a.\(\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}\)

\(\dfrac{5}{3}x-2\dfrac{1}{3}=\dfrac{5}{6}\)

\(\dfrac{5}{3}x=\dfrac{5}{6}+2\dfrac{1}{3}\)

\(\dfrac{5}{3}x=\dfrac{19}{6}\)

\(x=\dfrac{19}{5}:\dfrac{5}{3}\)

\(x=\dfrac{19}{10}\)

b. \(2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}\)

\(2\dfrac{1}{6}:x+\dfrac{5}{8}=\dfrac{47}{63}\)

\(2\dfrac{1}{6}:x=\dfrac{47}{63}-\dfrac{5}{8}\)

\(2\dfrac{1}{6}:x=\dfrac{61}{504}\)

\(x=2\dfrac{1}{6}:\dfrac{61}{504}\)

\(x=\dfrac{1092}{61}\)

a, \(\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}\)

\(\Rightarrow\dfrac{5}{3}x=-\dfrac{3}{2}-\dfrac{2}{3}+2\dfrac{1}{3}=-\dfrac{3}{2}+2=\dfrac{1}{2}\)

\(\Rightarrow x=\dfrac{1}{2}:\dfrac{5}{3}=\dfrac{3}{10}\)

b, \(2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}\)

\(\Rightarrow\dfrac{13}{6}:x=-\dfrac{7}{15}:\dfrac{21}{5}+\dfrac{6}{7}-\dfrac{5}{8}\)

\(\Rightarrow\dfrac{13}{6}:x=\dfrac{61}{504}\Rightarrow x=\dfrac{1092}{61}\)

c, \(\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%\)

\(\Rightarrow\dfrac{5}{6}x-0,3=\dfrac{1}{4}.\dfrac{7}{3}\)

\(\Rightarrow\dfrac{5}{6}x=\dfrac{7}{12}+0,3=\dfrac{53}{60}\)

\(\Rightarrow x=\dfrac{53}{60}:\dfrac{5}{6}=1,06\)

d, \(\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x\)

\(\Rightarrow\dfrac{4}{5}x+\dfrac{2}{3}x=\dfrac{4}{7}-1,5\)

\(\Rightarrow\dfrac{22}{15}x=-\dfrac{13}{14}\Rightarrow x=-\dfrac{195}{308}\)

Chúc bạn học tốt!!!

b) \(\dfrac{4}{5}-\dfrac{3}{4}:x=0,3\)

\(\Rightarrow0,8-0,75:x=0,3\)

\(\Rightarrow0,75:x=0,5\)

\(\Rightarrow x=1,5\)

c) \(\dfrac{-3}{2}-\dfrac{1}{4}x=1\dfrac{1}{3}-0,2x\)

\(\Rightarrow\dfrac{-3}{2}-\dfrac{4}{3}=\dfrac{1}{4}x-\dfrac{1}{5}x\)

\(\Rightarrow x=\dfrac{-17}{6}\cdot20\)

\(\Rightarrow x=\dfrac{-170}{3}\)

d) \(\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|:\dfrac{2}{3}-0,5=1\dfrac{1}{2}\)

\(\Rightarrow\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|:\dfrac{2}{3}=\dfrac{3}{2}+\dfrac{1}{2}\)

.\(\Rightarrow\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|=\dfrac{4}{3}\)

\(\Rightarrow\left[{}\begin{matrix}\dfrac{3}{5}x+\dfrac{4}{3}=\dfrac{4}{3}\Rightarrow x=0\\\dfrac{3}{5}x+\dfrac{4}{3}=-\dfrac{4}{3}\Rightarrow x=\dfrac{-40}{9}\end{matrix}\right.\)

Giải:

a) \(\left(\dfrac{1}{3}.x\right):\dfrac{2}{3}=1\dfrac{3}{4}:\dfrac{2}{5}\)

\(\Leftrightarrow\left(\dfrac{1}{3}x\right):\dfrac{2}{3}=\dfrac{7}{4}:\dfrac{2}{5}\)

\(\Leftrightarrow\left(\dfrac{1}{3}x\right):\dfrac{2}{3}=\dfrac{35}{8}\)

\(\Leftrightarrow\dfrac{1}{3}x=\dfrac{35}{8}.\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{1}{3}x=\dfrac{35}{12}\)

\(\Leftrightarrow x=\dfrac{35}{12}:\dfrac{1}{3}\)

\(\Leftrightarrow x=\dfrac{35}{4}\)

Vậy \(x=\dfrac{35}{4}\).

b) \(4,5:0,3=2,25\left(0,1.x\right)\)

\(\Leftrightarrow15=2,25\left(0,1.x\right)\)

\(\Leftrightarrow2,25\left(0,1.x\right)=15\)

\(\Leftrightarrow0,1.x=\dfrac{15}{2,25}\)

\(\Leftrightarrow0,1.x=\dfrac{20}{3}\)

\(\Leftrightarrow x=\dfrac{20}{3}:0,1\)

\(\Leftrightarrow x=\dfrac{200}{3}\)

Vậy \(x=\dfrac{200}{3}\).

c) \(8:\left(\dfrac{1}{4}.x\right)=2:0,02\)

\(\Leftrightarrow8:\left(\dfrac{1}{4}.x\right)=100\)

\(\Leftrightarrow\dfrac{1}{4}.x=\dfrac{2}{25}\)

\(\Leftrightarrow x=\dfrac{2}{25}:\dfrac{1}{4}\)

\(\Leftrightarrow x=\dfrac{8}{25}\)

Vậy \(x=\dfrac{8}{25}\).

d) \(3:2\dfrac{1}{4}=\dfrac{3}{4}:\left(6.x\right)\)

\(\Leftrightarrow3:\dfrac{9}{4}=\dfrac{3}{4}:\left(6.x\right)\)

\(\Leftrightarrow\dfrac{4}{3}=\dfrac{3}{4}:\left(6.x\right)\)

\(\Leftrightarrow\dfrac{4}{3}:\left(6.x\right)=\dfrac{3}{4}\)

\(\Leftrightarrow6.x=\dfrac{4}{3}:\dfrac{3}{4}\)

\(\Leftrightarrow6.x=\dfrac{16}{9}\)

\(\Leftrightarrow x=\dfrac{16}{9}:6\)

\(\Leftrightarrow x=\dfrac{8}{27}\)

Vậy \(x=\dfrac{8}{27}\).

Chúc bạn học tốt!!!

\(A=88-80-\dfrac{8.16}{1.02}\)

=8-8=0

=>A/B=0

d, 32%-0,25:x=-3/2/5

0,32-0,25:x=-3,4

-0,25:x=-3,4-0,32

-0,25:x=-3,72

x=-0,25:-3,72

x=25/372

7/8+4/1/2:x=-13/40

0,875+4,5:x=-0,325

4,5:x=-0,325-0,875

4,5:x=-1,2

x=4,5:-1,2

x=-3,75

b, 0,25.x-27/8.x=3/4

x.(0,25-3,375)=0,75

x.(-3,125)=0,75

x=0,75:(-3,125)

x=-0,24

\(1\dfrac{2}{3}:\dfrac{x}{4}=6:0,3\)

\(\dfrac{5}{3}:\dfrac{x}{4}=20\)

\(\dfrac{x}{4}=\dfrac{5}{3}:20\)

\(\dfrac{x}{4}=\dfrac{1}{12}\)

\(x=\dfrac{1}{3}\)

1/

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\dfrac{x}{5}=\dfrac{y}{6}=\dfrac{x-y}{5-6}=\dfrac{36}{-1}=-36\)

\(\Rightarrow\left\{{}\begin{matrix}x=-36\cdot5=-180\\y=-36\cdot6=-216\\z=-36\cdot4=-144\end{matrix}\right.\)

2/

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{y+z}{3+4}=\dfrac{28}{7}=4\)

\(\Rightarrow\left\{{}\begin{matrix}x=4\cdot7=28\\y=4\cdot3=12\\z=4\cdot4=16\end{matrix}\right.\)

3/

\(\dfrac{x}{1,2}=\dfrac{y}{1,3}\Leftrightarrow\dfrac{2x}{2,4}=\dfrac{y}{1,3}\)

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\dfrac{2x}{2,4}=\dfrac{y}{1,3}=\dfrac{2x-y}{2,4-1,3}=\dfrac{5,5}{1,1}=5\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5\cdot2,4}{2}=6\\y=5\cdot1,3=6,5\\z=5\cdot1,4=7\end{matrix}\right.\)

4/

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\dfrac{x}{0,5}=\dfrac{y}{0,3}=\dfrac{x-y}{0,5-0,3}=\dfrac{1}{0,2}=5\)

\(\Rightarrow\left\{{}\begin{matrix}x=5\cdot0,5=2,5\\y=5\cdot0,3=1,5\\z=5\cdot0,2=1\end{matrix}\right.\)

5/

\(z=\dfrac{x}{0,3}\Leftrightarrow z=\dfrac{3x}{0,9}\)

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(z=\dfrac{3x}{0,9}=\dfrac{z-3x}{1-0,9}=\dfrac{1}{0,1}=10\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{10\cdot0,9}{3}=3\\y=10\cdot0,7=7\\z=10\end{matrix}\right.\)

1. Tính hợp lí

a) \(0,7+\dfrac{-7}{19}-\left(-0,3\right)\)

\(=\dfrac{7}{10}+\dfrac{-7}{19}+\dfrac{3}{10}\)

\(=\left(\dfrac{7}{10}+\dfrac{3}{10}\right)+\dfrac{-7}{19}\)

\(=1+\dfrac{-7}{19}\)

\(=\dfrac{12}{19}\)

b) \(\dfrac{5}{3}.\left(-2,5\right):\dfrac{5}{6}\)

\(=\dfrac{5}{3}.\dfrac{-5}{2}.\dfrac{6}{5}\)

\(=\left(\dfrac{5}{3}.\dfrac{6}{5}\right).\dfrac{-5}{2}\)

\(=2.\dfrac{-5}{2}\)

\(=-5\)

c) \(0,6.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)

\(=\dfrac{3}{5}.\dfrac{-5}{17}-\dfrac{3}{5}.\dfrac{12}{17}\)

\(=\dfrac{3}{5}.\left(\dfrac{-5}{17}-\dfrac{12}{17}\right)\)

\(=\dfrac{3}{5}.-1\)

\(=\dfrac{-3}{5}\)

d) \(\dfrac{7}{4}.\dfrac{5}{2}-\dfrac{7}{4}.\dfrac{3}{2}\)

\(=\dfrac{7}{4}.\left(\dfrac{5}{2}-\dfrac{3}{2}\right)\)

\(=\dfrac{7}{4}.1\)

\(=\dfrac{7}{4}\)

Chúc bạn học tốt

a) 0,7+−719−(−0,3)0,7+19−7​−(−0,3)

=710+−719+310=107​+19−7​+103​

=(710+310)+−719=(107​+103​)+19−7​

=1+−719=1+19−7​

=1219=1912​

b) 53.(−2,5):5635​.(−2,5):65​

=53.−52.65=35​.2−5​.56​

=(53.65).−52=(35​.56​).2−5​

=2.−52=2.2−5​

$=-5$

c) 0,6.−517−35.12170,6.17−5​−53​.1712​

=35.−517−35.1217=53​.17−5​−53​.1712​

=35.(−517−1217)=53​.(17−5​−1712​)

=35.−1=53​.−1

=−35=5−3​

d) 74.52−74.3247​.25​−47​.23​

=74.(52−32)=47​.(25​−23​)

=74.1=47​.1

=74=47​

mình giúp rùi đó nhớ tick mình nha

1: =>1/3:x=3/5-2/3=9/15-10/15=-1/15

=>x=-1/3:1/15=5

2: \(\Leftrightarrow x\cdot\dfrac{2}{3}-3=\dfrac{2}{5}\cdot\left(-10\right)=-4\)

=>x*2/3=-1

=>x=-3/2

3: \(\Leftrightarrow\dfrac{8}{3}:x=\dfrac{25}{12}:\dfrac{-3}{50}=\dfrac{25}{12}\cdot\dfrac{-50}{3}\)

hay x=-48/625

9: =>x=-2*3/1,5=-4

8: =>2/3:x=5/2:-3/10=5/2*(-10)/3=-50/6=-25/3

=>x=-2/3:25/3=-2/3*3/25=-2/25