\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
\(\left(\frac{3x}{7}+1\right)=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
=> 3x = -6
=> x = -6 : 3
=> x = -2
Vậy x = -2
\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
\(\left(\frac{3x}{7}+1\right)=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1=\frac{-6}{7}\)
\(3x=-6\)
\(=>x=\left(-6\right):3=-2\)
\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
\(\Rightarrow\left(\frac{3x+7}{7}\right)=\frac{1}{7}\)
=> 3x+7=1
=>3x=-6
=>x=-2