x:0,25 + X x0,25=3,4

(0,25+0,25) :x=3,4

0,5:x=3,4

x=3,4:0,5

x=6,8

a) \(x:0,25+x.0,25=3,4\)

\(\Leftrightarrow x:\dfrac{1}{4}+\dfrac{1}{4}x=3,4\)

\(\Leftrightarrow4x+\dfrac{1}{4}x=3,4\Leftrightarrow\dfrac{17}{4}x=3,4\Leftrightarrow x=3,4:\dfrac{17}{4}\)

\(\Leftrightarrow x=0,8\)

b) \(0,7:x+0,5:x=0,75\)

<=> \(\left(0,7+0.5\right):x=0,75\)

<=> \(1,2:x=0,75\)

<=> \(x=1,6\)

\(x:0,5+x\times0,5=0,75\)'

\(\Rightarrow x:\frac{5}{10}+x\times\frac{5}{10}=\frac{3}{4}\)

\(\Rightarrow\frac{10x}{5}+\frac{5x}{10}=\frac{3}{4}\)

\(\Rightarrow2x+\frac{5x}{10}=\frac{3}{4}\)

\(\Rightarrow\frac{40x}{20}+\frac{10x}{20}=\frac{15}{20}\)

\(\Rightarrow50x=15\Rightarrow x=0,3\)

x/0.5+x*0.5=0.75

x*2+x*0.5=0.75

x*2.5=0.75

x=0.75/2.5

x=0.3

x/0,5+x*0,5=0,75

x*2+x*0,5=0,75

x*(2+0.5)=0,75

x*2,5=0.75

x=0,75/2,5

x=0,3

0,3

Ai tick mình đi mình cần 10 cái!!!!!!

a) \(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

 0,5 x + 0,6 ( x - 2 ) = 3

0,5 x + 0.6 x - 1,2 = 3

1,1 x = 4,2

x = \(\frac{42}{11}\)

Kết luận: 

b) \(\frac{1}{3}x-0,5x=0,75\)

\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(-\frac{1}{6}x=\frac{3}{4}\)

\(x=-\frac{9}{2}\)

Kết luận: 

c) \(\frac{3}{-2}x-0,5x=75\%\)

-1,5x - 0,5x = 0,75 

-2x = 0,75 

x = -0,375

Kết luận: 

d) \(-\frac{2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

-0,4 x + 0,25 = 0,75 - 0,75 x 

-0,4 x + 0,75 x = 0,75 - 0,25

0,35 x = 0,5 

x = \(\frac{10}{7}\)

Kết luận: 

\(a,\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

\(\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)

\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)

\(\frac{11}{10}x-\frac{6}{5}=3\)

\(\frac{11}{10}x=\frac{21}{5}\)

\(x=\frac{42}{11}\)

\(b,\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(\left(\frac{1}{3}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(\frac{-1}{6}x=\frac{3}{4}\)

\(x=\frac{-9}{2}\)

\(c,\frac{3}{-2}x-\frac{1}{2}x=75\%\)

\(\left(\frac{3}{-2}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(-2x=\frac{3}{4}\)

\(x=\frac{-3}{8}\)

\(\frac{-2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

\(\frac{-2}{5}x+\frac{3}{4}x=\frac{3}{4}-\frac{1}{4}\)

\(\left(\frac{-2}{5}+\frac{3}{4}\right)x=\frac{1}{2}\)

\(\frac{7}{20}x=\frac{1}{2}\)

\(x=\frac{10}{7}\)

a: \(\left(\dfrac{3}{4}x+2\dfrac{1}{2}\right)\cdot\dfrac{-2}{3}=\dfrac{1}{8}\)

=>\(\left(\dfrac{3}{4}x+\dfrac{5}{2}\right)=\dfrac{1}{8}:\dfrac{-2}{3}=\dfrac{-3}{16}\)

=>\(\dfrac{3}{4}x=-\dfrac{3}{16}-\dfrac{5}{2}=-\dfrac{3}{16}-\dfrac{40}{16}=-\dfrac{43}{16}\)

=>\(x=-\dfrac{43}{16}:\dfrac{3}{4}=\dfrac{-43}{16}\cdot\dfrac{4}{3}=\dfrac{-43}{12}\)

b: \(\dfrac{1}{3}\cdot x-0,5x=0,75\)

=>\(x\left(\dfrac{1}{3}-\dfrac{1}{2}\right)=0,75\)

=>\(x\cdot\dfrac{-1}{6}=0,75\)

=>\(x=-0,75\cdot6=-4,5\)

  0,75 + 1,5 \(\times\) 97,8 \(\times\) 0,5 + 0,25 \(\times\) 3 \(\times\) 1,2

= 0,75 \(\times\) 1 + (1,5 \(\times\) 0,5)\(\times\) 97,8 + (0,25 \(\times\)3) \(\times\) 1,2

= 0,75 \(\times\) 1 + 0,75 \(\times\) 97,8 + 0,75 \(\times\) 1,2

= 0,75 \(\times\) ( 1 + 97,8 + 1,2)

= 0,75 \(\times\) [1 + ( 97,8 + 1,2)]

= 0,75 \(\times\) [1 + 99]

= 0,75 \(\times\) 100

= 75

\(\frac{1}{3}x-0,5x=0,75\)

\(\Rightarrow-\frac{1}{6}x=0,75\)

\(\Rightarrow x=-\frac{9}{2}\)

\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(\left(\frac{1}{3}+\frac{1}{2}\right)x=\frac{3}{4}\)

\(\frac{5}{6}x=\frac{3}{4}\)

\(x=\frac{3}{4}\div\frac{5}{6}\)

\(x=\frac{3}{4}\cdot\frac{6}{5}=\frac{9}{10}\)

                           \(#Cothanhkhe\)

\(\frac{1}{3}.x-0,5.x=0,75\)

\(\frac{1}{3}.x-\frac{1}{2}.x=\frac{3}{4}\)

\(x.\left(\frac{1}{3}-\frac{1}{2}\right)=\frac{3}{4}\)

\(x.\left(\frac{2}{6}-\frac{3}{6}\right)=\frac{3}{4}\)

\(x.\frac{-1}{6}=\frac{3}{4}\)

\(x=\frac{3}{4}:\frac{-1}{6}\)

\(x=\frac{-9}{2}\)

100000