1/3<4/5<7/3<5/2

6/8<6/7<3/2<5/2

1/3; 4/5; 7/3; 5/2

5/2; 3/2; 6/7; 6/8

1/3, 4/5, 7/3, 5/2

6/8, 6/7, 3/2, 5/2

Lời giải:
a) $8^3:(-8)^{-5}=8^3:(-8^{-5})=-(8^3:8^{-5})$

$=-8^{3-(-5)}=-8^{13}$

b) $(\frac{-5}{16})^{12}:(\frac{5}{-16})^4$

$=(\frac{-5}{16})^{12}:(\frac{-5}{16})^4$

$=(\frac{-5}{16})^{12-4}=(\frac{-5}{16})^8=(\frac{5}{16})^8$

c) $(\frac{5}{3})^6:(\frac{5}{3})^4=(\frac{5}{3})^{6-4}=(\frac{5}{3})^2$

d)

$(\frac{9}{7})^9:(\frac{-9}{-7})^3=(\frac{9}{7})^9:(\frac{9}{7})^3$

$=(\frac{9}{7})^{9-3}=(\frac{9}{7})^4$

1. 

$(5^{1986}-5^{1985}):5^{1985}=5^{1985}(5-1):5^{1985}=5-1=4$

2.

\((7^{846}+7^{847}):7^{846}=7^{846}(1+7):7^{846}=1+7=8\)

3.

\((9^{2018}-3^{4036}):6^{2006}=[(3^2)^{2018}-3^{4036}]:6^{2006}\)

$=(3^{4036}-3^{4036}):6^{2006}=0:6^{2006}=0$

4.

$(7^{80}.8^{70}-56^{70}):56^{70}$

$=[7^{10}(7.8)^{70}-56^{70}]:56^{70}$

$=[7^{10}.56^{70}-56^{70}]:56^{70}$

$=56^{70}(7^{10}-1):56^{70}=7^{10}-1$

5.

$4^{4016}:(4^{4017}-4^{4016})=4^{4016}:[4^{4016}(4-1)]$

$=4^{4016}:4^{4016}:3=1:3=\frac{1}{3}$

6.

$(12^{206}.2^{207}-24^{206}):24^{206}$

$=(12^{206}.2^{206}.2-24^{206}):24^{206}$

$=[(12.2)^{206}.2-24^{206}]:24^{206}$

$=(24^{206}.2-24^{206}):24^{206}$

$=24^{206}(2-1):24^{206}=2-1=1$

7.

$(5^2-24)^{8946}+4^{30}:2^{60}=1^{8946}+(2^2)^{30}:2^{60}$

$=1+2^{60}:2^{60}=1+1=2$

8.

$(37.8^{1007}-7.2^{3021}):8^{1007}=[37.8^{1007}-7.(2^3)^{1007}]:8^{1007}$

$=[37.8^{1007}-7.8^{1007}]:8^{1007}$

$=8^{1007}(37-7):8^{1007}=37-7=30$

\(A=1-2+3-4+5-6+7-8+...+99-100\)

\(A=\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)

\(A=\left(-1\right).50\)

\(A=-50\)

\(B=1+3-5-7+9+11-...-397-399\)

\(B=1-2+2-2+2-...+2-2-399\)

\(B=1-399\)

\(B=-398\)

\(C=1-2-3+4+5-6-7+...+97-98-99+100\)

\(C=-1+1-1+1-...-1+1\)

\(C=0\)

\(D=2^{2024}-2^{2023}-...-1\)

\(D=2^{2024}-\left(2^0+2^1+2^2+...2^{2023}\right)\)

\(D=2^{2024}-\left(\dfrac{2^{2024}-1}{2-1}\right)\)

\(D=2^{2024}-\left(2^{2024}-1\right)\)

\(D=2^{2024}-2^{2024}+1\)

\(D=1\)

A = 1 - 2 + 3  - 4 + 5 - 6 + 7 - 8 +...+ 99 - 100

A = (1 - 2) + ( 3 - 4) + ( 5- 6) +....+(99 - 100)

Xét dãy số 1; 3; 5;...;99

Dãy số trên là dãy số cách đều có khoảng cách là: 3 - 1 = 2

Dãy số trên có số số hạng là: (99 - 1) : 2 + 1 = 50 (số)

Vậy tổng A có 50 nhóm, mỗi nhóm có giá trị là: 1- 2 = -1

A =  - 1\(\times\)50 = -50

b, 

B = 1 + 3 - 5 - 7 + 9 + 11-...- 397 - 399

B = ( 1 + 3 - 5 - 7) + ( 9 + 11 - 13 - 15) + ...+( 393 + 395 - 397 - 399)

B = -8 + (-8) +...+ (-8)

Xét dãy số 1; 9; ...;393

Dãy số trên là dãy số cách đều có khoảng cách là: 9-1 = 8

Dãy số trên có số số hạng là: ( 393 - 1): 8 + 1 = 50 (số hạng)

Tổng B có 50 nhóm mỗi nhóm có giá trị là -8

B = -8 \(\times\) 50 = - 400

c, 

C = 1 - 2 - 3 + 4 + 5 -  6 +...+ 97 - 98 - 99 +100

C = ( 1 - 2 - 3 + 4) + ( 5 - 6 - 7+ 8) +...+ ( 97 - 98 - 99 + 100)

C = 0 + 0 + 0 +...+0

C = 0

d,   D =           2²⁰²⁴ - 2²⁰²³- ... +2 - 1

    2D = 2²⁰⁰⁵- 2²⁰⁰⁴ + 2²⁰⁰³+...- 2

2D + D = 2²⁰⁰⁵ - 1

 3D      = 2²⁰⁰⁵ - 1

   D      = (2²⁰⁰⁵ - 1): 3

T=(a*2/3):5/6 a:8/15 với a=-4/5

I=3/4*a+4/9*a-1/4*a với a=12/5

P=a(b+1/5)-a*(6/5+b) với a= 2004 ;b=206

Q=1/19*a+3*b:5/7+9/4 với a=38;b=-10/7

V=3/2*(a+b+c)- 1/5*(a-b-c) với a=1/3;b=-5/6;c=3/4

giúp mình với

17+17+17=17x3=41

KHO THE

\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)

\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)

\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)

`#lv`

`-2/5+(-7/10)-9/6`

`=-2/5-7/10-9/6`

`=-4/10-7/10-9/6`

`=-11/10-3/2`

`=-11/10-15/10`

`=-26/10`

`=-13/5`

__

`1/2+(-2/5)-(-2/3)`

`=1/2-2/5+2/3`

`=5/10-4/10+2/3`

`=1/10+2/3`

`=3/30+20/30`

`=23/30`

__

`5/3-3/4+7/6`

`=20/12-9/12+14/12`

`=11/12+14/12`

`=25/12`

__

`-1/5+5/3-3/2`

`=-3/15+25/15-3/2`

`=22/15-3/2`

`=44/30-45/30`

`=-1/30`

__

`1/4-7/8+(-9/10)`

`=2/8-7/8-9/10`

`=-5/8-9/10`

`=-25/40-36/40`

`=-61/40`

__

`5/4+1/2+(-7/12)`

`=15/12+6/12-7/12`

`=21/12-7/12`

`=14/12`

`=7/6`

__

`-5/8-1/3+(-7/6)`

`=-5/8-1/3-7/6`

`=-15/24-8/24-28/24`

`=-52/24`

`=-13/6`

__

`-3/4-7/10+(-5/6)`

`=-3/4-7/10-5/6`

`=-45/60-42/60-50/60`

`=-137/60`

Bài làm

a, (-2/5) + (-7/10) - 9/6 =(-12/30) + (-21/30) - 45/30=(-33/30) - 45/30 = (-78/30)

b,1/2 + (-2/5) - (-2/3) = 15/30 + (-12/30) - (-20/30) = 3/30 - (-20/30) = 23/30

c,5/3 - 3/4 + 7/6 = 40/24 - 18/24 + 28/24 = 22/24 + 28/24 = 50/24 = 25/12

d, (-1/5) + 5/3 - 3/2 = (-6/30) + 50/30 - 45/30 = 44/30 - 45/30 = (-1/30)

e, 1/4 - 7/8 + (-9/10) = 10/40 - 35/40 - 36/40 = (-25/40) - 36/40 = (-61/40)

f, 5/4 +1/2 + (-7/12) = 15/12 + 6/12 - 7/12 = 21/12 - 7/12 = 14/12 = 7/6

g,(-5/8) -1/3 + (-7/6) = (-15/24) - 8/24 - 28/24 = (-23/24) - 28/24 = (-51/24) 

k,(-3/4) - 7/10 + (-5/6) = (-45/60) - 42/60 - 50/60 = (-87/60) - 50/60 = (-137/60)

chúc bn học tốt nha

sai thì mn góp ý giúp mk

2/3 + 7/1 = 2/3 + 7 = 2/3 + 21/3 = 23/3

25/48 + 11/24 = 25/48 + 22/48 = 47/48

5/7 + 3/8 = 40/56 + 21/56 = 61/56

15/24 + 12/6 = 5/8 + 2 = 5/8 + 16/8 = 21/8

5/6 + 4/3 = 5/6 + 8/6 = 13/6

3/8 + 7/12 = 9/24 + 14/24 = 23/24

= 23/3

= 47/48

=61/56

=21/8

=13/6

= 23/24

Cảm ơn mn nhìu nhaaaaaa

a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)

\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)

\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)

\(\Rightarrow x=\dfrac{-5}{12}\)

b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)

\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{2}{5}\)

c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)

\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-77}{120}\)

d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)

\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{-7}{20}\)

e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)

\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-59}{105}\)

g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-13}{12}\)