`!`

\(a,\dfrac{8}{9}\times\dfrac{7}{5}-\dfrac{7}{9}\times\dfrac{2}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\left(\dfrac{7}{5}-\dfrac{2}{5}\right)+\dfrac{2}{9}\\ =\dfrac{8}{9}\times\dfrac{5}{5}+\dfrac{2}{9}\\ =\dfrac{8}{9}+\dfrac{2}{9}\\ =\dfrac{10}{9}\)

\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\\ =\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\\ =\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\\ =\dfrac{1}{4}\times\dfrac{9}{9}\\ =\dfrac{1}{4}\)

ai trl giúp mình được không, mình xin ấy:<<

a)\(4\dfrac{8}{23}+5\dfrac{7}{8}-9\dfrac{8}{23}=\dfrac{100}{23}+\dfrac{47}{8}-\dfrac{215}{23}=\dfrac{100}{23}-\dfrac{215}{23}+\dfrac{47}{8}=-\dfrac{115}{23}+\dfrac{47}{8}=-5+\dfrac{47}{8}=\dfrac{7}{8}\)

b) \(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}=\dfrac{58}{7}-\dfrac{30}{7}-\dfrac{31}{9}=4-\dfrac{31}{9}=\dfrac{5}{9}\)

` a)  4 8/23 + 5 7/8 - 9 8/23 `

`= 100/23 + 47/8 - 215/23 `

`= ( 100/23 - 215/23) + 47/8 `

`= -115/23 + 47/8 `

`= -5 + 47/8 `

`= -5/1 + 47/8 `

`= -40/8 + 47/8 `

`=7/8`

`b) 8 2/7 - ( 3 4/9 + 4 2/7 ) `

`= 58/7 - 31/9 - 30/7 `

`= (58/7 - 30/7 ) - 31/9 `

`= 28/7 - 31/9 `

` = 252/63 - 217/63 `

`= 35/63`

`= 5/9`

`@ animephamdanhv.`

lớp 5 ạ

\(C=\dfrac{3}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{3}{7}-\dfrac{3}{7}\)

\(=\dfrac{3}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{3}{7}-\dfrac{3}{7}\times1\)

\(=\dfrac{3}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}-1\right)\)

\(=\dfrac{3}{7}\times0=0\)

\(D=8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)

\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)

\(=\left(\dfrac{58}{7}-\dfrac{30}{7}\right)-\dfrac{31}{9}\)

\(=4-\dfrac{31}{9}=\dfrac{36}{9}-\dfrac{31}{9}\)

\(=\dfrac{5}{9}\)

\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}.\)

\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}.\)

\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8}=\dfrac{15}{8}.\)

\(d,5:\dfrac{6}{21}=5\times\dfrac{21}{6}=\dfrac{5\times21}{6}=\dfrac{105}{6}=\dfrac{35}{2}.\)

\(đ,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}.\)

\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}\)

\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}\)

\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8\times1}=\dfrac{15}{8}\)

\(d,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}\)

[(1+100)*100]/2= 5050

SỐ ĐẦU + SỐ CUỐI NHÂN CHO SỐ SỐ HẠNG RỒI CHIA TẤT CẢ CHO 2

sai đề nhá, 9 chứ ko phải 999 đâu

số số hạng trong dãy số trên là: ( 100-1):1+1=100

tổng dãy số trên là: ( 100+1 ) x 100 :2=5050

a) = 80/91

b)= 1/9

a) = 80/91

b) = 1/9

ai tích mình mình tích lại cho!!!!

a)  80/91

b) 1/9

Ai k tôi tôi k lại

\(E=1-2+3-4+5-6+...2015-2016-2017\)

\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...\left(2015-2016\right)-2017\)

Mỗi nhóm có kết quả = -1. 

\(=>\left[\left(2016-1\right)+1\right]:2=1008\)

\(=-1.1008+2017=-1008+2017=1009\)

= (3/7 + 4/7) + (8/13 + 18/13) + (7/9 + 11/9)

= 7/7 + 26/3 + 18/9

= 1 + 2+ 2

=5

=(3\7+4\7)+(8\13 +18|13)+(7\9+11\9)

=7\7+26\13+18\9

=1+2+2

=5

\(\frac{3}{7}+\frac{8}{13}+\frac{7}{9}+\frac{4}{7}+\frac{18}{13}+\frac{11}{9}\)

\(=\left(\frac{3}{7}+\frac{4}{7}\right)+\left(\frac{8}{13}+\frac{18}{13}\right)+\left(\frac{7}{9}\cdot\frac{11}{9}\right)\)

\(=1+2+2\)

\(=5\)