x^8 + 98x^4 + 1
\(x^8+98x^4+1\)
x8 + 98x4 + 1
= (x8 + 2x4 + 1 ) + 96x4
= (x4 + 1)2 + 16x2(x4 + 1) + 64x4 - 16x2(x4 + 1) + 32x4
= (x4 + 1 + 8x2)2 – 16x2(x4 + 1 – 2x2) = (x4 + 8x2 + 1)2 - 16x2(x2 – 1)2
= (x4 + 8x2 + 1)2 - (4x3 – 4x)2
= (x4 + 4x3 + 8x2 – 4x + 1)(x4 - 4x3 + 8x2 + 4x + 1)
Tính giá trị của biểu thức :
A = x^7 - 98x^6 - 98x^5 - 98x^4 - 98x^3 - 98^2 - 98x + 1 tại x = 99
Vì \(x=99\Rightarrow98=x-1\)
Thay \(98=x+1\)vào biểu thức A , ta có :
\(A=x^7-\left(x-1\right)x^6-\left(x-1\right)x^5-\left(x-1\right)x^4-\left(x-1\right)x^3-\left(x-1\right)x^2-\left(x-1\right)x+1\)
\(\Rightarrow A=x^7-x^7+x^6-x^6+x^5-x^5+x^4-x^4+x^3-x^3+x^2-x^2+x+1\)
\(\Rightarrow A=x+1=99+1=100\)
x8 + 98x4 + 1
a) x8 + 14x4 + 1
b) x8 + 98x4 + 1
a) \(x^8+14x^4+1=\left(x^4+1\right)^2+12x^4=\left(x^4+1\right)^2+4x^2\left(x^4+1\right)+4x^4-4x^2\left(x^4+1\right)+8x^4\)
\(=\left(x^4+2x^2+1\right)^2-4x^2\left(x^4-2x^2+1\right)=\left(x^4+2x^2+1\right)^2-\left(2x\left(x^2-1\right)\right)^2\)
\(=\left(x^4-2x^3+2x^2+2x+1\right)\left(x^4+2x^3+2x^2-2x+1\right)\)
Tính giá trị của biểu thức
a) A = x^7 - 98x^6 - 98x^5 - 98x^4 - 98x^3 - 98^2 - 98x + 1
PTĐTTNT:
\(\text{a) }x^8+14x^4+1\)
\(\text{b) }x^8+98x^4+1\)
\(a,x^8+14x^4+1=\left(x^8+14x^4+49\right)-48\)
\(=\left(x^4+7\right)^2-48\)
\(=\left(x^4+7+\sqrt{48}\right)\left(x^4+7-\sqrt{48}\right)\)
\(b,x^8+98x^4+1\)
\(=\left(x^8+98x^4+2401\right)-2400\)
\(=\left(x^4+49\right)^2-2400\)
\(=\left(x^4+49+20\sqrt{6}\right)\left(x^4+49-20\sqrt{6}\right)\)
Mình nghĩ vậy k bt đúng k :)
Phân tích đa thức thành nhân tử:
a)\(x^8+14x^4+1\)
b) \(x^8+98x^4+1\)
Ta có : \(x^8+14x^4+1\)
\(=x^8+2.x^4.7+1\)
\(=x^8+2.x^4.7+49-48\)
\(=\left(x^4+7\right)^2-48\)
\(=\left(x^4+7-\sqrt{48}\right)\left(x^4+7+\sqrt{48}\right)\)
a/\(=\left(x^4+1\right)^2+12x^4=\left(x^4+1\right)^2+4x^2\left(x^4+1\right)+4x^4-4x^2\left(x^4+1\right)+8x^4\)
\(=\left(x^4+1+2x^2\right)^2-4x^2\left(x^4+1-2x^2\right)=\left(x^4+2x^2+1\right)-\left(2x^3-2x\right)^2\)
\(=\left(x^4+2x^3+2x^2-2x+1\right)\left(x^4-2x^3+2x^2+2x+1\right)\)
b/\(=\left(x^4+1\right)^2+96x^4=\left(x^4+1\right)^2+16x^2\left(x^4+1\right)+64x^4-16x^2\left(x^4+1\right)+32x^4\)
\(=\left(x^4+1+8x^2\right)^2-16x^2\left(x^4+1-2x^2\right)=\left(x^4+8x^2+1\right)-\left(4x^3-4x\right)^2\)
\(=\left(x^4+4x^3+8x^2-4x+1\right)\left(x^4-4x^3+8x^2+4x+1\right)\)
x8 + 98x4 + 1
Phân tích đa thức
x8 + 98x4 + 1
= (x8 + 2x4 + 1 ) + 96x4
= (x4 + 1)2 + 16x2(x4 + 1) + 64x4 - 16x2(x4 + 1) + 32x4
= (x4 + 1 + 8x2)2 – 16x2(x4 + 1 – 2x2)
= (x4 + 8x2 + 1)2 - 16x2(x2 – 1)2
= (x4 + 8x2 + 1)2 - (4x3 – 4x )2
= (x4 + 4x3 + 8x2 – 4x + 1)(x4 - 4x3 + 8x2 + 4x + 1)
x8 + 98x4 + 1
= (x8 + 2x4 + 1 ) + 96x2
= (x4 + 1)2 + 16x2(x4 + 1) + 64x4 - 16x2(x4 + 1) + 32x4
= (x4 + 1 + 8x2)2 – 16x2(x4 + 1 – 2x2)
= (x4 + 8x2 + 1)2 - 16x2(x2 – 1)2
= (x4 + 8x2 + 1)2 - (4x3 – 4x )2
= (x4 + 4x3 + 8x2 – 4x + 1)(x4 - 4x3 + 8x2 + 4x + 1)
Vậy...
Phân tích đa thức thành nhân tử:
\(x^8+98x^4+1\)
https://coccoc.com/search/math#query=Ph%C3%A2n+t%C3%ADch+%C4%91a+th%E1%BB%A9c+th%C3%A0nh+nh%C3%A2n+t%E1%BB%AD%3A+x%5E8%2B98x%5E4%2B1
x8 + 98x4 + 1 = (x8 + 2x4 + 1 ) + 96x4
= (x4 + 1)2 + 16x2(x4 + 1) + 64x4 - 16x2(x4 + 1) + 32x4
= (x4 + 1 + 8x2)2 – 16x2(x4 + 1 – 2x2) = (x4 + 8x2 + 1)2 - 16x2(x2 – 1)2
= (x4 + 8x2 + 1)2 - (4x3 – 4x )2
= (x4 + 4x3 + 8x2 – 4x + 1)(x4 - 4x3 + 8x2 + 4x + 1)