What does the mother look like?

What does the mother do?

Who is taller, the son or the daughter?

How old is the daughter?

What class is the son in?

Gọi số hoa của Hằng và Nga lần lượt là a,b

Theo đề, ta có: a-b=18 và a+6=5/3b

=>a-b=18 và a-5/3b=-6

=>a=54 và b=36

mình lm ở dưới r mà bạn

We will have a three-month vacation

từ gợi ý hình như sai

theo mình câu 5 là :

We will have a three-month vacation.

Lỗi Sai :

We will have a three-month vacation.

Bài 5 hình 1: (tự vẽ hình nhé bạn)
a) Xét ΔABD và ΔACB ta có:
\(\widehat{BAD}\)= \(\widehat{BAC}\) (góc chung)
\(\widehat{ABD}\)= \(\widehat{ACB}\) (gt)
=> ΔABD ~ ΔACB (g-g)
=> \(\dfrac{AB}{AC}\) = \(\dfrac{BD}{CB}\) = \(\dfrac{AD}{AB}\) (tsđd)
b) Ta có: \(\dfrac{AB}{AC}\) = \(\dfrac{AD}{AB}\) (cm a)
=> \(AB^2\) = AD.AC
=> \(2^2\) = AD.4
=> AD = 1 (cm)
Ta có: AC = AD + DC (D thuộc AC)
      => 4   =   1   + DC
      => DC = 3 (cm)
c) Xét ΔABH và ΔADE ta có: 
   \(\widehat{AHB}\) = \(\widehat{AED}\) (=\(90^0\))
   \(\widehat{ADB}\) = \(\widehat{ABH}\) (ΔABD ~ ΔACB)
=> ΔABH ~ ΔADE
=> \(\dfrac{AB}{AD}\) = \(\dfrac{AH}{AE}\) = \(\dfrac{BH}{DE}\) (tsdd)
Ta có: \(\dfrac{S_{ABH}}{S_{ADE}}\) = \(\left(\dfrac{AB}{AD}\right)^2\)= \(\left(\dfrac{2}{1}\right)^2\)= 4
=> đpcm

Tiếp bài 5 hình 2 (tự vẽ hình)
a) Xét ΔABC vuông tại A ta có:
\(BC^2\) = \(AB^2\) + \(AC^2\)
\(BC^2\) = \(21^2\) + \(28^2\)
BC = 35 (cm)
b) Xét ΔABC và ΔHBA ta có:
\(\widehat{BAC}\) = \(\widehat{AHB}\) ( =\(90^0\))
\(\widehat{ABC}\) = \(\widehat{ABH}\) (góc chung)
=> ΔABC ~ ΔHBA (g-g)
=> \(\dfrac{AB}{BH}\) = \(\dfrac{BC}{AB}\) (tsdd)
=> \(AB^2\) = BH.BC
=> \(21^2\) = 35.BH
=> BH = 12,6 (cm)
c) Xét ΔABC ta có:
BD là đường p/g (gt)
=> \(\dfrac{AD}{DC}\) = \(\dfrac{AB}{BC}\) (t/c đường p/g)
Xét ΔABH ta có: 
BE là đường p/g (gt)
=> \(\dfrac{HE}{AE}\) = \(\dfrac{BH}{AB}\) (t/c đường p/g)
Mà: \(\dfrac{AB}{BC}\) = \(\dfrac{BH}{AB}\) (cm b)
=> đpcm
d) Ta có: \(\left\{{}\begin{matrix}\widehat{HBE}+\widehat{BEH}=90^0\\\widehat{ABD}+\widehat{ADB=90^0}\\\widehat{HBE}=\widehat{ABD}\end{matrix}\right.\)
=> \(\widehat{BEH}=\widehat{ADB}\)
Mà \(\widehat{BEH}=\widehat{AED}\) (2 góc dd)
Nên \(\widehat{ADB}=\widehat{AED}\)
=> đpcm

Câu 2. 1c. Doing => to do

2a. many => much

3b. less => fewer

4a. playing => is playing

5b. go always => always go

Câu 3.

1a. teenager

2c. orchestra

3d. realize

4b. hour

5c. future

Câu 4.

1. nearest

2. regularly

3. musicians

4. less

5. activities

Câu 5.

1. It takes me half an hour to get to work.

2. Is this the cheapest computer you have?

3. How much does this dictionary cost?

4. You don't have to finish the work today.

5. Tim's collection has over eight hundred stamps.

- Đ.m lần sau chép cái đề ra giúp cái -.-

\(1,BaO+2HCl\rightarrow BaCl_2+H_2O\\ 2,Na_2O+H_2SO_4\rightarrow Na_2SO_4+H_2O\\ 3,Cu+2H_2SO_{4\left(đ\right)}\rightarrow CuSO_4+2H_2O+SO_2\uparrow\\ 4,Fe_3O_4+2C\rightarrow3Fe+2CO_2\uparrow\\ 5,2KOH+CuCl_2\rightarrow2KCl+Cu\left(OH\right)_2\downarrow\\ 6,BaCl_2+CuSO_4\rightarrow BaSO_4\downarrow+CuCl_2\\ 7,3Ba\left(OH\right)_2+2FeCl_3\rightarrow3BaCl_2+2Fe\left(OH\right)_3\downarrow\\ 8,CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2\uparrow\\ 9,3Fe+2H_3PO_4\rightarrow Fe_3\left(PO_4\right)_2+3H_2\\ 10,Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

1. BaO + 2HCl → BaCl₂ + H₂O

2. Na₂O + H₂SO_{4 đặc} → Na₂SO₄ + H₂O

có lẽ họ bận hay ko lên thôi

They can play volleyball and so can we

They can play volleyball and we can too

Mr Tam won't come to the party tonight and neither will his wife

Mr Tam won't come to the party tonight and his wife won't either

My father didn't drink beer and neither did my uncle/ my uncle did either
She is learning English and so am I/ I am too
I'm not a doctor and neither are they / they aren't either