\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
Những câu hỏi liên quan
\(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)
\(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)
\(\frac{3x}{7}+1=\frac{-1}{28}\times\left(-4\right)\)
\(\frac{3x}{7}+1=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
\(3x=\frac{-6}{7}\times7\)
\(3x=-6\)
\(x=-2\)
Vậy x = -2
tớ ko bít đúng hay sai đâu nha
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\(\Leftrightarrow\)\(-\frac{1}{28}\cdot\left(-4\right)\)=\(\frac{3x}{7}+1\)
\(\Leftrightarrow\frac{1}{7}=\frac{3x}{7}+1\)
\(\Leftrightarrow\frac{1}{7}-1=3x:7\)
\(\Leftrightarrow3x:7=-\frac{6}{7}\)
\(\Leftrightarrow3x=\frac{-6}{7}.7\)
\(\Leftrightarrow x=-6:3\)
\(\Leftrightarrow x=-2\)
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Tìm x :\(\left(\frac{3x}{7}+1\right):\left(-4\right)=-\frac{1}{28}\)
\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
\(\Leftrightarrow\frac{3x+7}{7}.\frac{1}{-4}=\frac{-1}{28}\)
\(\Leftrightarrow-\frac{3x+7}{28}=\frac{-1}{28}\)
\(\Leftrightarrow-\left(3x+7\right)=-1\)
\(\Leftrightarrow3x+7=1\)\(\Leftrightarrow3x=-6\)
\(\Leftrightarrow x=-2\)
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\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
Giúp mik với
\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
\(\Leftrightarrow\frac{3x}{7}+1=\frac{-1}{28}.\left(-4\right)\)
\(\Leftrightarrow\frac{3x}{7}+1=\frac{1}{7}\)
\(\Leftrightarrow\frac{3x}{7}=\frac{-6}{7}\)
\(\Leftrightarrow3x=-6\)
\(\Leftrightarrow x=-2\)
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
ghi sai để nên mik ko giải dc
\(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(2-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=-\frac{1}{20}\)
Tìm x biết:\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
tìm x: \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
Loan còn lượt cho đúng cho mình không chứ mấy bn kia chắc ko cho đúng đâu?
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(3x/7+1):(-4)=-1/28
3x/7+1=-1/28x(-4)
3x/7+1=1/7
3x/7=1/7-1=-6/7
3x=-6
x=-6:3=-2
Vậy x=-2
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Tìm x: \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}+\frac{1}{x-28}=\frac{-1}{20}\)