(\Rightarrow\) \(\left(4^3\right)^x.\left(4^2\right)^x=\left(4^4\right)^{12}:4^5\)
\(\Rightarrow\) \(4^{3x}.4^{2x}=4^{48}:4^5\)
\(\Rightarrow\) \(4^{3x+2x}=4^{43}\)
\(\Rightarrow\) \(3x+2x=43\)
\(\Rightarrow\) \(\left(3+2\right)x=43\)
\(\Rightarrow\) \(5x=43\)
\(\Rightarrow\) \(x=\frac{43}{5}\)
64x.16x=25612:1024
1024x=443
45x=443
5x=43
x=8,6
a)x^20=x;b)2^x* 16^2=1024;c)64*4x=16^8;d)2^x-15=17;e)(7x-11)^3=2^5*5^2+200
x^20-x=0
x(x^19-1)=0
x= 0
hoặc x ^ 19 =1
x = 0 hoặc x= 1
Phân tich ra thừa số nguyên tố
a) 2100 x 1024 x 125 x 64 x 52021
b) 7100 + 7101 + 7102