\(\left(\frac{2}{11.13}+\frac{2}{13.15}+.........+\frac{2}{19.21}\right)x623-24,808:\left(y+0,5\right)+12,04=30\)

Ta tính bên trong ngoặc:

\(\frac{2}{11.13}+\frac{2}{13.15}+..........+\frac{2}{19.21}\)

= \(\frac{2}{11}-\frac{2}{13}+\frac{2}{13}-\frac{2}{15}+...........+\frac{2}{19}-\frac{2}{21}\)

= \(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+.........+\frac{1}{19}-\frac{1}{21}\)

=> \(\frac{1}{11}-\frac{1}{19}\)= \(\frac{8}{209}\)

=> \(\frac{8}{209}x623-24,808:\left(y+0,5\right)+12,04=30\)

      Tiếp tục làm tiếp nhé

Nhầm mk làm lại:

\(\frac{1}{11}-\frac{1}{21}=\frac{10}{231}\)

=> \(\frac{10}{231}x623-24,808:\left(y+05\right)+12,04=30\)

      \(\frac{890}{33}\)- 24,808 : .......

Làm tiếp đi nhé

=> 1/11 - 1/13 + 1/13 - 1/15 + ..... + 1/19 - 1/21 - x + 4 + 221/231 = 7/3

=> 1/11 - 1/21 - x + 4 + 221/231 = 7/3

=> 2099/420 - x = 7/3

=> x = 2099/420 - 7/3 = 373/140

Tk mk nha

Bài làm

\(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11.13}+\frac{1}{13.15}+...+\frac{1}{19.21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2\left(\frac{1}{11}-\frac{1}{21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow2.\frac{10}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+4+\frac{221}{231}=\frac{7}{3}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}+\frac{221}{231}=\frac{539}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{539}{231}-\frac{221}{231}\)

\(\Leftrightarrow\frac{20}{231}-x+\frac{924}{231}=\frac{318}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=\frac{318}{231}-\frac{924}{231}\)

\(\Leftrightarrow\frac{20}{231}-x=-\frac{606}{231}\)

\(\Leftrightarrow x=\frac{20}{231}-\frac{606}{231}\)

\(\Leftrightarrow x=-\frac{586}{231}\)

Vậy \(\Leftrightarrow=-\frac{586}{231}\)

ta có : 2/11*15 +2/13*15+...+2/19*21 - x +4+221/231=7/3

=>(1/11 -1/13 + 1/13-1/15+...+1/19 - 1/21)-x+4 +221/231=7/3

<=>(1/11 - 1/21)-x+4 + 221/231=7/3

<=>10/231 -  x+4 +221/231 =7/3

<=>1-x +4=7/3

<=>x+4=1-7/3

<=>x+4=-4/3

<=>x=-4/3-4

<=>x=-16/3

vậy x=-16/3

(2/143+2/195+2/255+2/323+2/399).462-y=19

=> 10/231.462-y=19

=>  20-y=19

=> y= 20-19=1

DUYỆT NHA                                                     "T I C K"

giai câu a

a)   ta có   (\(\frac{2}{11.13}\)+\(\frac{2}{13.15}\)+.....+\(\frac{2}{19.21}\))*462 - x =19

                (\(\frac{1}{11}\)-\(\frac{1}{13}\)+\(\frac{1}{13}\)-\(\frac{1}{15}\)+....+\(\frac{1}{19}\)-\(\frac{1}{21}\)) * 462 -x=19

                (\(\frac{1}{11}\)-\(\frac{1}{21}\))*462-x=19

còn lại ban tu tinh nhu bai tim x

a ) ta gọi biểu thức trước 462 là A

\(A=1.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\)

\(A=\frac{1}{11}-\frac{1}{21}=\frac{10}{231}\)

từ đó ta có biểu thức \(\frac{10}{231}.462-x=19\)\(\Rightarrow x=1\)

b)ta gọi biểu thức trước x là B

\(B=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{6.7}\)

\(B=1-\frac{1}{7}=\frac{6}{7}\)

Từ đó x = \(\frac{1}{7}\)

kb nha

Bài 1: 

\(\Leftrightarrow\left(\dfrac{1}{11}-\dfrac{1}{21}\right)\cdot462-\left[2.04:\left(x+1.05\right)\right]:0.12=19\)

\(\Leftrightarrow\left[2.04:\left(x+1.05\right)\right]:0.12=1\)

\(\Leftrightarrow2.04:\left(x+1.05\right)=0.12\)

\(\Leftrightarrow x+1.05=17\)

hay x=15,85

\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+...+\frac{2}{19\times21}\right)\times462-2,04\div\left(x+15\right)+11,02=30\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-2,04\div\left(x+15\right)+11,02=30\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-2,04\div\left(x+15\right)=30-11,02\)

\(\frac{10}{231}\times462-2,04\div\left(x+15\right)=18,98\)

\(20-2,04\div\left(x+15\right)=18,98\)

\(2,04\div\left(x+15\right)=20-18,98\)

\(2,04\div\left(x+15\right)=1,02\)

\(x+15=2,04\div1,02\)

\(x+15=2\)

\(x=2-15\)

\(x=-13\)