4 . tính :
( 1/4 + 35% + 0,65 + 75%) x ( \(1\frac{6}{9}\)+\(4\frac{8}{24}\))
Những câu hỏi liên quan
\(\left(\frac{1}{4}+35\%+0,65+75\%\right)X\left(1\frac{6}{3}+4\frac{8}{24}\right)\)
X là nhân
\(\left(\frac{1}{4}+35\%+0,65+75\%\right)x\)\(\left(1\frac{6}{3}+4\frac{8}{24}\right)\)
\(=\left(\frac{1}{4}+\frac{7}{20}+\frac{13}{20}+\frac{3}{4}\right)\)\(x\left(3+\frac{13}{3}\right)\)
\(=\left(\frac{5}{20}+\frac{7}{20}+\frac{13}{20}+\frac{15}{20}\right)\)\(x7\)
\(=2x7\)
\(=14\)
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(1/4 + 35% + 0,65 + 75%) x (1 6/9 + 4 8/24)
giúp tớ nhé Hữu Nghĩa mai tớ lộp rồi nhé bạn
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\times\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(0,25+0,35+0,65+0,75\right)\times\left(1+\dfrac{2}{3}+4+\dfrac{1}{3}\right)\)
\(=2\times6\)
\(=12\)
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\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\times\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{65}{100}+\dfrac{3}{4}\right)\times\left(\dfrac{15}{9}+\dfrac{13}{3}\right)\)
\(=\left(\dfrac{5}{20}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{15}{20}\right)\times6\)
\(=\left[\left(\dfrac{15}{20}+\dfrac{5}{20}\right)+\left(\dfrac{7}{20}+\dfrac{13}{20}\right)\right]\times6\)
\(=2\times6\)
\(=12\)
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[ 1/4 +35%+0,65%+75%]:[1 6/4+4 8/24]
[\(\dfrac{1}{4}\) + 35% + 0,65% + 75% ]: [ 1\(\dfrac{6}{4}\) + 4\(\dfrac{8}{24}\)]
= [25% + 35% + 0,65% + 75%] : [ \(\dfrac{10}{4}\) + \(\dfrac{104}{24}\)]
= [ (25% +75%) + (35% +0,65%)]:(\(\dfrac{60}{24}\) + \(\dfrac{104}{24}\))
= [ 100% + 35,65%]: \(\dfrac{41}{6}\)
= 135,65% : \(\dfrac{41}{6}\)
= \(\dfrac{13565}{10000}\) : \(\dfrac{41}{6}\)
= \(\dfrac{13565}{10000}\) \(\times\) \(\dfrac{6}{41}\)
= \(\dfrac{8139}{41000}\)
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1.Tính giá trị biểu thức:
\(A=\)\(\left[\frac{1}{4}+35\%+0,65+75\%\right]x\)\(\left[1\frac{6}{9}+4\frac{8}{24}\right]\)
2.So sánh:
\(B=\frac{19}{20}+\frac{29}{30}+\frac{41}{40}+\frac{55}{56}+\frac{71}{72}+\frac{89}{90}\) \(C=6\frac{2010}{2011}\)
\(\left(35\%+\frac{1}{4}+75\%+0,65\right)x105+\left(\frac{1}{2}+50\%\right)\)
\(\left(35\%+\frac{1}{4}+75\%+0,65\right)\cdot105+\left(\frac{1}{2}+50\%\right)\)
\(=\left(\frac{7}{20}+\frac{1}{4}+\frac{3}{4}+\frac{13}{20}\right)\cdot105+\left(\frac{1}{2}+\frac{1}{2}\right)\)
\(=2\cdot105+1\)
\(=211\)
\(=210x+1\)
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bài 1 : tính phân số:a) frac{5}{7}+frac{4}{9}?;frac{4}{5}-frac{2}{3}?;frac{9}{11}+frac{3}{8}?;frac{16}{25}-frac{2}{5}??b)5+frac{3}{5}?;10-frac{9}{16}?;frac{2}{3}-left(frac{1}{6}+frac{1}{8}right)?c)frac{5}{7}+frac{7}{6}?;frac{7}{12}+frac{17}{18}?;frac{9}{8}+frac{15}{32}?;4+frac{35}{45}?d)frac{11}{4}-frac{15}{16}?;frac{5}{6}-frac{5}{8}?;frac{196}{64}-2?;3-frac{13}{9}?e)frac{8}{5}+frac{7}{6}+frac{5}{9}-2?;3-frac{5}{6}-frac{4}{9}+frac{32}{24}?
Đọc tiếp
bài 1 : tính phân số:
a) \(\frac{5}{7}+\frac{4}{9}=?;\frac{4}{5}-\frac{2}{3}=?;\frac{9}{11}+\frac{3}{8}=?;\frac{16}{25}-\frac{2}{5}=?\)=?
b)\(5+\frac{3}{5}=?;10-\frac{9}{16}=?;\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=?\)
c)\(\frac{5}{7}+\frac{7}{6}=?;\frac{7}{12}+\frac{17}{18}=?;\frac{9}{8}+\frac{15}{32}=?;4+\frac{35}{45}=?\)
d)\(\frac{11}{4}-\frac{15}{16}=?;\frac{5}{6}-\frac{5}{8}=?;\frac{196}{64}-2=?;3-\frac{13}{9}=?\)
e)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2=?;3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}=?\)
a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)
\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)
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Xem thêm câu trả lời
a, tính:\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
b, tìm x biết:\(1\frac{1}{30}:(24\frac{1}{6}-24\frac{1}{5})-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=(-1\frac{1}{5}):(8\frac{1}{5}-8\frac{1}{3})\)
tính
a, (1/4 + 35% + 0,65+75% ): (15/9 + 104/24)
b, 1999 x 2001-1 / 1998 + 1999 x 2000
x7/5
ghi cả cách làm mình tick
a) =(1/4+7/20+13/20+3/4):(15/9+104/24)=1/3 b) =4000001,001
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(1/4 + 35% + 0, 65 + 75%) x ( 1 6/9 + 4 8/24)
nhanh lên nhé nhớ giải đầy đủ đấy
\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\cdot\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\\ =\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{3}{4}\right)\cdot\left(\dfrac{5}{3}+\dfrac{13}{3}\right)\\ =\left[\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{7}{20}+\dfrac{13}{20}\right)\right]\cdot\left(\dfrac{18}{3}\right)\\ =\left(\dfrac{4}{4}+\dfrac{20}{20}\right)\cdot6\\ =\left(1+1\right)\cdot6\\ =2\cdot6\\ =12\)
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\(\left(\dfrac{1}{4}+35\%+0,65+75\%\right)\left(1\dfrac{6}{9}+4\dfrac{8}{24}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{7}{20}+\dfrac{13}{20}+\dfrac{3}{4}\right)\left(\dfrac{5}{3}+\dfrac{13}{3}\right)\)
\(=\left\{\left[\dfrac{1}{4}+\dfrac{3}{4}\right]+\left[\dfrac{7}{20}+\dfrac{13}{20}\right]\right\}\left(\dfrac{5+13}{3}\right)\)
=\(\left(1+1\right).6=2.6=12\)
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