Ta có : (1+2+3+.....+100).(1²+ 2² +.....+10² ).(65.111 - 13.15.37)

         =A .B.(65.111-13.5.3.37)

         =A.B.(65.111-65.111)

         =A.B.0

         =0

\(A=\left(1+2+3+...+2023\right)\left(1^2+2^2+...+2023^2\right)\left(65\cdot111-13\cdot15\cdot37\right)\)

\(=\left(1+2+3+...+2023\right)\cdot\left(1^2+2^2+...+2023^2\right)\cdot\left(13\cdot5\cdot3\cdot37-13\cdot5\cdot3\cdot37\right)\)

=0

b, ( mik cx ko viết đề bài lun ^_^ )

= ( 1 + 2 + 3 + ... + 100 ) . ( 1² + 2² + 3² + ... + 10² ) . ( 65 . 111 - 13 . 555 )

= ( 1 + 2 + 3 + ... + 100 ) . ( 1² + 2² + 3² + ... + 10² ) . ( 65 . 111 - 13 . 5 . 111 )

= ( 1 + 2 + 3 + ... + 100 ) . ( 1² + 2² + 3² + ... + 10² ) . ( 65 . 111 - 65 . 111 )

= ( 1 + 2 + 3 + ... + 100 ) . ( 1² + 2² + 3² + ... + 10² ) . 0

= 0

Chúc hok tốt !

Mk nhầm sr nhé :

A = \(\frac{2^{10}\left(13+65\right)}{2^8.2^3.13}\)

A = \(\frac{2^{10}.78}{2^{11}.13}\)

A = \(\frac{2^{10}.13.3.2}{2^{11}.13}\)

A = \(\frac{2^{11}.13.3}{2^{11}.13}\)

A = \(3\)

a, ( mik ko viết đề bài đặt A luôn nhé )

 A = \(\frac{2^{10}\left(13+65\right)}{2^8.2^3.3}\)

A = \(\frac{2^{10}.78}{2^{11}.3}\)

A = \(\frac{2^{10}.2.3.13}{2^{11}.3}\)

A = \(\frac{2^{11}.3.13}{2^{11}.3}\)

A = \(13\)

210 . 13 + 210 . 6528 .104

= 210 . ( 13 + 6528 ) . 104

= 210 . 6541 .104

= 142855440