Bài 1:

a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)

b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)

Bài 2:

 \(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)

Bài 3:

\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)

1.

7/15:(1/2-9/10xX)-1/6=13/6

=>7/15:(1/2-9/10xX)=13/6+1/6

=>7/16:(1/2-9/10xX)=7/3

=>1/2-9/10xX=7/16:7/3

=>1/2-9/10xX=3/16

=>9/10xX=1/2-3/16

=>9/10xX=5/16

=>X=5/16:9/10

=>X=25/72

a. Tính đúng y = 40

b. Tính đúng  y = 4 2 3

1: Áp dụng tính chất của DTSBN, ta được:

\(\dfrac{x}{7}=\dfrac{y}{13}=\dfrac{x-y}{7-13}=\dfrac{42}{-6}=-7\)

=>x=-48; y=-91

2: x/y=3/4

=>4x=3y

=>4x-3y=0

mà 2x+y=10

nên x=3 và y=4

3: =>7x-3y=0 và x-y=-24

=>x=18 và y=42

4: =>7x-5y=0 và x+y=24

=>x=10 và y=14

a) \(y-6:2-\left(48-24.2:6-3\right)=0.\)

\(\Rightarrow y-3-\left(48-8-3\right)=0\)

\(\Rightarrow y-3-37=0\)

\(\Rightarrow y=0+37+3=40\)

Vậy y = 40

b) \(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)

\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)

\(\Rightarrow\frac{29}{3}-y=195:39=5\)

\(\Rightarrow y=\frac{29}{3}-5=\frac{14}{3}\)

Vậy y=\(\frac{14}{3}\)

a) y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0

y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0

y - 6 : 2 - ( 48 - 8 - 3 ) = 0

y - 6 : 2 - 37 = 0

y - 3 = 0 + 37

y - 3 = 37

y = 37 + 3

y = 40

b) ( 7 x 13 + 8 x 13 ) : (  \(9\frac{2}{3}\) - y ) = 39

( 15 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39

195 : ( \(9\frac{2}{3}\) - y ) = 39

\(9\frac{2}{3}\) - y = 195 : 39

\(9\frac{2}{3}-y=5\)

\(y=9\frac{2}{3}-5\)

\(y=\frac{14}{3}\)

 a,  y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0 

     y - 3 - 37 = 0 

     y - 3 = 0 + 37 

     y - 3 = 37 

     y = 37 + 3

     y = 40 

b,  ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39

     195 : ( \(\frac{29}{3}\)- y ) = 39 

     \(\frac{29}{3}\)- y = 195 : 39 

   \(\frac{29}{3}\)- y = 5

  y = \(\frac{29}{3}\)- 5 

y = \(\frac{14}{3}\)

áp dung tc cua day ti so bang nhau co

\(\frac{x}{2}=\frac{y}{3}=\frac{x+y}{2+3}=\frac{-15}{5}=-3\)

x=-6;y=-9

y b lam tuong tuu nhung thay cong bang tru 

y c

co \(\frac{x}{y}=\frac{7}{-9}\Rightarrow\frac{x}{7}=\frac{y}{-9}\Rightarrow\frac{2x}{14}=\frac{3y}{-27}\)

lam tuong tuu y a

d,

h cheo

7 ( x + 4 ) = 4 ( 7 + y )

7x + 28 = 4y + 28 

        7x = 4y

\(\Rightarrow\frac{x}{4}=\frac{y}{7}\)

ap dung tc cua day ti so bang nhau va lam tuong tuu y a

t i c k nha

a/b nhân 4 cộng 1/6 = 17/6 số phải tìm là bao nhiêu

Cậu cho nhiều quá

Mỗi bài mình làm một dạng thôi nhé!

1) \(\left(\frac{3}{2}-\frac{x}{y}\right)+\frac{5}{7}=\frac{11}{14}\)

\(\Rightarrow\frac{x}{y}=\frac{3}{2}-\left(\frac{11}{14}-\frac{5}{7}\right)=\frac{10}{7}\)

2) a) 

\(\frac{17}{9}+\frac{19}{13}+\frac{14}{6}+\frac{7}{13}+\frac{10}{6}+\frac{1}{9}\)

\(=\left(\frac{17}{9}+\frac{1}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)+\left(\frac{14}{6}+\frac{10}{6}\right)\)

\(=2+2+4\)

\(=8\)

3) a) 

\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{42}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}\)

\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}\)

\(A=\frac{1}{1}-\frac{1}{7}=\frac{6}{7}\)

4) a)

\(y.\frac{5}{6}=1+\frac{1}{2}\)

\(\Rightarrow y.\frac{5}{6}=\frac{3}{2}\)

\(\Rightarrow y=\frac{3}{2}.\frac{6}{5}=\frac{9}{5}\)

\(\text{ x . (x - 3) = 0}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}\)

vậy_______

1 ) 5 - ( 10 - x ) = 7

            10 - x   = 5 - 7

             10 - x  = - 2

                    x  = 10 - ( - 2 )

                     x = 12

Vậy x = 12

Bài 2: 

b: x=12; y=80